`2.3^x+1=10.3^12+8.3^12`
2.3x=10.312+8.312
2.3x=10.312+8.312
=>2.3x=18.312
=>2.3x=2.32.312
=>3x=314
=>x=14
2.3x =10.312+8.312
2.3x= 312.(10+8)
2.3x=312. 18
2.3x=312 . 32.2
2.3x=314.2
x=14
tìm x
2.3x = 10.312 + 8.312
2 . 3x = 10 . 312 + 8 . 312
2 . 3x = ( 10 + 8 ) . 312
2 . 3x = 18 . 312
3x = 18 . 312 : 2
3x = 312 . 9
3x = 312 . 32
3x = 314
=>x = 14
\(\text{( đó là cách thuận tiện, lấy 18 : 2 = 9 cho thuận tiện nha )}\)
2.3\(^x\)=10.3\(^{12}\)+8.3\(^{12}\)
2.3\(^x\)=3\(^{12}\).(10+8)
2.3\(^x\)=18 .3\(^{12}\)=2.3\(^2\).3\(^{12}\)=2.3\(^{14}\)
vậy x=14
Tìm x
a)\(5^{\left(x-2\right).\left(x+3\right)}=1\)
b)\(\left(7-x\right)^{x+1}-\left(x-7\right)^{x+11}\ne0\)
c)\(x.\left(6-x\right)^{2003}=\left(6-x\right)^{2003}\)
d)\(2.3^x=10.3^{12}+8.3^{12}\)
e)\(5^x+5^{x+2}=650\)
a)5(x-2)(x+3)=1
=>5(x-2)(x+3)=50
=>(x-2)(x+3)=0
=>x-2=0=>x=2.
Và x+3=0=>x=-3.
Vậy x=2 và x=-3.
b)Câu này mik ko làm dc.
c)x.(6-x)2003=(6-x)2003
=>x=(6-x)2003:(6-x)2003
=>x=1.
Vậy x=1.
d)2.3x=10.312+8.312
=>2.3x=2.
2.3^x =10.3^12 +8.27^4
tìm x 2.3^x=10.3^12+8.27^4
\(2.3^x=10\cdot3^{12}+8.27^4\)
\(10.3^{12}+8.27^4=10.3^{12}+8.3^{12}\)
\(10.3^{12}+8.3^{12}=3^{12}\cdot\left(10+8\right)=3^{12}\cdot18=3^{12}\cdot2\cdot3^2=3^{14}\cdot2\)
=>x = 14
tìm x
2.3^x = 10.3^12+8.27^4
<=>2.3x=9565938 tính ra số hơi to ^^
=>3x2=2.4782696 ( 2 vế rút gọn 2 )
=>3x=4782969
=>x=14
2.3 mũ x =10.3 mũ 12 + 8.27 mũ 4
2.3x = 10.312 + 8.274
=> 2.3x = 10.312 + 23 . (33)4
=> 2.3x = 10.312 + 8.312
=> 2.3x = (10 + 8).312
=> 2.3x = 18.312
=> 2.3x = 2.32 . 312
=> 2.3x = 2.314
=> x = 14
\(2.3^x=10.3^{12}+8.27^4\)
\(\Leftrightarrow2.3^x=2.5.3^{12}+2^3.\left(3^3\right)^4\)
\(\Leftrightarrow2.3^x=2.5.3^{12}+2^3.3^{12}\)
\(\Leftrightarrow2.3^x=2.3^{12}\left(5+2^2\right)\)
\(\Leftrightarrow2.3^x=2.3^{12}.9\)
\(\Leftrightarrow2.3^x=2.3^{12}.3^2\)
\(\Leftrightarrow2.3^x=2.3^{14}\)
\(\Leftrightarrow x=14\)
Vậy x=14
Hok Tốt !!!!!!!!!!!!!!!!!!!!!!!
\(2\cdot3^x=10\cdot3^{12}+8\cdot27^4\)
\(2\cdot3^x=2\cdot5\cdot3^{12}+2^3\cdot\left(3^3\right)^4\)
\(2\cdot3^x=2\cdot5\cdot3^{12}+2^3\cdot3^{12}\)
\(2\cdot3^x=2\cdot3^{12}\left(5+2^2\right)\)
\(3^x=3^{12}\left(5+4\right)\)
\(3^x=3^{12}\cdot9\)
\(3^x=3^{12}\cdot3^2\)
\(3^x=3^{14}\)
x = 14
2.3 mũ x = 10.3 mũ 12 + 8.27 mũ 4
2.3x = 10.312 + 8.274
=> 2.3x = 10.312 + 8.(33)4
=> 2.3x = 10.312 + 8.312
=> 2.3x = (10 + 8).312
=> 2.3x = 18.312
=> 3x = 18 : 2.312
=> 3x = 9.312
=> 3x = 32.312
=> 3x = 314
=> x = 14
vậy_
a) x^10 = 1^x
b) 2.3^x =10.3^12+8.27^4
c) x^10=x
a) x^10 = 1^x
=> x=0;1
b) 2.3^x =10.3^12+8.27^4
=> 2.3^x=9565938
=> 3^x=4782969
=> x=3^14
=> x=14
c) x^10=x
=> x=0 ;1