3A=1.2.3+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+5.6.(7-4)+6.7.(8-5)+7.8.(9-6)+8.9.(10-7)+9.10.(11-8)

=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+5.6.7-4.5.6+6.7.8-5.6.7+7.8.9-6.7.8+8.9.10-7.8.9+9.10.11-8.9.10

=9.10.11

=> A=9.10.11:3

=3.10.11

=330

3A= 3.(1.2 + 2.3 + 3.4 + 4.5 + 5.6 + 6.7 + 7.8 + 8.9 + 9.10)
= 1.2.(3 - 0) + 2.3.(4 - 1) + 3.4.(5 - 2) + 4.5.(6 - 3) + 5.6.(7 - 4) + 6.7.(8 - 5) + 7.8.(9 - 6) + 8.9.(10 - 7) + 9.10.(11 - 8)
= 1.2.3 - 1.2.3 + 2.3.4 - 2.3.4 + 3.4.5 - … + 8.9.10 - 8.9.10 + 9.10.11
= 9.10.11 = 990.
A= 990/3 = 330

\(A=1.2+2.3+3.4+4.5+5.6+6.7+7.8+8.9+9.10\)

\(A=2.\left(1+3\right)+4.\left(3+5\right)+6.\left(5+7\right)+8.\left(7+9\right)+9.10\)

\(A=8+32+72+128+90\)

\(A=330\)

A=1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9

A=1/3-1/9

A=2/9

các câu 2;3 còn lại giống câu 1 bạn nhé

bạn thay số vào rồi làm tương tự

A=1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9

A=1/3-1/9

A=2/9.

\(A=\frac{5}{2.5}+\frac{5}{5.8}+\frac{5}{8.11}+...+\frac{5}{98.101}\)

\(=\frac{5}{2}-\frac{5}{5}+\frac{5}{5}-\frac{5}{8}+....+\frac{5}{98}-\frac{5}{101}\)

\(=\frac{5}{2}-\frac{5}{101}=\frac{495}{202}\)

\(\frac{5}{2\times5}+\frac{5}{5\times8}+\frac{5}{8\times11}+...+\frac{5}{98\times101}\)

\(=\frac{5}{3}\times\left(\frac{3}{2\times5}+\frac{3}{5\times8}+\frac{3}{8\times11}+...+\frac{3}{98\times101}\right)\)

\(=\frac{5}{3}\times\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{98}-\frac{1}{101}\right)\)

\(=\frac{5}{3}\times\left(\frac{1}{2}-\frac{1}{101}\right)\)

\(=\frac{5}{3}\times\frac{99}{202}=\frac{165}{202}\)

3x/2.5 + 3x/5.8 + 3x/8.11 + 3x/11.14 = 1/21

=> x . ( 3/2.5 + 3/5.8 + 3/8.11 + 3/11.14 ) = 1/21

=> x . ( 1/2.5 + 1/5.8 + 1/8.11 + 1/11.14 ) = 1/21

x . ( 1/2 - 1/5 + 1/5 - 1/8 + 1/8 - 1/11 + 1/11 - 1/14 ) = 1/21

x . ( 1/2 - 1/14 ) = 1/21

x . 3/7 = 1/21 

x = 1/21 : 3/7

=> x = 1/9

\(\frac{3x}{2\cdot5}+\frac{3x}{5\cdot8}+\frac{3x}{8\cdot11}+\frac{3x}{11\cdot14}=\frac{1}{21}\)

<=> \(x\left(\frac{3}{2\cdot5}+\frac{3}{5\cdot8}+\frac{3}{8\cdot11}+\frac{3}{11\cdot14}\right)=\frac{1}{21}\)

<=> \(x\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}\right)=\frac{1}{21}\)

<=> \(x\left(\frac{1}{2}-\frac{1}{14}\right)=\frac{1}{21}\)

<=> \(x\cdot\frac{3}{7}=\frac{1}{21}\)

<=> \(x=\frac{1}{9}\)

= 1/3.(1/2-1/5)+1/3.(1/5-1/8)+....+1/3.(1/92-1/95)+1/3.(1/95-1/98)

=1/3.(1/2-1/5+1/5-1/8+....+1/92-1/95+1/95-1/98)

=1/3.(1/2-1/98)

=1/3.24/49

=8/49

Phân tích: 1/2.5 = 1/2 - 1/5

1/5.8 = 1/5 - 1/8

1/8.11 = 1/8 - 1/11

...

1/92.95 = 1/92 - 1/95

1/95.98 = 1/95 - 1/98

Ta có: 1/2 - 1/5 + 1/5 - 1/8 + 1/8 - 1/11 +...+ 1/92 - 1/95 + 1/95 - 1/98

3 = 3/2.5 + 3/5.8 + 3/8.11 + ...+ 3/92.95 + 3/95.98

3 =  1 - 1/2 + 1/2 - 1/5 + 1/5 - 1/8 + 1/8 - 1/11 +...+ 1/92 - 1/95 + 1/95 - 1/98

= 1 - 1/98

= 97/98 : 3 = 97/98 x 1/3 = (tự tính)

1/2.5+...+1/95.98

=1/2-1/5+1/5-1/8+....1/95+1/98

=1/2-1/98

=24/49

K NHA!!!

Sai đề => Sửa: \(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{17.20}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{20}\)

\(\Rightarrow\frac{9}{20}\)

nói j chứ trả lời sao đc

dễ ẹt tí nữa làm cho

`Answer:`

\(A=1.\left(-2\right).3.\left(-4\right).5.\left(-6\right).7.\left(-8\right).9.\left(-10\right)\)

\(=-\left(2.3.4.5.6.7.8.9.10\right)\)

\(=-2[\left(2.3.4\right).\left(5.8.9\right).\left(6.7.10\right)]\)

\(=-\left(24.360.420\right)\)

\(=-3628800\)