\(7^{x+2}+2.7^{x-1}=\frac{345}{7}\)
7 mũ x+2+2.7 mũ x-1=345
tìm x biết: 72+x + 2.7x-1 = 345
\(\Leftrightarrow7^x\cdot49+2\cdot7^x\cdot\dfrac{1}{7}=345\)
\(\Leftrightarrow7^x=7\)
=>x=1
Tìm X :
\(\frac{1}{2}.2^x+2^{x+2}=2^8+2^5\)
\(9^x:3^x=3^7\)
\(7^{x+2}+2.7^{x-1}=345\)
giúp mình nhé mình tick cho
\(\frac{1}{2}\cdot2^x+2^x\cdot2^2=2^8+2^5\)
\(2^x\left(\frac{1}{2}+4\right)=2^8+2^5\)
\(2^x\cdot\frac{9}{2}=288\)
\(2^x=64\)
\(2^x=2^6\)
\(x=6\)
\(9^x:3^x=3^7\)
\(3^{2x}:3^x=3^7\)
\(3^x=3^7\)
\(x=7\)
\(7^{x+2}+2\cdot7^{x-1}=345\)
\(7^x\cdot7^2+2\cdot7^x:7=345\)
\(7^x\left(7^2+\frac{2}{7}\right)=345\)
\(7^x\cdot\frac{345}{7}=345\)
\(7^x=7\)
\(x=1\)
a) 1/2.2^x + 2^x+2 = 256 + 32
1/2.2^x + 2^2.2^x=288
2^x(1/2+4)= 288
2^x.4,5=288
2^x= 288:4,5
2^x=64=2^6
x=6
2.3x+3x-1=7.(32+2.62)
7x+22.7x-1=345
2.3x + 3x - 1 = 7 . (32 + 2 . 62)
=> 2.3x + 3x - 1 = 567
=> 7 . 3x - 1 = 567
=> 3x - 1 = 567 : 7 = 81
=> x - 1 = 4
=> x = 5
a)2*3x+3x-1=7(32+2*62)
2*3x+3x-1=7(9+72)=7*81
2*3x+3x/3=567
2*3x+3x*1/3=567
(2+1/3)*3x=567
7/3*3x=567
3x=567:7/3
3x=243=35
=>x=5
b) mk ko hiểu đề mấy, cái chỗ 7x+2 là nhân vs 2 ak
tìm các số nguyên n sao cho
\(\left(\frac{4}{9}\right)^n=\left(\frac{2}{3}\right)^5\)
Tìm X
\(7^{X+2}+2.7^{X-1}=345\)
\(\left(\frac{4}{9}\right)^n=\left(\frac{2}{3}\right)^5\)
<=>\(\left(\frac{2}{3}\right)^{\frac{n}{2}}=\left(\frac{2}{3}\right)^5\)
<=>\(\frac{n}{2}=5\)
<=>n=10
\(\left(\frac{4}{9}\right)^n=\left(\frac{2}{3}\right)^5\)
\(\Rightarrow\left(\frac{2}{3}\right)^{2n}=\left(\frac{2}{3}\right)^5\)
\(\Rightarrow2n=5\Rightarrow n=\frac{5}{2}\)
Vậy n = 5/2
tính:
\(a.9^x:3^x=3^7\)
b.\(\frac{1}{2}.2^x+2^{x+2}=2^8+2^5\)
c\(^{7^{x+2}+2.7^{x-1}=345}\)
d \(\left(\frac{1}{2}-\frac{1}{3}\right).6^x+6^{x+2}=6^7+6^4\)
\(9^x:3^x=3^7\)
\(\Rightarrow9:3^x=3^7\)
\(\Rightarrow3^x=3^7\)
\(\Rightarrow x=7\)
9x : 3x = 37
=> 9 : 3x = 37
=> 3x = 37
=> x = 7
9x ÷ 3x = 37
=> 9 ÷ 3x = 37
=> 3x = 37
=> x = 7
Tìm x biết \(7^{x+2}+2.7^{x-1}=345\)
7x+2+2.7x-1=345
=>7x-1(73+2)=345
=>7x-1=345:345=1
=>x-1=0
=>x=1
7^x-1 . 7^x+3 + 2. 7^x-1 = 345
7^x-1 .(7^x+3 + 2) =345
7^x-1. (7^x+3 + 2) = 7^x+3 -2
7^x-1 =(7^x+3 - 2) : (7^x+3 +2)
7^x-1 = 0
=> x-1 = 1
chắc chắn luôn
Tìm x, biết:
7x+2+2.7x-1=345
\(7^{x+2}+2.7^{x-1}=345\)
\(\Leftrightarrow7^x.\left(7^2+\dfrac{2}{7}\right)=345\)
\(\Leftrightarrow7x.\dfrac{345}{7}=345\)
\(\Leftrightarrow7x=345:\dfrac{345}{7}\)
\(\Leftrightarrow7x=7\)
\(\Leftrightarrow x=1\)
Vậy x = 1.
Tìm x
\(7^{x+2}+2.7^{x-1}=345\)
\(\frac{1}{2}2^x+2^{x+2}=2^8+2^5\)
\(2.3^x+3^{x-1}=7\left(3^2+2.6^2\right)\)
a) 7x+2 + 2.7x-1 = 345
7x-1 . 73 + 2.7x-1 = 345
7x-1.(343+2) = 345
7x-1. 345=345
=> 7x-1=1
=> 7x-1=70
=> x-1 =0
x=1
b)\(\frac{1}{2}\).2x + 2x+2= 28+25
\(\frac{1}{2}\).2x + 2x . 22 = 288
2x . ( \(\frac{1}{2}\)+ 4)= 288
2x . \(\frac{9}{2}\)=288
=>2x=64
2x= 26
=>x=6
c)2.3x +3x-1 = 7.( 32+2.62)
2.3x-1.31 + 3x-1 = 567
3x-1.(6+1)=567
3x-1.7=567
=>3x-1= 81
3x-1=34
=>x-1=4
x=5