\(H=\left(9+\dfrac{3}{8}+7+\dfrac{5}{8}\right)+4.03=17+4.03=21.03\)

\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4.03\)

\(H=\left(\frac{75}{8}+\frac{61}{8}\right)+\frac{403}{100}\)

\(H=17+\frac{403}{100}\)

\(H=\frac{2103}{100}\)

\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

\(I=10101.\left(\frac{5}{111111}-\frac{4}{111111}+\frac{5}{222222}\right)\)

\(I=10101.\left(\frac{1}{111111}+\frac{5}{222222}\right)\)

\(I=10101.\frac{7}{222222}\)

\(I=\frac{7}{22}\)

\(A=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03\)

\(A=\left(9,375+7,625\right)+4,03\)

\(A=17+4,03\)

\(A=21,03\)

I=10101(5/111111+5/222222+4/3.7.11.13.37)

I=10101(5/111111+5/222222+4/111111)

I=10101(10/222222+5/222222+8/222222)

I=10101.23/222222

I=232323/222222

\(I=\frac{7}{22}\)

\(H=\frac{2103}{100}=21,03\)

Nguyễn Triệu Yến Nhi chép sai đề rồi!!!

\(A=9.75\left(21+\dfrac{3}{7}+18+\dfrac{4}{7}\right)\cdot\dfrac{15}{78}=9.75\cdot40\cdot\dfrac{15}{78}=75\)

\(C=9\frac{30303}{80808}+4,03+7\frac{303030}{484848}\)

     \(=9\frac{3}{8}+4\frac{3}{100}+7\frac{5}{8}\)

      \(=\left(9+7\right)+\left(\frac{3}{8}+\frac{5}{8}\right)+4\frac{3}{100}\)

      \(=16+1+4\frac{3}{100}\)

       \(=21\frac{3}{100}\)

\(A=\left(9+\frac{30303}{80808}+7+\frac{303030}{484848}\right)+4,03\)

\(A=\left(9+\frac{3\times10101}{8\times10101}+7+\frac{30\times10101}{48\times10101}\right)+4,03\)

\(A=\left(9+\frac{3}{8}+7+\frac{5}{8}\right)+4,03\)

\(A=\left(9+7+\frac{3}{8}+\frac{5}{8}\right)+4,03\)

\(A=\left(16+1\right)+4,03\)

\(A=17+4,03=21,03\)