Có : 13! - 11! = 6187104000

a) A chia hết cho 2

b) A chia hết cho 5

c) A chia hết cho 155

Rảnh ~~~

Ta có:              13!       =    1x2x3x...x13

                       11!       =   1x2x3x...11

==>13!    -     11!           =    2(1x3x...13 -  1x3x...11) chia hết cho 2

Tương tự ta có chia hết cho 5 cũng như trên

c/ 13!    -     11!  =       1x2x3x...x11(12x13-1)   =      1x2x3x...x11 x 155 chia hết cho 155

minh kobiet cau c sao laitru 1

a) có

b) có

c) có

a) có

b) có

c) có 

k mình nha

*13! chia hết cho 2

11! chia het cho 2=>13!-11! chia hết cho 2

*13! chia het cho 5

11! chia het cho 5=>3!-11! chia het cho 5

*155=5.31

13! ko chia hết cho 5.31

11! ko chia het cho 5.31=>13!-11! ko chia het cho 155

a)A chia hết cho 2

b)A chia hết cho 5

c)A ko chia het cho 155

**** GIÙM MÌNH NHA

a) 13! = 13.12.11....5.4.3.2.1 => 13! chia hết cho 2 và 5

11! = 11.10.9....5.4.3.2.1 => 11! chia hết cho 2 và 5

=> A = 13! - 11! chia hết cho 2 và 5

c) A = 13! - 11! = 13.12.11! - 11! = (13.12 - 1) .11! = 155.11! chia hết cho 155

Vậy A chia hết cho 155

cảm ơn Trần Thị

 Loan nhé

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 \(A=13!-11!\)

\(A=11!\cdot12\cdot13-11!\)

\(A=11!\left(12\cdot13-1\right)\)

\(A=11!\cdot155\)

\(\Rightarrow\)A chia hết cho 2 ( vì trong 11! chứa thừa số 2 )

         A chia hết cho 5

         A chia hết cho 155

a)A có chia hết cho 2

b)A có chia hết cho 5

c)A có chia hết cho 155

a) có 

b) không

c) không

A=13!-11!=6187104000

a) A chia hết cho 2 vì số tận cùng của A là số 0

b) A chia hết cho 5 vì số tận cùng của A là số 0

c)A chia hết cho 2 và 5 vì số tận cùng của A là số 0

A=13!-11!

A=1.2.3....12.13-1.2.3....10.11

A=618 710 400

a)A chia hết cho 2 ( vì có số cuối là 0)

b)A chia hết cho 5( vì có số cuối là 0)

C)A chia hết cho 155( vì a>155 và 155=5.31)

\(A=13!-11!=1.2.3.4.5.6.7.8.9.10.11.12.13-1.2.3.4.5.6.7.8.9.10.11\)

a) \(13!⋮2\)\(11!⋮2\)\(\Rightarrow A⋮2\)

b) \(13!⋮5\)\(11!⋮5\)\(\Rightarrow A⋮5\)

c) \(A=13!-11!=1.2.3.4.5.6.7.8.9.10.11.12.13-1.2.3.4.5.6.7.8.9.10.11\)

\(=1.2.3.4.5.6.7.8.9.10.11.\left(12.13-1\right)\)

\(=1.2.3.4.5.6.7.8.9.10.11.155\)

\(\text{​​}\Rightarrow A⋮155\)