32/5 - 2/5 + 2
Muốn biết kết quả biểu thức (32 – 7)2 – (6 – 5 )3 tại ô A3 nhập công thức:
A. =(32 – 7)2 – (6 – 5 )3 B. =(32 – 7)^2 – (6 – 5 )^3
C. =(32 – 7)^2 – (6 – 5 )3 D. =(32 – 7)2 – (6 – 5 )*(6 – 5)
Tính bằng 2 cách:
a. (75 + 45) : 5 = ?
Cách 1: (75 + 45) : 5 = ……………………
Cách 2: (75 + 45) : 5 = ……………………
b.(88 – 32) : 8 = ?
Cách 1: (88 - 32) : 8 = ……………………
Cách 2: (88 - 32) : 8 = ……………………
a. (75 + 45) : 5 = ?
Cách 1: (75 + 45) : 5
= 120 : 5 = 24
Cách 2: (75 + 45) : 5
= 75 : 5 + 45 : 5
= 15 + 9
= 24
b.(88 – 32) : 8 = ?
Cách 1: (88 - 32) : 8
= 56 : 8 =7
Cách 2: (88 - 32) : 8
= 88 : 8 – 32 : 8
= 11 – 4
= 7
a) \(\dfrac{5-2\sqrt{ }5}{\sqrt{ }5-2}-\dfrac{11}{4+\sqrt{ }5} \)
b)\(\sqrt{9+4\sqrt{ }5-\sqrt{ }6-2\sqrt{ }5}\)
c)\(\sqrt{17-3\sqrt{ }32+\sqrt{ }17+\sqrt{ }32}\)
\(\dfrac{\sqrt{5}\left(\sqrt{5}-2\right)}{\sqrt{5}-2}-\dfrac{11\left(4-\sqrt{5}\right)}{16-5}=\sqrt{5}-4+\sqrt{5}=2\sqrt{5}-4\)
\(=\sqrt{5}-4+\sqrt{5}=2\sqrt{5}-4\)
A= [(-3/5 + 4/9):2/7-(-14/9+2/5):2/7]:(32/7.71/2-32/7.51/2)
A= [(-\(\frac{3}{5}+\frac{4}{9}\)) : \(\frac{2}{7}\) - (-\(\frac{14}{9}+\frac{2}{5}\)) : \(\frac{2}{7}\)] : (\(\frac{32}{7}.\) \(\frac{71}{2}-\frac{32}{7}\) . \(\frac{51}{2}\))
A= [ (-\(\frac{3}{5}+\frac{2}{5}\)) - (\(\frac{4}{9}+\frac{14}{9}\)) : \(\frac{2}{7}\)] : [ \(\frac{32}{7}\). (\(\frac{71}{2}-\frac{51}{2}\)) ]
A= (-\(\frac{36}{5}\)) : (\(\frac{320}{7}\))
A= - \(\frac{63}{400}\)
Chúc bạn học tốt!
a)\(\left(-3\right).8.\left(-2\right).5=\left(-3\right).\left(-2\right).8.5\)
\(=6.40=240\)
b)\(127-18.\left(5+6\right)=127-18.11\)
\(=127-198=-71\)
c)\(125-\left(-75\right)+32-\left(48+32\right)=125+75+32-48-32\)
\(\left(125+75\right)+\left(32-32\right)-48=200-48=152\)
d)\(3.\left(-4\right).2+2.\left(-5\right)-20=-12.2+2.\left(-5\right)-20\)
\(=\left(-12-5\right).2-20=-17.2-20=-140-20=-160\)
Chúc bạn học tốt
So sánh
0,625^200 và 0,5^1000
(-32)^27 và (-27)^32
(-3/2)^5 và (-2)^5
a) Ta có \(0,625^{200}=\left(\dfrac{5}{8}\right)^{200}\) và \(0,5^{1000}=\left(\dfrac{1}{2}\right)^{1000}=\left(\dfrac{1}{2}\right)^{5.200}\) \(=\left[\left(\dfrac{1}{2}\right)^5\right]^{200}\) \(=\left(\dfrac{1}{32}\right)^{200}\). Mà hiển nhiên \(\left(\dfrac{5}{8}\right)^{200}>\left(\dfrac{1}{32}\right)^{200}\) nên suy ra \(0,625^{200}>0,5^{1000}\)
b) Ta thấy \(\left(-32\right)^{27}< 0\) trong khi \(\left(-27\right)^{32}>0\) nên đương nhiên \(\left(-32\right)^{27}< \left(-27\right)^{32}\)
c) Ta thấy \(-\dfrac{3}{2}>-2\) nên \(\left(-\dfrac{3}{2}\right)^5>\left(-2\right)^5\)
Đúng ghi Đ, sai ghi S:
a) (32 + 128) : 4 = 32 : 4 + 128 : 4 = 8 + 32 = 40
b) 240 : (2 + 5) = 240 : 2 + 240 : 5 = 120 + 48 = 168
Hướng dẫn giải:
a) (32 + 128) : 4 = 32 : 4 + 128 : 4 = 8 + 32 = 40
b) 240 : (2 + 5) = 240 : 2 + 240 : 5 = 120 + 48 = 168
Tính:
\(A=\sqrt{20}-10\sqrt{\dfrac{1}{5}}+\sqrt{\left(\sqrt{5}-1\right)^2}\)
\(B=2\sqrt{32}+5\sqrt{8}-4\sqrt{32}\)
\(C=\sqrt{\left(3-\sqrt{2}^2\right)}-\sqrt{\left(1-\sqrt{2}\right)^2}\)
\(D=\sqrt{\left(5-1\right)^2}+\sqrt{\left(\sqrt{5}-3\right)^2}\)
\(E=\left(3+\dfrac{5-\sqrt{5}}{\sqrt{5}-1}\right)\left(3-\dfrac{5+\sqrt{5}}{\sqrt{5}-1}\right)\)
\(F=\sqrt{6+2\sqrt{5}}-\sqrt{9-4\sqrt{5}}\)
\(G=\dfrac{3\sqrt{2}-2\sqrt{3}}{\sqrt{3}-\sqrt{2}}+\dfrac{\sqrt{15}-\sqrt{5}}{\sqrt{3}-1}\)
\(H=\dfrac{10}{\sqrt{3}-1}-\dfrac{55}{2\sqrt{3}+1}\)
help
a) Ta có: \(A=\sqrt{20}-10\sqrt{\dfrac{1}{5}}+\sqrt{\left(\sqrt{5}-1\right)^2}\)
\(=2\sqrt{5}-2\sqrt{5}+\sqrt{5}-1\)
\(=\sqrt{5}-1\)
b) Ta có: \(B=2\sqrt{32}+5\sqrt{8}-4\sqrt{32}\)
\(=8\sqrt{2}+10\sqrt{2}-16\sqrt{2}\)
\(=2\sqrt{2}\)
tính nhanh p/s 1+ 5/4 + 5/8 + 5/16 + 5/32 + 5/64
b) 1/3 +1/9 + 1/27 + 1/81 +...........+ 1/59049
c) 3/2 + 3/8 + 3/32 +3/128 + 3/512
d) 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 giúp mình với
b: A=1/3+1/9+...+1/3^10
=>3A=1+1/3+...+1/3^9
=>A*2=1-1/3^10=(3^10-1)/3^10
=>A=(3^10-1)/(2*3^10)
c: C=3/2+3/8+3/32+3/128+3/512
=>4C=6+3/2+...+3/128
=>3C=6-3/512
=>C=1023/512
d: A=1/2+...+1/256
=>2A=1+1/2+...+1/128
=>A=1-1/256=255/256
Rút gọn các biểu thức sau:
a ) ( 8 − 3 2 + 10 ) 2 − 5 b ) 0 , 2 ( − 10 ) 2 ⋅ 3 + 2 ( 3 − 5 ) 2 c ) 1 2 1 2 − 3 2 ⋅ 2 + 4 5 ⋅ 200 : 1 8 d ) 2 ( 2 − 3 ) 2 + 2 ⋅ ( − 3 ) 2 − 5 ( − 1 ) 4
= (2√2 - 3√2 + 10)√2 - √5
= 2.(√2)2 - 3.(√2)2 + √10.√2 - √5
= 4 - 6 + √20 - √5 = -2 + 2√5 - √5
= -2 + √5
= 0,2.10.√3 + 2|√3 - √5|
s
= 2√3 + 2(√5 - √3)
= 2√3 + 2√5 - 2√3 = 2√5