a) Ta có: |26| > |–6|. Mà 26 mang dấu “+” nên kết quả phép tính mang dấu “+”.

26 + (–6) = 26 – 6 = 20.

b) |–75| > |50|. Mà –75 mang dấu “–“ nên kết quả phép tính mang dấu “–“.

(–75) + 50 = – (75 – 50 ) = –25;

c) |–220| > |80|. Mà –220 mang dấu “–“ nên kết quả phép tính mang dấu “–“.

80 + (–220 ) = – (220 – 80) = –140.

a ) \(26+\left(-6\right)=20\)

b )  \(\left(-75\right)+50=-25\)

c )    \(80+\left(-200\right)=-120\)

a. 26 + (-6) = 20

b. (-75) + 50 = -25

c. 80 + (-220) = -140

a . 26 + ( - 6 ) = + ( 26 - 6 ) = 20

b . ( - 75 ) + 50 = + ( 75 - 50 ) = 25

c . 80 + ( - 220 ) = - ( 220 - 80 ) = - 140

a)

b)

c)

a) 26 + (-6)

= 26 - 6

= 20

b) (-75) +50

= - (75 - 50)

= -25

c) 80 + (-220)

= - (220 - 80)

= -140

câu nầy hơn khó nên mình ko giải đc bạn đợ mình giải đã

1) 2763 + 152 = 2951

2)(-7) + (-14) = -21

3)(-35) + (-9) =-44

4) (-5) + (-248) = -253 

Cho mik xin lại đề bài mik nhìn ki hiểu j hết

1)2763 + 152 = 2915

2)(-7) + (-14) = -21

3)(-35) + (-9) = -44

4; (-5) + (-248)

= - (5 + 248)

= - 253

5; (-23) + 105

= -23 + 105

= 82;

6; 78 + (-123)

= 78 - 123

= -(123 - 78)

= - 45

7; 23 + (-13)

= 23 - 13

= 10

1.Tính                                                       2.Tính

 a)20                                                          a)-73 

 b)-25                                                         b)-30

 c)-140                                                        c)-18

 3.So sánh

      a)  A>B

      b) A=B

4. So sánh

      a)A<B

      b)A>B

      c) A<B

 Tick cho mình nha!!!

1) 2763 +152 =2915

2) (-7) +(-14) = -21

3) (-35) + (-9) = -44

4) (-5) + (-248) = -253

5) (-23) + 105 = 82

6) 78 + (-123) = -45

7) 23 +(-13) = 10

8) (-23) +13 = -10

9) 26 + (-6) = 20

10) (-75) +50 = -25

11) 80 + (-220) = -140

12) (-23) + (-13) = -36

13) (-26) + (-6) = -32

14) (-75) + (-50) = -125

15) ❏-18❏ + (-12) = -17❏ -12

16)17 + ❏ - 33❏ = 17 -32❏

17) (-20) +❏ - 88❏ = -20 -87❏

18) ❏- 3❏+ ❏5❏ = ❏5❏ -2❏

19)❏-37❏+❏15❏ = ❏15❏ -36❏

20) ❏-37❏+(-❏15❏) = -❏15❏ - 36❏

21) (-❏-32❏) +❏5❏ = ❏5❏ -33❏

22) (-❏-22❏) + (-❏16❏) = -❏16❏ -23❏

23) (-23) +13 +(-17) +57 = 30

24) 14 +6 + (-9) + (-14) = -3

25) (-123 ) +❏-13❏+(-7) = -130-12❏

26) ❏0❏ + ❏45❏ +(-❏-455)❏+❏-796❏ = ❏45❏-❏\(^2\) -1250❏

1.

a) \(125+80+375+220\)

\(=\left(125+375\right)+\left(80+220\right)\)

\(=500+300\)

\(=800\)

b) \(25.11.8.4.125\)

\(=\left(25.4\right).\left(8.125\right).11\)

\(=100.1000.11\)

\(=1100000\)

c) \(18.74+18.27-18\)

\(=18.\left(74+27-1\right)\)

\(=18.100\)

\(=1800\)

d) \(75.23+75.77-500\)

\(=75.\left(23+77\right)-500\)

\(=75.100-500\)

\(=7500-500\)

\(=7000\)

e) \(150:\left[25.\left(18-4^2\right)\right]\)

\(=150:\left[25.\left(18-16\right)\right]\)

\(=150:\left[25.2\right]\)

\(=150:50\)

\(=3\)

f) \(125.23.2.8.50\)

\(=\left(125.8\right).\left(2.50\right).23\)

\(=1000.100.23\)

\(=2300000\)

g) \(235+88+165+12\)

\(=\left(235+165\right)+\left(88+12\right)\)

\(=400+100\)

\(=500\)

h) \(71.32+71.68-1100\)

\(=71.\left(32+68\right)-1100\)

\(=71.100-1100\)

\(=7100-1100\)

\(=6000\)

i) \(6^7:6^6+4^3.2-24^0\)

\(=6+64.2-1\)

\(=6+128-1\)

\(=133\)

j) \(546-6.\left[158:\left(30+7^2\right)\right]\)

\(=546-6.\left[158:\left(30+49\right)\right]\)

\(=546-6.\left[158:79\right]\)

\(=546-6.2\)

\(=546-12\)

\(=534\)

k) \(268+147+132+253\)

\(=\left(268+132\right)+\left(147+253\right)\)

\(=400+400\)

\(=800\)

2. 

a) \(7x=707\)

\(x=707:7\)

\(x=101\)

b) \(6x+5=47\)

\(6x=47-5\)

\(6x=42\)

\(x=42:6\)

\(x=7\)

c) \(35:\left(x+1\right)=7\)

\(x+1=35:7\)

\(x+1=5\)

\(x=5-1\)

\(x=4\)

d) \(12+\left(29-3x\right)=35\)

\(29-3x=35-12\)

\(29-3x=23\)

\(3x=29-23\)

\(3x=6\)

\(x=6:3\)

\(x=2\)

e) \(2.4^x+10^1=138\)

\(2.4^x=138-10\)

\(2.4^x=128\)

\(4^x=128:2\)

\(4^x=64=4^3\)

\(\Rightarrow x=3\)

f) \(7x=140\)

\(x=140:7\)

\(x=20\)

g) \(7\left(15-x\right)+14=84\)

\(7\left(15-x\right)=84-14\)

\(7\left(15-x\right)=70\)

\(15-x=70:7\)

\(15-x=10\)

\(x=15-10\)

\(x=5\)

h) \(3^x.5-15=390\)

\(3^x.5=390+15\)

\(3^x.5=405\)

\(3^x=405:5\)

\(3^x=81=3^4\)

\(\Rightarrow x=4\)

3.

Ta có:

\(\Rightarrow n+11⋮n+1\)

\(\Rightarrow n+1+10⋮n+1\)

\(\Rightarrow10⋮n+1\) hay \(n+1\inƯ\left(10\right)=\left\{-10;-5;-2;-1;1;2;5;10\right\}\)

\(\Rightarrow\) \(n\in\left\{-11;-6;-3;-2;0;1;4;9\right\}\)

Vì \(n\in N\) nên \(n\in\left\{0;1;4;9\right\}\)