\(\Leftrightarrow-2x+\dfrac{3}{20}=1-\dfrac{1}{2}+1-\dfrac{1}{6}+...+1-\dfrac{1}{110}\)

\(\Leftrightarrow-2x+\dfrac{3}{20}=10-\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{10}-\dfrac{1}{11}\right)\)

\(\Leftrightarrow-2x+\dfrac{3}{20}=10-\dfrac{10}{11}=\dfrac{100}{11}\)

=>-2x=1967/220

hay x=-1967/440

a/ x – 6 = - 3

   x = -3 + 6 = 3

b/ 3x + 17 = 29

   3x = 29 - 17

    x  = 12 : 3 =4

c/ 2x + 11 = 15

   2x = 15 - 11

    x = 4 : 2 =2

\(a,x=\left(-3\right)+6=3\\ b,3x=29-17=12\\ x=12:3=4\\ c,2x=15-11=4\\ x=14:2=7\)

x - 6 = -3

x = - 3  + 6

x = 3

b ) 3x + 17 = 29

3x = 29 - 17

3x = 12

x = 12 : 3

x = 4

c/ 2x + 11 = 15

2x = 15 - 11

2x = 4

x = 4 : 2

x = 2

1 Tìm số nguyên x bik:

a.-( 2x+2)+25=-19           

-2x - 2 + 25 = - 19

-2x = -19+2-25

-2x = -42

   x = 21   

 b.1-(12+3x)=7

1 - 12 - 3x = 7

- 11 - 3x = 7

 -3x = 7 + 11

- 3x = 18

    x = -6

c.-(2x+2)+25=-19

 giống câu a nhé

2.Rút gọn biểu thức 

a.2x+(-61)-(21-61)       

= 2x - 61 - 21 + 61

= 2x - 21  

b. (-3-x+5)+3

= 2 - x + 3

= -1 -x 

c.11-(13-x)+(13-11)         

= 11 - 13 + x + 13 - 11

= x

d.25-(15-x+303)+303

= 25 - 15 + x - 303 + 303

= 10 + x

e.x+(-81)-(11-8)                     

= x - 81 - 11 + 8

= x - 84

f. (-1-x+2)+1

= -1 - x + 2 + 1

= - x + 2

g.15-(11-x)+(11-15)             

= 15 - 11 + x + 11 - 15

= x  

i) 15-(15-x+202)+202

= 15 - 15 + x - 202 + 202

= x

3.Chứng minh đẳng thức

a.-(59-3x)+39=3x-20       

- 59 + 3x + 39 = 3x - 20

- 59 + 39 + 20 = 3x - 3x

           0          = 0

b.-(a+b+c)+(b-c)-(a-c-1)=1+c-29

b - a - b - c + b - c - a + c + 1 = 1 + c - 29

b - a - b - c + b - c - a + c - c = 1 - 29 - 1

                   - 2a + b - 2c          = - 29

chịu luôn  -__- 

c.-(19-2x)+39=2x+20

- 19 + 2x + 39 = 2x + 20

2x - 2x = 20 + 19 - 29

0          = 0

d.-(a+b+c)+b-c-( a-c+1)=c-2a-1

- a - b - c + b - c - a + c - 1 = c - 2a - 1

- a - b - c + b - c - a + c + 2a - c = -1 + 1

                     - 2c  =  0

                         c  = 0

Vậy c = 0

Lời giải:
\(\frac{1}{2}+\frac{5}{6}+\frac{11}{12}+\frac{19}{20}+\frac{29}{30}=1-\frac{1}{2}+1-\frac{1}{6}+1-\frac{1}{12}+1-\frac{1}{20}+1-\frac{1}{30}\)

\(=5-\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\right)\)

\(=5-\left(\frac{2-1}{1\times 2}+\frac{3-2}{2\times 3}+\frac{4-3}{3\times 4}+\frac{5-4}{4\times 5}+\frac{6-5}{5\times 6}\right)\)

\(=5-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\right)\)

\(=5-\left(1-\frac{1}{6}\right)=5-\frac{5}{6}=\frac{25}{6}\)

b: =>15-x=-10

hay x=25

a: =>-2x+17=9

=>-2x=-8

hay x=4

d: \(\Leftrightarrow9x^2=81\)

hay \(x\in\left\{3;-3\right\}\)

e: \(\Leftrightarrow\left[{}\begin{matrix}2x-4=0\\3-x=0\end{matrix}\right.\Leftrightarrow x\in\left\{2;3\right\}\)

Lằng nhằng vậy😅

Bằng 3060 nha nhớ k mình luôn nha =))))

bấm máy đi

\(5-\frac{1}{2}-\frac{5}{6}-\frac{11}{12}-\frac{19}{20}-\frac{29}{30}\)

\(=\left(1-\frac{1}{2}\right)+\left(1-\frac{5}{6}\right)+\left(1-\frac{11}{12}\right)+\left(1-\frac{19}{20}\right)+\left(1-\frac{29}{30}\right)\)

\(=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\)

\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{5}-\frac{1}{6}\)

\(=1-\frac{1}{6}\)

\(=\frac{5}{6}\)

Đáp án : \(\frac{5}{6}\)

TK NHA!!

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