= 52 nha em

a) 36 + 53 + 47 + 64 = (36+64)+(53+47)= 100+100=200

b) =(242-42)+(167-67)= 200+100=300

A)

= ( 36 + 64 ) + ( 53 + 47 )

= 100 + 100

= 200

B)

= ( 242 - 42 ) + ( 167 - 67 )

= 200 + 100

= 300

300

300

= 300 

a) 2 x 31 x 12 + 4 x 6 x 42 + 8 x 27 x 3

= 24 x 31 + 24 x 42 + 24 x 27

= 21 x ( 31 + 42 + 27)

= 21 x 100

= 2100

b) 36 x 28 + 36 x 82 + 64 x 69 + 64 x 41

= 36 x ( 28 + 82) + 64 x ( 69 + 41)

= 36 x 110 + 64 x 110 

= 110 x ( 36 + 64)

= 110 x 100

= 11000

a)2 x 31 x12 + 4 x 6 x 42 + 8 x 27 x 3

= 24 x 31 + 24 x 42 + 24 x 27

= 24 x (31 + 24 + 27)

=24 x 82

=1968

b)36 x 28 + 36 x 82 + 64 x 69 + 64 x 41

=36 x (28 + 82) + 64 x ( 69 + 41 )

=36 x 110 + 64 x 110

=3960 + 7040

=11000

a) 2x31x12+4x6x42+8x27x3

=2x12x31+4x6x42+8x3x27

=24x31+24x42+24x27

=24x(31+42+27)

24x100=2400

b)36x28+36x82+64x69+64x41

=36x(28+82)+64x(69+41)

=36x110+64x110

a ) 5 x 216 x 25 x 4 = 1080 x 100 = 108000

b ) 37 x 16 x 25 x 4 = 592 x 100 = 59200

c ) 36 x ( 28 + 82 ) + 64 x ( 69 + 41 ) = 36 x 110 + 64 x 110 = ( 36 + 64 ) x 110 = 100 x 110 = 11000

d ) 42 x ( 53 + 36 + 11 ) = 42 x 100 = 4200

e) 37 x 45 + 56 x 37 - 37 x 1 = 37 x ( 45 + 56 - 1 ) = 37 x 100 = 3700

h) 17 x 1 + 17 x 81 + 18 x 17 = 17 x ( 1 + 81 + 18 ) = 17 x 100 = 1700

Mik nhanh nhất đấy , nhớ click cho mik nha !!!!!!!!!!!!!!!!!!!

a) 5 x 25 x 216 x 4

= ( 5 x 216 ) x ( 25 x 4 )

= 1080 x 100

= 108000

b) 4 x 37 x 25 x 16 

= ( 4 x 25 ) x ( 37 x 16 )

= 100 x 592 

= 59200

a)=(25x4)x5x216=100x5x216=500x216=108000

b)=(4x25)x37x16=100x37x16=3700x16=59200

c)=[36x(28+82)]+[64x(69+41)]=[36x110]+[64x110]=110x(36+64)=110x100=11000

d)=42x(53+36+11)=42x100=4200

e)=37x(45+56-1)=37x100=3700

h)=17x(1+81+18)=17x100=1700

k mk nhá

- Đặt tính : Viết các phép tính sao cho các chữ số cùng hàng thẳng cột với nhau.

- Tính : Thực hiện tính từ phải sang trái.

Vì dãy số hạng có 21 số nên trung bình cộng của dãy số trên là số hạng thứ 11 

Tổng của chúng là :

36 x 21 = 756

=  712 nha bn

16+18+20+....+56

= (16+56):2x21

= 72:2x21

=36x21

=756

Bài 1: 

1) Ta có: \(\left(-12\right)+6\cdot\left(-3\right)\)

\(=-12-18\)

=-30

2) Ta có: \(\left(36-2020\right)+\left(2019-136\right)-27\)

\(=36-2020+2019-136-27\)

\(=1-100-27\)

\(=-126\)

3) Ta có: \(\left(144-97\right)-\left(244-197\right)\)

\(=144-97-244+197\)

\(=-100+100=0\)

4) Ta có: \(\left(-24\right)\cdot13-24\cdot\left(-3\right)\)

\(=-24\cdot13+24\cdot3\)

\(=24\cdot\left(-13+3\right)\)

\(=24\cdot\left(-10\right)=-240\)

5) Ta có: \(54+55+56+57+58-\left(64+65+66+67+68\right)\)

\(=54+55+56+57+58-64-65-66-67-68\)

\(=\left(54-64\right)+\left(55-65\right)+\left(56-66\right)+\left(57-67\right)+\left(58-68\right)\)

\(=\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)+\left(-10\right)\)

=-50

6) Ta có: \(24\cdot\left(16-5\right)-16\cdot\left(24-5\right)\)

\(=24\cdot16-24\cdot5-16\cdot24+16\cdot5\)

\(=-24\cdot5+16\cdot5\)

\(=5\cdot\left(-24+16\right)\)

\(=-5\cdot8=-40\)

7) Ta có: \(47\cdot\left(23+50\right)-23\cdot\left(47+50\right)\)

\(=47\cdot23+47\cdot50-23\cdot47-23\cdot50\)

\(=47\cdot50-23\cdot50\)

\(=50\cdot\left(47-23\right)\)

\(=50\cdot24=1200\)

8) Ta có: \(\left(-31\right)\cdot47+\left(-31\right)\cdot52+\left(-31\right)\)

\(=-31\cdot\left(47+52+1\right)\)

\(=-31\cdot100=-3100\)

Bài 2: 

1) Ta có: \(-17-\left(2x-5\right)=-6\)

\(\Leftrightarrow-17-2x+5+6=0\)

\(\Leftrightarrow-2x-6=0\)

\(\Leftrightarrow-2x=6\)

hay x=-3

Vậy: x=-3

2) Ta có: \(10-2\left(4-3x\right)=-4\)

\(\Leftrightarrow10-8+6x+4=0\)

\(\Leftrightarrow6x+6=0\)

\(\Leftrightarrow6x=-6\)

hay x=-1

Vậy: x=-1

3) Ta có: \(-12+3\left(-x+7\right)=-18\)

\(\Leftrightarrow-12-3x+21+18=0\)

\(\Leftrightarrow-3x+27=0\)

\(\Leftrightarrow-3x=-27\)

hay x=9

Vậy: x=9

4) Ta có: \(-45:\left[5\cdot\left(-3-2x\right)\right]=3\)

\(\Leftrightarrow5\cdot\left(-3-2x\right)=-15\)

\(\Leftrightarrow-2x-3=-3\)

\(\Leftrightarrow-2x=0\)

hay x=0

Vậy: x=0

5) Ta có: x(x+3)=0

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-3\right\}\)

6) Ta có: (x-2)(x+4)=0

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-4\end{matrix}\right.\)

Vậy: \(x\in\left\{2;-4\right\}\)

7) Ta có: \(x\left(x+1\right)\left(x-3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-1\\x=3\end{matrix}\right.\)

Vậy: \(x\in\left\{0;-1;3\right\}\)

Bài 1: 

1) Ta có: (−12)+6⋅(−3)(−12)+6⋅(−3)

=−12−18=−12−18

=-30

2) Ta có: (36−2020)+(2019−136)−27(36−2020)+(2019−136)−27

=36−2020+2019−136−27=36−2020+2019−136−27

=1−100−27=1−100−27

=−126

Tớ chcs cậu học thật giỏi nha !

a) \(56^2+44^2+2.56.44=56^2+2.56.44+44^2=\left(56+44\right)^2=100^2=10000\)

b) \(36^2+64^2+72.64=36^2+2.36.64+64^2=\left(36+64\right)^2=100^2=10000\)

c) \(136^2+36^2-72.136=136^2-2.36.136+36^2=\left(136-36\right)^2=100^2=10000\)

a) $56^2+44^2+2.56.44=56^2+2.56.44+44^2=\left(56+44\right)^2=100^2=10000$562+442+2.56.44=562+2.56.44+442=(56+44)2=1002=10000

b) $36^2+64^2+72.64=36^2+2.36.64+64^2=\left(36+64\right)^2=100^2=10000$362+642+72.64=362+2.36.64+642=(36+64)2=1002=10000

c) $136^2+36^2-72.136=136^2-2.36.136+36^2=\left(136-36\right)^2=100^2=10000$