1000+1000+1000+x=4000

3000+x=4000

x=4000-3000

x=1000

mình mình tk lại

X= 1000

1000 +1000+1000+x=4000

=> x=4000-1000-1000-1000

=>x= 1000

Ta có : \(x-\left\{x-\left[x+x-1\right]\right\}=1\)

\(x-\left\{x-x-x+1\right\}=1\)

\(x-x+x+x-1=1\)

\(2x-1=1\)

\(2x=1+1\)

\(2x=2\)

\(\Rightarrow x=2:2\)

\(x=1\)

\(x-\left\{x-\left[x-\left(-x+1\right)\right]\right\}=1\)

          \(x-\left\{x-\left[x+x-1\right]\right\}=1\)

                \(x-\left\{x-x-x+1\right\}=1\)

                        \(x-x+x+x-1=1\)

                                                \(2x-1=1\)

                                                         \(2x=2\)

                                                           \(x=1\)

                        Vậy x=1

5000 + X = 10 000

           X = 10 000 - 5000

           X = 2000

tk nhe

mình đang cần điểm hỏi đáp

cảm ơn

ok 5000

1000+1000+1000+2000+x=10000

(1000+1000+1000+2000)+x=10000

5000+x=10000

x=10000-5000

x=5000

=>x=5000

toi khong biey xin hay giup toi

X=56/27

\(x+\frac{16}{9}=\frac{x}{7}\)

\(\frac{16}{9}=\frac{x}{7}-\frac{x}{1}\) 

\(\frac{16}{9}=\frac{x}{7}-\frac{7x}{7}\)

\(\frac{19}{9}=\frac{\left(-6\right)x}{7}\)

\(\frac{133}{63}=\frac{\left(-54\right)x}{63}\)

\(\Rightarrow133=\left(-54\right)x\)

\(\Rightarrow133:\left(-54\right)=x\)

\(\Rightarrow-2,4629=x\)

=>3.(x-3)=2.(x+1)

<=>3x-9=2x+2

<=>3x-2x=2+9

<=>x=11

\(\frac{x+2}{3}=\frac{x-2}{2}\Rightarrow2\left(x+2\right)=3\left(x-2\right)\)

=>2x+4=3x-6

=>2x-3x=-4-6

=>-x=-10

=>x=10

k minh di minh lm cho

1) \(x-36:18=12\)

\(\Rightarrow x-2=12\)

\(\Rightarrow x=14\)

2) \(\left(x-36\right):18=12\)

\(\Rightarrow x-36=216\)

\(\Rightarrow x=252\)

x(2 + x²)(7 - x) = 0

<=> x = 0 hoặc 2 + x² = 0 hoặc 7 - x = 0

Mà 2 + x² > 0 => x = 0 và 7 - x = 0

=> x = 0 và x = 7

Vậy  x = 0 và x = 7

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