Tìm x: \(32^{-x}.16^x=2048\)
Tìm số tự nhiên x:
a/ 2^(-1)*2^n+4*2^n=9*2^5
b/ 32^(-n)*16^n=2048
2x+2 - 22 = 96
32-x . 16x = 2048
Tìm x biết
\(32^{-x}\cdot16^x=2048\)
ta có công thức như sau :
\(a^{-x}=?\)
lời giải công thức này như sau :
\(a^{-x}=\left(\frac{1}{a}\right)^x\)
vậy bài cũng gải tương tự
\(32^{-x}.16^x=\left(\frac{1}{32}\right)^x.\left(16^x\right)\)
\(=\left(\frac{16}{32}\right)^x=\left(\frac{1}{2}\right)^x=2^{-x}\)
mà \(2048=2^{11}\)
\(\Rightarrow-x=11\)
\(\Leftrightarrow x=-11\)
vậy \(x=-11\)
\(\Rightarrow\)\(\left(\frac{1}{32}\right)^x\cdot16^x=2048\)
\(\Rightarrow\)\(\left(\frac{1}{2}\right)^x=\left(\frac{1}{2}\right)^{-11}\)
\(\Rightarrow\)\(x=-11\)
Tìm x thuộc Z
a)\(32^{-n}.16^n=2048\)
b)\(2^{-1}.2^n+4.2^n=9.2^5\)
a)\(32^{-n}\cdot16^n=2048\)
\(\left(2^5\right)^{-n}\cdot\left(2^4\right)^n\)=2048
\(2^{-5n}\cdot2^{4n}\)=\(2^{11}\)
\(2^{-5n+4n}=2^{11}\)
\(2^{-x}=2^{11}\)
\(\Rightarrow x=-11\)
b)\(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\frac{1}{2}\cdot2^n+4\cdot2^n=288\)
\(2^n\left(\frac{1}{2}+4\right)=288\)
\(2^n\cdot\frac{9}{2}=288\)
\(2^n=288:\frac{9}{2}\)
\(2^n=64\)
\(2^n=2^6\)
\(\Rightarrow n=6\)
a) 32-n . 16n = 2048
\(\frac{1}{32n}\) . 16n = 2048
\(\frac{1}{2^n.16^n}\) . 16n = 2048
\(\frac{1}{2^n}\) = 2048
2-n = 2048
2-n = 211
\(\Rightarrow\) -n = 11
\(\Rightarrow\) n = -11
Vậy n = -11
\(32^{-x}\cdot16^x=2048\)
a ) 32^ -x .16^x =2048 =>x=?
b ) (x-y)^2 +|2x-1| = 0 =>x=? ;y=?
c ) (x-2y)^2 +(y+1)^6 =0 =>x=? ;y=?
d ) (2x-5)^2000 + (3y+4)^2002 < hay = 0
=>x=? ;y=?
giai thich ra nha
Tìm n biết 32-n*16n=2048
32^-n.16^n=2048=>1/32^n.16^n=2048
=>1/(16^n.2^n).16^N=2048
=>1/2^n=2048=>n= -11
bài 1 : tìm GTLN : M = 3 - /5-x/
N = 10 - /x+2/ - /1-y/
Bài 2: tìm n
a ) 32< 2n < 128
b)\(\frac{1}{9}.27^n=3^n\)
c) \(3^{-1}.3^n+4.3^n=13.3^7\)
\(32^{-n}.16^n=2048\)
HELP ME NOW
tìm x ; a) (3x-5)^5= -243
b) (7x+2)^-1= 3^-2
c)2^-1. 2^x + 4.2^x = 9.2^5
d)32^-x . 16^x=2048
e)3^-2 . 3^4 . 3^x=3^7
mik sẽ tích cho 2 bạn làm nhanh nhất nhé