\(1+1+1+1+1+1+1+1+1+1X10=.............\)
(1+1/2+1/3+....+1/9+1/10)/ (1/1x10+1/2x9+1/3x8+....+1/8x3+1/9x2+1/10x1)
Tính nhanh
(1+1/2+1/3+....+1/9+1/10)/ (1/1x10+1/2x9+1/3x8+....+1/8x3+1/9x2+1/10x1)
Tính nhanh
1+1-1x1:1x10=?
b=1/1x10+1/2x15+1/3x20+x.......x1/98x495+11/99x500
\(B=\frac{1}{1x2x5}+\frac{1}{2x3x4}+\frac{1}{3x4x5}+...+\frac{1}{98x99x5}+\frac{1}{99x100x5}\)
\(5B=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{98x99}+\frac{1}{99x100}\)
\(5B=\frac{2-1}{1x2}+\frac{3-2}{2x3}+\frac{4-3}{3x4}+...+\frac{99-98}{98x99}+\frac{100-99}{99x100}\)
\(5B=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{98}-\frac{1}{99}+\frac{1}{99}-\frac{1}{100}\)
\(5B=1-\frac{1}{100}=\frac{99}{100}\Rightarrow B=\frac{99}{500}\)
1) 1/1+2 + 1/1+2+3+.........+1/1+2+3+..............+10
2) 1+3+6+10+.........+45+55/1x10+2x9+.......+9x2+10x1
\(A=\dfrac{1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{9}+\dfrac{1}{10}}{\dfrac{1}{1x10}+\dfrac{1}{2x9}+\dfrac{1}{3x8}+...+\dfrac{1}{8x3}+\dfrac{1}{9x2}+\dfrac{1}{10x1}}\)
\(\frac{1}{2x3}+\frac{1}{4x5}+\frac{1}{6x7}+\frac{1}{8x9}+\frac{1}{1x10}\)
nhân trước, cộng lại
quy đồng
kết quả là số tìm được
Tìm hệ số của 1 x 2 trong khai triển 1 − 1 x 10 .
A. 1 x 2
B. 2
C. 1
D. -1
\(\dfrac{1+3+6+10+...+45+55}{1x10+9x2+3x8+...9x2+10x1}\)