a)\(\frac{x^2+3x+2}{3x+6}=\frac{x^2+2x+x+2}{3\cdot\left(x+2\right)}=\frac{\left(x^2+2x\right)+\left(x+2\right)}{3\cdot\left(x+2\right)}=\frac{x\cdot\left(x+2\right)+\left(x+2\right)}{3\cdot\left(x+2\right)}\)

\(=\frac{\left(x+2\right)\cdot\left(x+1\right)}{3\cdot\left(x+2\right)}=\frac{x+1}{3}\)

b) \(\frac{2x^2+x-1}{6x-3}=\frac{2x^2+2x-x-1}{3\cdot\left(2x-1\right)}=\frac{\left(2x^2+2x\right)-\left(x+1\right)}{3\cdot\left(2x-1\right)}\)

\(=\frac{2x\cdot\left(x+1\right)-\left(x+1\right)}{3\cdot\left(2x-1\right)}=\frac{\left(2x-1\right)\cdot\left(x+1\right)}{3\cdot\left(2x-1\right)}=\frac{x+1}{3}\)

a) Ta có: \(\frac{x^2+3x+2}{3x+6}\) \(\left(x\ne-2\right)\)

\(=\frac{\left(x+1\right)\left(x+2\right)}{3\left(x+2\right)}\)

\(=\frac{x+1}{3}\)

b) Ta có: \(\frac{2x^2+x-1}{6x-3}\) \(\left(x\ne\frac{1}{2}\right)\)

\(=\frac{\left(2x-1\right)\left(x+1\right)}{3\left(2x-1\right)}\)

\(=\frac{x+1}{3}\)

xem lại phân số cuối          

đúng đề òi ạ

a: \(=\dfrac{3\left(x-2\right)}{\left(x-2\right)^3}=\dfrac{3}{\left(x-2\right)^2}\)

b: \(=\dfrac{x^2\left(x+2\right)}{\left(x+2\right)^3}=\dfrac{x^2}{\left(x+2\right)^2}\)

nhân cả tử và mẫu của phân số thứ nhất với x là ra thôi bn

\(Q=\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)

\(Q=\frac{3x}{2x^2+6x}-\frac{x-6}{2x^2+6x}\)

\(Q=\frac{3x-x+6}{2x^2+6x}=\frac{2x+6}{2x^2+6x}=\frac{1}{x}\)

Chúc bạn học tốt!!!

Câu 1: C

Câu 2: =x(x-2)*(x+2)

khó quá tui ko biết làm..

k cho tui nha

thanks

A=\(\frac{x^3-7x+6}{x^3+5x^2-2x-24}\)=\(\frac{x^3-2x^2+2x^2-4x-3x+6}{x^3-2x^2+7x^2-14x+12x-24}\)=\(\frac{x^2\left(x-2\right)+2x\left(x-2\right)-3\left(x-2\right)}{x^2\left(x-2\right)+7x\left(x-2\right)+12\left(x-2\right)}\)=\(\frac{\left(x-2\right)\left(x^2+2x-3\right)}{\left(x-2\right)\left(x^2+7x+12^{^{^{^{^{^{^{^{^{ }}}}}}}}}\right)}\)=\(\frac{\left(x-2\right)\left(x^2-x+3x-3\right)}{\left(x-2\right)\left(x^2+3x+4x+12\right)}\)=\(\frac{\left(x-2\right)\left(x-1\right)\left(x+3\right)}{\left(x-2\right)\left(x+4\right)\left(x+3\right)}\)=\(\frac{x-1}{x+4}\)