tính f = 1 1/5 x 1 1/6 x 1 1/7 x ..............x 1 1/2019 x 1 1/2020
*GIẢI THÍCH*
VD: 2 3/4= Hai ba phần bốn.
#Toán lớp 5
tính f = 1 1/5 x 1 1/6 x 1 1/7 x ..............x 1 1/2019 x 1 1/2020
*GIẢI THÍCH*
VD: 2 3/4= Hai ba phần bốn.
cái này chỉ là thử sức thôi nha chỉ dành cho lớp 5 ai giải được là thông minh
1.TÍNH
a 5454 / 5757 - 171717 / 191919
b 6/5 X 7/6 X 8/7 X 9/8 X ... 2020/2019 X 2021/2020
2.SO SÁNH
1/3 + 1/6 +1/10 + 1/15 + 1/21+ 1/28 + 1/36+ 1/45 và 1
1/a-1 và 1/a+1
1) a) \(\frac{5454}{5757}-\frac{171717}{191919}=\frac{18\times3\times101}{19\times3\times101}-\frac{17\times10101}{19\times10101}=\frac{18}{19}-\frac{17}{19}=\frac{1}{19}\)
b) \(\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times....\times\frac{2021}{2020}=\frac{6\times7\times8\times...\times2021}{5\times6\times7\times...\times2020}=\frac{2021}{5}\)
2) \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{45}=2\times\frac{1}{6}+2\times\frac{1}{12}+2\times\frac{1}{20}+...+2\times\frac{1}{90}\)
\(=2\times\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{90}\right)\)
\(=2\times\left(\frac{1}{2\times3}+\frac{1}{3\times4}+\frac{1}{4\times5}+...+\frac{1}{9\times10}\right)\)
\(=2\times\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)=2\times\left(\frac{1}{2}-\frac{1}{10}\right)=2\times\frac{2}{5}=\frac{4}{5}\)
b)Vì \(a-1< a+1\)
=> \(\frac{1}{a-1}>\frac{1}{a+1}\)
1/ a x b = 1/a - 1/b
a) (1 - 1/2) x (1 - 1/3) x (1 - 1/4) x (1 - 1/5) x (1 - 1/6)
b) (1 - 1/2) x (1 - 1/4)x...x (1 - 1/2019) x (1 - 1/2020)
a, \(=\dfrac{1.2.3...5}{2.3...6}=\dfrac{1}{6}\)
1.a 2 5 1 4 3 10b 8 12 3 7 9 7 c 1 6 x 4 9 5 9 x 1 6 1d 183 93 1 5 2 x 102 1 2 3 4 1 2021 2.a 3 5 x 0,8b 1 4 3 4 x 2 5c x 1 2 8 25 x 1 cái gạch ngang là gạch phân số ạ VD một phần hai 1 2mong mng giúp em sớm ạ
Xin lỗi m.n nhé gửi nhầm tí
Bài 1: thực hiện phép tính
a)1/1×2+1/2×3+1/3×4+...+1/2019×2020
b)1/1×3+1/3×5+1/5×7+...+1/2017×2019
c)3^0+3^1+3^2+...+3^100
d)1/2+1/2^2+1/2^3+...+1/2^2019
Bài2:tìm x
a)|x-2|+|x2 -4=0
b)x+1/2.x-25%.x=10
c)2+4+6+8+...+2x=210
d)1/5×8+1/8×11+1/11×14+...+1/x(x+3)=101/1504
Chú ý: dấu chấm ở câu b)bài 2 là dấu nhân
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2019.2020}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2019}-\frac{1}{2020}\)
\(A=1-\frac{1}{2020}\)
\(A=\frac{2019}{2020}\)
\(B=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{2017.2019}\)
\(2B=\frac{2}{1.3}+\frac{2}{3.5}=\frac{2}{5.7}+...+\frac{2}{2017.2019}\)
\(2B=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}=\frac{1}{5}-\frac{1}{7}+...+\frac{1}{2017}-\frac{1}{2019}\)
\(2B=1-\frac{1}{2019}\)
\(2B=\frac{2018}{2019}\)
\(B=\frac{2018}{2019}:2=\frac{1009}{2019}\)
\(C=3^0+3^1+3^2+...+3^{100}\)
\(3C=3^1+3^2+3^3+...+3^{101}\)
\(3C-C=\left(3^1+3^2+3^3+...+3^{101}\right)-\left(1+3^1+3^2+...+3^{100}\right)\)
\(2C=3^{101}-1\)
\(C=\frac{3^{101}-1}{2}\)
Cho hàm số f(x)= x +1/4 Tính tổng f(0)+f(1/2021)+f(2/2021)+f(3/2021)+...+f(2019/2021)+f(2020/2021)+f(1)
Nếu 1/3 + 1/6 +1/10 + ...... + 1/x.(x+1) : 2 = 2019/2021
A.x = 2019/2020 B. x = 2019 C. x = 2020 D. x = 2021
Tính giải trí của biểu thức : ( 1 - 1/2 ) x ( 1 - 1/3 ) x ( 1 - 1/4 ) x ... x ( 1 - 1/2019 ) x ( 1 - 1/2020 )
Hộ mình cái minh cần gấp
A=1/2x2/3x3/4x...x2018/2019x2019/2020=1/2020
A = 1/2 x 2/3 x 3/4 x ... x 2018/2019 x 2019/2020 = 1/2020
1. 2019/2020-(2019/2020-2020/2021)
2.2/9+7/9 :(42/5-7/5
3.a)3/4+x/4=5/8
4./3x+1/-1/4=-1/4
1. \(\dfrac{2019}{2020}-\left(\dfrac{2019}{2020}-\dfrac{2020}{2021}\right)\)
\(=\dfrac{2019}{2020}-\dfrac{2019}{2020}+\dfrac{2020}{2021}\)
\(=0+\dfrac{2020}{2021}=\dfrac{2020}{2021}\)
Giải:
1) \(\dfrac{2019}{2020}-\left(\dfrac{2019}{2020}-\dfrac{2020}{2021}\right)\)
\(=\dfrac{2019}{2020}-\dfrac{2019}{2020}+\dfrac{2020}{2021}\)
\(=\left(\dfrac{2019}{2020}-\dfrac{2019}{2020}\right)+\dfrac{2020}{2021}\)
\(=0+\dfrac{2020}{2021}\)
\(=\dfrac{2020}{2021}\)
2) \(\dfrac{2}{9}+\dfrac{7}{9}:\left(\dfrac{42}{5}-\dfrac{7}{5}\right)\)
\(=\dfrac{2}{9}+\dfrac{7}{9}:7\)
\(=\dfrac{2}{9}+\dfrac{1}{9}\)
\(=\dfrac{1}{3}\)
3) \(\dfrac{3}{4}+\dfrac{x}{4}=\dfrac{5}{8}\)
\(\dfrac{x}{4}=\dfrac{5}{8}-\dfrac{3}{4}\)
\(\dfrac{x}{4}=\dfrac{-1}{8}\)
\(\Rightarrow x=\dfrac{4.-1}{8}=\dfrac{-1}{2}\)
4) \(\left|3x+1\right|-\dfrac{1}{4}=\dfrac{-1}{4}\)
\(\left|3x-1\right|=\dfrac{-1}{4}+\dfrac{1}{4}\)
\(\left|3x-1\right|=0\)
\(3x-1=0\)
\(3x=0+1\)
\(3x=1\)
\(x=1:3\)
\(x=\dfrac{1}{3}\)
Chúc bạn học tốt!
4) \(\left|3x+1\right|-\dfrac{1}{4}=\dfrac{-1}{4}\)
\(\left|3x+1\right|=\dfrac{-1}{4}+\dfrac{1}{4}\)
\(\left|3x+1\right|=0\)
\(3x+1=0\)
\(3x=0-1\)
\(3x=-1\)
\(x=-1:3\)
\(x=\dfrac{-1}{3}\)