6. ÉT O ÉT
\(\dfrac{9}{7}\) và \(\dfrac{5}{6}\) \(\dfrac{4}{7}\) và \(\dfrac{8}{21}\) \(\dfrac{2}{5};\dfrac{1}{3}\) và \(\dfrac{1}{2}\) \(\dfrac{1}{3};\dfrac{4}{3}\) và\(\dfrac{1}{5}\)
6. ÉT O ÉT
\(\dfrac{125}{90}=\dfrac{25}{...}\) / \(\dfrac{84}{91}=\dfrac{...}{13}\) / \(\dfrac{75}{...}=\dfrac{25}{15}=\dfrac{...}{3}\)
\(\dfrac{6}{7}=\dfrac{...}{21}=\dfrac{54}{...}=\dfrac{...}{126}\)
125/90=25/18
84/91=12/13
75/45=25/15=5/3
125/90=25/18
84/91=12/13
75/45=25/15=5/3
6/7=18/21=54/63=104/126
125/90 = 25/18
84/91 = 12/13
75/45 = 25/15 = 5/3
6/7 = 18/21 = 54/63 = 108/126
98775 - 32 x 85 / 67500 - 24 x 236 / 568 + 101598 : 287 / 6875 + 980 -180 \(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}\) / \(\dfrac{8}{11}+\dfrac{8}{33}\) x \(\dfrac{3}{4}\) / 7/9 x 3/14 :5/8 / \(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}\)
ÉT O ÉT
98775 - 32 x 85
=98775 -2720
=96055
67500 - 24 x 236
= 67500 -5664
=61836
568 + 101598 : 287
= 568 +354
=922
6875 + 980 -180
=7855 -180
=7675
\(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}\)
\(=\dfrac{7}{10}-\dfrac{1}{2}\)
= \(\dfrac{1}{5}\)
\(\dfrac{8}{11}+\dfrac{8}{33}x\dfrac{3}{4}\)
\(=\dfrac{8}{11}+\dfrac{2}{11}\)
\(=\dfrac{10}{11}\)
\(\dfrac{7}{9}x\dfrac{3}{14}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}x\dfrac{8}{5}\)
\(=\dfrac{8}{30}\)
\(=\dfrac{4}{15}\)
\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}\)
\(=\dfrac{5}{12}-\dfrac{7}{32}x\dfrac{16}{21}\)
\(=\dfrac{5}{12}-\dfrac{1}{6}\)
\(=\dfrac{5}{12}-\dfrac{2}{12}\)
\(=\dfrac{3}{12}=\dfrac{1}{4}\)
\(\dfrac{7}{5}X\dfrac{2}{5}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}X\dfrac{1}{2}\)
35864:175
247x328
ÉT O ÉT
247 X 328 = 81016
35864:175= 35864/175
\(\dfrac{7}{5}x\dfrac{2}{5}=\dfrac{14}{25}\)
\(\dfrac{3}{4}+\dfrac{5}{4}:\dfrac{1}{4}x\dfrac{1}{2}=\dfrac{3}{4}+5x\dfrac{1}{2}=\dfrac{5}{2}\)
7/5 x 2/5 = 14/25
3/4 + 5/4 : 1/4 x 1/2 = 13/4
Tìm 1 phân số \(\dfrac{x}{y}\) sao cho: \(\dfrac{7}{9}\)<\(\dfrac{x}{y}\)<\(\dfrac{7}{8}\) giải thích hộ mik luôn nha!
ét o ét
\(\dfrac{7}{9}< \dfrac{x}{y}< \dfrac{7}{8}\)
\(\dfrac{56}{72}< \dfrac{x}{y}< \dfrac{63}{72}\)
\(\dfrac{x}{y}=\left\{\dfrac{57}{72};\dfrac{58}{72};\dfrac{59}{72};\dfrac{60}{72};\dfrac{61}{72};\dfrac{62}{72}\right\}\)
a)\(\dfrac{7}{-25}+\dfrac{-8}{25}\)
ét o ét
b)\(\dfrac{-18}{24}-\dfrac{15}{21}\)
a: =-7/25-8/25=-15/25=-3/5
b: =-3/4-5/7=-21/28-20/28=-41/28
\(\dfrac{12}{7}+\dfrac{8}{22}\)
Ét o ét
\(\dfrac{12}{7}+\dfrac{8}{22}=\dfrac{12}{7}+\dfrac{4}{11}=\dfrac{132}{77}+\dfrac{28}{77}=\dfrac{160}{77}\)
\(\dfrac{12}{7}+\dfrac{8}{22}=\dfrac{264}{154}+\dfrac{56}{154}=\dfrac{220}{154}\)
a) tìm x :\(\dfrac{2}{1.4}x+\dfrac{2}{4.7}x+\dfrac{2}{7.10}x+....+\dfrac{2}{31.344}x=10\)
b)so sánh hai phân số sau : A=\(\dfrac{6^{2020}+1}{6^{2021}+1}\)và B=\(\dfrac{6^{\text{2021}}+1}{\text{6}^{\text{2022}}+1}\)
ét o ét giúp với ạ
so sánh các hỗn số sau:
\(7\dfrac{4}{5}\) và \(9\dfrac{1}{2}\)
\(7\dfrac{1}{6}\) và \(3\dfrac{4}{5}\)
\(9\dfrac{9}{1}\) và \(5\dfrac{8}{6}\)
\(7\dfrac{4}{5}và9\dfrac{1}{2}\\ Tacó:7< 9\\ \Rightarrow7\dfrac{4}{5}< 9\dfrac{1}{2}\\ 7\dfrac{1}{6}và3\dfrac{4}{5}\\ Tacó:7>3\\ \Rightarrow7\dfrac{1}{6}>3\dfrac{4}{5}\)
Câu cuối không phải hỗn số
Bài 4: So sánh:
a. \(\dfrac{2}{3}\)và\(\dfrac{1}{4}\)
b. \(\dfrac{7}{10}\)và\(\dfrac{7}{8}\)
c. \(\dfrac{6}{7}\)và\(\dfrac{3}{5}\)
d. \(\dfrac{14}{21}\)và\(\dfrac{60}{72}\)
\(a:ta.c\text{ó}:BCNN:12\\ \dfrac{2}{3}=\dfrac{2\cdot4}{3\cdot4}=\dfrac{8}{12};\dfrac{1}{4}=\dfrac{1\cdot3}{4\cdot3}=\dfrac{3}{12}\\ v\text{ì }\dfrac{8}{12}< \dfrac{3}{12}n\text{ê}n\dfrac{2}{3}< \dfrac{1}{4}\\ b:ta.c\text{ó}:\\ 10=2\cdot5\\ 8=2^3\\ \Rightarrow BCNN=2^3\cdot5=8\cdot5=40\\ \dfrac{7}{10}=\dfrac{7\cdot4}{10\cdot4}=\dfrac{28}{40};\dfrac{7}{8}=\dfrac{7\cdot5}{8\cdot5}=\dfrac{35}{40}\\ v\text{ì }\dfrac{28}{40}< \dfrac{35}{40}n\text{ê}n\dfrac{7}{10}< \dfrac{7}{8}\\ c:ta.c\text{ó}:\\ 7=7;5=5\\ \Rightarrow BCNN=7\cdot5=35\\ \dfrac{6}{7}=\dfrac{6\cdot5}{7\cdot5}=\dfrac{30}{35};\dfrac{3}{5}=\dfrac{3\cdot7}{5\cdot7}=\dfrac{21}{35}\\ v\text{ì }\dfrac{30}{35}>\dfrac{21}{35}n\text{ê}n\dfrac{6}{7}>\dfrac{3}{5}\\ d:ta.c\text{ó}:\\ 21=3\cdot7\\ 72=2^3\cdot3^2\\ \Rightarrow BCNN=2^3\cdot3^2\cdot7=504\\ \dfrac{14}{21}=\dfrac{14\cdot24}{21\cdot24}=\dfrac{336}{504};\dfrac{60}{72}=\dfrac{60\cdot7}{72\cdot7}=\dfrac{420}{504}\\ v\text{ì }\dfrac{336}{504}< \dfrac{420}{504}n\text{ê}n\dfrac{14}{21}< \dfrac{60}{72}\)