5 + 5 - 5 + 4
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4 5. 4. 6.
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15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5...
Đọc tiếp
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
4 5. 4. 6.
--- + --- --- + ---
15 6. 5. 7
3. 4. 2. 5
--- + --- --- + ---
5. 20. 5. 12
Khoanh vào phân số lớn hơn 1_3
5+5+5+5+5+5+5+5+5+4+4+4+5=
(5.10)+(4.3)
=50+12
=62
( 5 x 10) + (4x3)
=50+12
=62
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27 tháng 3 2022 lúc 8:28
Tìm x biết \(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^4}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}\)=2\(2^x\)
Sửa đề: 3^5+3^5+3^5; 2^x
=>\(2^x=\dfrac{4^5\cdot4}{3^5\cdot3}\cdot\dfrac{6^5\cdot6}{2^5\cdot2}\)
=>\(2^x=\left(\dfrac{4}{3}\right)^6\cdot\left(\dfrac{6}{2}\right)^6=4^6=2^{12}\)
=>x=12
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>, < , = ?
| 5 – 2 … 4 | 5 – 4 … 2 | 4 + 1 … 5 |
| 5 – 2 …. 3 | 5 – 3 … 1 | 5 – 1 … 5 |
| 5 – 2 … 2 | 5 – 1 …. 4 | 5 – 4 … 0 |
Lời giải chi tiết:
| 5 – 2 < 4 | 5 – 4 < 2 | 4 + 1 = 5 |
| 5 – 2 = 3 | 5 – 3 > 1 | 5 – 1 < 5 |
| 5 – 2 > 2 | 5 – 1 = 4 | 5 – 4 > 0 |
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5-2<4 5-4<2 4+1=5
5-2=3 5-3>1 5-1<5
5-2>2 5-1=4 5-4>0
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4^5+4^5+4^5+4^5/3^5+3^5+3^5.6^5+6^5+6^5+6^5+6^5+6^5/2^5+2^5=8^x Tìm x
Tìm số tự nhiên n, biết rằng:
\(\dfrac {4^{5} + {4^{5}} +{4^{5}} + {4^{5}}}{{3^{5}} + {3^{5}} + {3^{5}}}\) . \(\dfrac{6^{5} + {6^{5}} + {6^{5}} + {6^{5}} + {6^{5}} + {6^{5}} }{2^{5} + 2^{5}} = 2^{n}\)
\(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n\)
\(\Rightarrow\dfrac{4^5.4}{3^5.3}.\dfrac{6^5.6}{2^5.2}=2^n\)
\(\Rightarrow\dfrac{4^5.4.6^5.6}{3^5.3.2^5.2}=2^n\)
\(\Rightarrow\dfrac{\left(2.2\right)^5.2.2.\left(3.2\right)^5.3.2}{3^5.3.2^5.2}=2^n\)
\(\Rightarrow\dfrac{2^5.2^5.2.2.3^5.2^5.3.2}{3^5.3.2^5.2}=2^n\)
Rút gọn vế trái ta có :
\(2^5.2.2.^5=2^n\)
\(\Rightarrow2^{12}=2^n\)
\(\Rightarrow n=12\) ( Thỏa mãn điều kiện \(n\in N\) )
Vậy n =12
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Số tự nhiên n thỏa mãn:
\(\dfrac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\dfrac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n\)
=>\(\dfrac{4^5\left(1+1+1+1\right)}{3^5\left(1+1+1\right)}.\dfrac{6^5\left(1+1+1+1+1+1\right)}{2^5\left(1+1\right)}=2^n\)
=>\(\dfrac{4^5.4}{3^5.3}.\dfrac{6^5.6}{2^5.2}=2^n\) =>\(\dfrac{4^6}{3^6}.\dfrac{6^6}{2^6}=2^n\)
=>\(\left(\dfrac{4.6}{3.2}\right)^6=2^n\) =>\(4^6=2^n\) =>\(2^{12}=2^n\) =>n=12.
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Viết số thích hợp vào chỗ chấm:
4×6=… 4×4=…5×4=…5×8=…
2×4=…4×7=…5×6=…5×2=…
4×9=…4×8=…5×7=…5×3=…
3×4=…4×10=…5×10=…5×9=…
4 × 6 = 24 4 × 4 = 16 5 × 4 = 20 5 × 8 = 40 |
2 × 4 = 8 4 × 7 = 28 5 × 6 = 30 5 × 2 = 10 |
4 × 9 = 36 4 × 8 = 32 5 × 7 = 35 5 × 3 = 15 |
3 × 4 = 12 4 × 10 = 40 5 × 10 = 50 5 × 9 = 45 |
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4 x 6 = 24 4 x 4 = 16 5 x 4 = 20 5 x 8 = 40
2 x 4 = 8 4 x 7 = 28 5 x 6 = 30 5 x 2 = 10
4 x 9 = 36 4 x 8 = 32 5 x 7 = 35 5 x 3 = 15
3 x 4 = 12 4 x 10 = 40 5 x 10 = 50 5 x 9 = 45
dfrac{1}{3}+dfrac{2}{3}dfrac{4}{5}+dfrac{5}{6}dfrac{4}{5}-dfrac{3}{5}dfrac{9}{8}-dfrac{4}{2}dfrac{8}{5}xdfrac{5}{8}dfrac{6}{7}xdfrac{4}{7}dfrac{4}{5}:dfrac{4}{5}dfrac{5}{5}:dfrac{5}{5}a,
Đọc tiếp
\(\dfrac{1}{3}+\dfrac{2}{3}=\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\)
\(\dfrac{9}{8}-\dfrac{4}{2}=\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\)
a,
\(\dfrac{1}{3}+\dfrac{2}{3}=\dfrac{3}{3}=1\)
\(\dfrac{4}{5}+\dfrac{5}{6}=\dfrac{24}{30}+\dfrac{25}{30}=\dfrac{49}{30}\)
\(\dfrac{4}{5}-\dfrac{3}{5}=\dfrac{1}{5}\)
\(\dfrac{8}{5}x\dfrac{5}{8}=\dfrac{1}{1}=1\)
\(\dfrac{6}{7}x\dfrac{4}{7}=\dfrac{24}{49}\)
\(\dfrac{4}{5}:\dfrac{4}{5}=\dfrac{4}{5}x\dfrac{5}{4}=\dfrac{1}{1}=1\)
\(\dfrac{5}{5}:\dfrac{5}{5}=\dfrac{5}{5}x\dfrac{5}{5}=\dfrac{1}{1}=1\)
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1) \(\dfrac{1}{3}+\dfrac{2}{3}=\dfrac{1+2}{3}=\dfrac{3}{3}=1\)
2) \(\dfrac{4}{5}+\dfrac{5}{6}=\dfrac{24}{30}+\dfrac{25}{30}=\dfrac{24+25}{30}=\dfrac{49}{30}\)
3) \(\dfrac{4}{5}-\dfrac{3}{5}=\dfrac{4-3}{5}=\dfrac{1}{5}\)
4) \(\dfrac{9}{8}-\dfrac{4}{2}=\dfrac{9}{8}-2=\dfrac{9}{8}-\dfrac{16}{8}=-\dfrac{7}{8}\)
5) \(\dfrac{8}{5}\times\dfrac{5}{8}=\dfrac{8\times5}{5\times8}=\dfrac{40}{40}=1\)
6) \(\dfrac{6}{7}\times\dfrac{4}{7}=\dfrac{6\times4}{7}=\dfrac{24}{7}\)
7) \(\dfrac{4}{5}:\dfrac{4}{5}=\dfrac{4}{5}\times\dfrac{5}{4}=\dfrac{4\times5}{5\times4}=\dfrac{20}{20}=1\)
8) \(\dfrac{5}{5}:\dfrac{5}{5}=\dfrac{5}{5}\times\dfrac{5}{5}=\dfrac{5\times5}{5\times5}=\dfrac{25}{25}=1\)
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2 ^ 15 : 2 ^ 13 + 3 ^ 2. 2 ^ 3 - 5 ^ 2 - 2 ^ 0
81 . ( 27 + 9 ^ 15) : (3 ^ 5 + 3 ^ 32)
(4 ^ 42 .123 - 23 . 4 ^ 42) : (4 ^ 15 . 4 ^ 27)
(15 . 3 ^ 7 - 3 ^ 8) : (4 . 9 ^ 4)
(100 . 5 ^ 7 + 5 ^ 11 : 25 ) : ( 5 . 5 ^ 13 : 25 ^ 2)
( 2 ^ 5 . 3 ^ 6 . 5 ^ 7 + 2 ^ 6 . 3 ^ 7 . 5 ^ 8 ) : ( 2 ^ 4 . 3 ^ 5 . 5 ^ 6)
(4 ^ 5 . 10 . 5 ^ 6 + 2 ^ 8 . 25 ^ 5) : ( 2 ^ 8 . 5 ^ 4 + 5 ^ 4 + 5 ^ 7 . 2 ^ 5)
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