x*(x-3)^2-16+32=2*(x-3)^2
Đúng ghi Đ, sai ghi S:
a) 32 : 4 : 2 = 8 : 2 = 4
32 : 4 : 2 = 32 : 2 = 16
b) 18 : 2 x 3 = 18 : 6 = 3
18 : 2 x 3 = 9 x 3 = 18
a) 32 : 4 : 2 = 8 : 2 = 4
32 : 4 : 2 = 32 : 2 = 16
b) 18 : 2 x 3 = 18 : 6 = 3
18 : 2 x 3 = 9 x 3 = 18
Tinh gia tri cua phan so: A= 2 x 3 + 2 x 4 x 8 + 4 x 8 x 16 + 8 x 16 x 32/ 3x 4 + 2 x 6 x 8 + 4 x 12 x 16 + 8 x 24 x 32
tìm x:
x*(x-3)^2-16+32=2*(x-3)^2
3.x + 5/16 + 2.x + 7/8=4+3.x/32 + 2.x
Ta có: \(\dfrac{3x+5}{16}+\dfrac{2x+7}{8}=\dfrac{4+3x}{32}+2x\)
\(\Leftrightarrow\dfrac{2\left(3x+5\right)}{32}+\dfrac{4\left(2x+7\right)}{32}=\dfrac{4+3x}{32}+\dfrac{64x}{32}\)
Suy ra: \(6x+10+8x+28=4+3x+64x\)
\(\Leftrightarrow67x+4-14x-38=0\)
\(\Leftrightarrow53x=34\)
hay \(x=\dfrac{34}{53}\)
96/x^2-16+7+x/4-x=2x-1/x+4-3
2/x-1 +3/x-2 =3/x-3
1/x+1+5-x/x-2=3/x^2-x-2-1
a: \(\dfrac{96}{\left(x-4\right)\left(x+4\right)}+\dfrac{7+x}{4-x}=\dfrac{2x-1}{x+4}-3\)
\(\Leftrightarrow\dfrac{96}{\left(x-4\right)\left(x+4\right)}-\dfrac{\left(x+7\right)\left(x+4\right)}{\left(x-4\right)\left(x+4\right)}=\dfrac{\left(2x-1\right)\left(x-4\right)}{\left(x+4\right)\left(x-4\right)}-\dfrac{3\left(x-4\right)\left(x+4\right)}{\left(x-4\right)\left(x+4\right)}\)
Suy ra: \(96-x^2-11x-28=2x^2-9x+4-3\left(x^2-16\right)\)
\(\Leftrightarrow-x^2-11x+68=2x^2-9x+4-3x^2+48\)
\(\Leftrightarrow-x^2-11x+68=-x^2-9x+52\)
=>-11x+68=-9x+52
=>-2x=-16
hay x=8(nhận)
b: \(\dfrac{2}{x-1}+\dfrac{3}{x-2}=\dfrac{3}{x-3}\)
\(\Leftrightarrow2\left(x-2\right)\left(x-3\right)+3\left(x-1\right)\left(x-3\right)=3\left(x-1\right)\left(x-2\right)\)
\(\Leftrightarrow2\left(x^2-5x+6\right)+3\left(x^2-4x+3\right)=3\left(x^2-3x+2\right)\)
\(\Leftrightarrow2x^2-10x+12+3x^2-12x+9=3x^2-9x+6\)
\(\Leftrightarrow5x^2-22x+21-3x^2+9x-6=0\)
\(\Leftrightarrow2x^2-13x+15=0\)
\(\Leftrightarrow2x^2-10x-3x+15=0\)
=>(x-5)(2x-3)=0
=>x=5(nhận) hoặc x=3/2(nhận)
3+x/7+y=3/7 và x+y=20
A=2*4+2*4*8+4*8*16+8*16*32/3*4+2*6*8+4*12*16+8*24*32
Bài 1: a) ( 4,45 - 2,2 ) x 8 : 0,3 / ( 0, 823 + 0,177 ) x 240
b) 247/ 12,49 x 1/2 + 247/ 12,47 x 1/6 + 247 / 12,49 x 1/3
Bài 2:
1) X - 32 : 16 = 48
2:( X - 32 ) : 16 = 48
3: 150 - 2 x ( X - 10) = 120
vậy làm cho mk phần b bài 1 va phần 3 bài 2 nhé
1) Tìm x, biết:
a) 3 + |-x| = |-7|
b) -3 + |1 - x| = |-2|
c) 5 + |-1 + x| = -|2|
d) -|3| + |2x| = |-3|
e) 1 + |-x + 2| = -|7|
g) -32 + |x - 16| = |12|
h) |-32| - |x - 16| = |-12|
i) -|32| - |16 - x| = |-32|
2) Tìm x, biết:
a) |x| < 10
b) |x| > 0
c) |x| < -1
3) Tính tổng các số nguyên sau:
a) -9 < x < 9
b) -10 < x \(\le\)10
c) -9 < x < 10
1 a x=4
b x=-4
c x=-7
d x=3
e x=10
g x=60
h x=36
i x=16
2a 1,2,3,4,5,6,7,8,9
b 1,2,3,4,5,6,7,8,9.........
c rỗng
3a 0
b 0
c10
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BÀI 4 . TÌM x
1 . X + 5 . 2 - { 32 + 16 . 3 : 6 } = 0
2 . { X -1 }^ 5 = 32
3 . { 2X - 3 }^ 2 = 25