\(A=\frac{12\cdot10101}{13\cdot10101}+\frac{14\cdot11011}{13\cdot11011}-\left(\frac{21\cdot101}{23\cdot101}+\frac{25\cdot11011}{23\cdot11011}\right)\)

\(A=\frac{12}{13}+\frac{14}{13}-\left(\frac{21}{23}+\frac{25}{23}\right)\)

\(A=0\)

nhớ cho đúng nha

\(A=\frac{121212}{131313}+\frac{154154}{143143}-\left(\frac{2121}{2323}+\frac{275275}{253253}\right)\)

\(\Leftrightarrow A=\frac{12}{13}-\frac{14}{13}-\left(\frac{21}{23}+\frac{25}{23}\right)\) (Áp dụng phương pháp rút gọn phân số)

\(\Leftrightarrow A=\frac{12}{13}-\frac{14}{13}-\frac{46}{23}=\frac{\left(-2\right)}{13}-\frac{46}{23}\)

\(\Leftrightarrow A=-\frac{28}{13}\)

7.15 : 0.5 + 7.15 x 9 - 7.15

= 14.3 + 7.15 x ( 9 - 1 )

= 14.3 + 7.15 x 8

= 14.3 +  57.2

= 71.5

7,15 :( 0,5+9 -1 ) 

7,15 : 0,5 + 7,15 x 9 -7,15

= 7,15 x 2 +7,15 x 9 - 7,15 x 1

= 7,15 x (2+9-1)

=7,15 x 10

= 71,5

hoa mắt quá, mk đang tính

kết quả = 1/13 đúng ko bn, k mk nha ( nếu đúng )

\(\frac{12x101x13x10101}{13x101x12x10101}=\frac{12x10101x13x101}{12x10101x13x101}=\frac{121212x1313}{121212x1313}=1.\)

1212 x 131313 =159151356

1313 x 121212 = 159151356

12,12 x 7,5 + 12,12 : 2 + 12,12 + 12,12

= 12,12 x 7,5 + 12,12 x 0,5 + 12,12 x 1 + 12,12 x 1

= 12,12 x (7,5 + 0,5 + 1 + 1)

= 12,12 x 10

= 121,2

121,2 nha bạn

File: undefined 

giúp mình với

   999 x 4,26 - 333 x 2,78

= 333 x 2 x 4,26 - 333 x 2,78

= 333 x ( 2 x 4,26 - 2,78 )

= 333 x 5,74

= 1911,42

   999x4,26-333x2,78

=333x3x4,26-333x2,78

=333x12,78-333x2,78

=333x(12,78-2,78)

=333x10

=3330

\(\dfrac{42}{46}+\dfrac{250}{186}+\dfrac{-2121}{2323}+\dfrac{-125125}{143143}\)

\(=\dfrac{21}{23}+\dfrac{125}{143}+\left(\dfrac{-21}{23}\right)+\left(\dfrac{-125}{143}\right)\)

\(=\dfrac{21}{23}+\dfrac{125}{143}-\dfrac{21}{23}-\dfrac{125}{143}\)

\(=0\)

\(\dfrac{42}{46}+\dfrac{250}{186}+\dfrac{-2121}{2323}+\dfrac{-125125}{143143}\)

\(=\dfrac{21}{23}+\dfrac{125}{93}+\dfrac{-21}{23}+\dfrac{-125}{143}\)

\(=125\left(\dfrac{1}{93}-\dfrac{1}{143}\right)\)

\(=\dfrac{6250}{13299}\)

   \(\dfrac{121212}{242424}+\dfrac{1313}{2626}+\dfrac{20212021}{40424042}\)

= \(\dfrac{12}{24}+\dfrac{13}{26}+\dfrac{2021}{4042}\)

= \(\dfrac{1}{2}+\dfrac{1}{2}+\dfrac{1}{2}\)

= \(\dfrac{3}{2}\)

121212/242424+1313/2626+20212021/404244024

= 1/2+1/2+1/2 

=3/2

121212/242424 + 1313/2626 + 20212021/40424042

= 1/2 + 1/2 + 1/2

= 3/2