Tìm x
a,541+(218-x)=735
b,96-3(x+2)=42
c,(x-36):18=12
Tìm x thuộc N biết :
A).541+(218-x)=735
B).3636:(12x-91)=36
C).96-3(x+1)=42
D).(x-36):18=12
tìm x thuộc N biết :
(x-5) (x-7)=0
541+(218-x)=735
96-3(x+1)=42
(x-47)-115=0
(x-36):18=12
(x-5)(x-7)=0
=> x-5=0 hoặc x-7=0
=> x=5 hoặc x=7
541+(218-x)=735
=> 218-x=735-541
=> 218-x=194
=> x=218-194
=> x=24
96-3(x+1)=42
=>3(x+1)=96-42
=>3(x+1)=54
=>x+1=54:3
=>x+1=18
=>x=18-1
=>x=17
(x-47)-115=0
=>x-47=0+115
=>x-47=115
=>x=115+47
=>x=162
(x-36):18=12
=>x-36=12.18
=>x-36=216
=>x=216+36
=>x=252
(x-5).(x-7)=0
x-5=0+7
x=7+5
x=12
541+(218-x)=735
218-x=735-541
x=218-196
x=12
96-3(x+1)=42
3(x+1)=96-42
x+1=54:3
x=17-1
x=16
(x-47)-115=0
x-47=0+115
x=115+47
x=162
(x-36):12=18
x-36=12*18
x-36=216
x=216+36
x=252
X=252 nha bạn Anh Anh nhớ tk mình và kb nha
tìm x e N biết
a)541+(218-x)=735
b)96-3.(x+1)=42
c)(x-36):18=12
d)3x + 3x+1 +3x+2 =13.81
a, 541 + ( 218 - x ) = 735
=> 218 - x = 735 - 541
=> 218 - x = 194
=> x = 218 - 194
=> x = 24
Vậy x = 24
b, 96 - 3.( x + 1 ) = 42
=> 3.( x + 1 ) = 96 - 42
=> 3.( x + 1 ) = 54
=> x + 1 = 54 : 3
=> x + 1 = 18
=> x = 18 - 1
=> x = 17
Vậy x = 17
c, ( x - 36 ) : 18 = 12
=> x - 36 = 12.18
=> x - 36 = 216
=> x = 216 + 36
=> x = 252
Vậy x = 252
d, 3x + 3x+1 + 3x+2 = 13.81
=> 3x.1 + 3x.3 + 3x.32= 13.81
=> 3x.( 1 + 3 + 32 ) = 13.81
=> 3x.( 1 + 3 + 9 ) = 13.81
=> 3x.13 = 13.81
=> 3x= 13.81:13
=> 3x= 81
=> 3x = 34
=> x = 4
Vậy x = 4
a/541+(218-x)=735
b/96-3(x+1)=42
c/(x-47)-115=0
d/(x-36):18=12
e/2^x=16
f/x^50=x
g/2^x.4=128
h/x^15=x
i/(2^x+1)^3=125
B1:Tính
a,3.52-16:22
b,22.17-23.14
c,15.141+59.10
d,17.85+15.17-120
e,100-[75-(7-2)]2
g,(23.94+93.45):(92.10-92)
B2:Tìm x
a,420+65.4=(x+175):3+30
b,96-3.(x+1)=42
c,(x-47)-115=0
d,(x-36):18=12
e,2x=16
B3:Tìm x
a,60-3.(x-2)=51
b,4x-20=25:22
c,8.6+288:(x-3)2=50
mk đang càn rất gấp
Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
Bài 1: Viết các kết quả sau dưới dạng 1 lũy thừa
a) 125^4 :25^3
b) 4^14. 5^28
c) 12^n : 2^2n
Bài 2: Tìm x; biết
a) 541+ (218-x)=735
b) 96-3.(x+1)=42
c) (x-47) -115=0
d) (x-36) :18=12
e) 2^x=16
x^50=x
a) 1254:253= (53)3: (52)3=59:56=53
b) 414:528=414: 52.14=414:(52)14= 414:2514
c) 12n:22n=
Tìm x, biết
A)128-3.(x+4)=23. B)[6x+28).3+55]:5=35. C)(x-5).(x-7)=0. D)541+(218-x)=735. E)96-3(x+1)=42. G)(x-47)-115=0.
H)(x-36):18=12
96 - 3 (x+1)= 42
6x - 39 = 603
541+ ( 218-x)= 735
5 ( x+ 35)= 515
12x - 33= 32. 33
( x - 36) : 18= 12
Tìm x thuộc N biết
a. => 3(x+1)=96-42=54
=> x+1=54:3=18
=> x=18-1=17
b. => 6x=603+39=642
=> x=642:6=107
c. => 218-x=735-541=194
=> x=218-194=24
d => x+35=515:5=103
=> x=103-35=68
e. =>12x=35+33=276
=> x=276:12=23
f. => x-36=12.18=216
=> x=216+36=252
541+(218-x)=735
96-3.(x+1)=42
541 + ( 218 - x ) = 735
=> 541 + 218 - x = 735
=> x = 541 + 218 - 735
=> x = 24
96 - 3 . ( x + 1 ) = 42
=> 3 . ( x + 1 ) = 96 - 42
=> 3 . ( x + 1 ) = 54
=> x + 1 = 54 : 3
=> x + 1 = 18
=> x = 18 - 1
=> x = 17
541+(218-x)=735
218-x = 735-541
218-x = 194
x=218-194=24
96-3.(x+1)=42
3.(x+1)=96-42
3.(x+1)=54
x+1=54:3=18
x=18-1=17
541+(218-x)=735
218-x=735-541
218-x=194
x=218-194
x=24
96-3.(x+1)=42
3.(x+1)=96-42
3.(x+1)=54
x+1=54:3
x+1=18
x=18-1
x=17