Tính:
\(\dfrac{32}{13}:\dfrac{8}{25}\)
Bài 1: Thực hiện phép tính sau:
\(a,\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(b,\dfrac{5}{-8}+\dfrac{14}{25}-\dfrac{6}{10}\)
a) 9/18 - (-7/12) + 13/32
= 13/12 + 13/32
= 143/96
b) (5/-8) + 14/25 - 6/10
= (-13/200) - 6/10
= -133/200
Chúc bạn học tốt!! ^^
a: \(\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}+\dfrac{13}{32}\)
\(=\dfrac{48}{96}+\dfrac{56}{96}+\dfrac{39}{96}\)
\(=\dfrac{143}{96}\)
b: \(\dfrac{-5}{8}+\dfrac{14}{25}-\dfrac{6}{10}\)
\(=\dfrac{-125}{200}+\dfrac{112}{200}-\dfrac{120}{200}\)
\(=\dfrac{-133}{200}\)
Bài 1:
1/\(\left(-\dfrac{25}{13}\right)+\left(-\dfrac{19}{17}\right)+\dfrac{12}{13}+\left(-\dfrac{25}{17}\right)\) 6/ \(2\dfrac{2}{15}.\dfrac{9}{17}.\dfrac{3}{32}:\left(-\dfrac{3}{17}\right)\)
2/\(\dfrac{1}{2}-\left(-\dfrac{1}{3}\right)+\dfrac{1}{23}+\dfrac{1}{6}\) 7/\(\left(\dfrac{-3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)
3/\(\left(-\dfrac{3}{7}\right).\dfrac{5}{11}+\left(-\dfrac{5}{14}\right).\dfrac{5}{11}\) 8/\(\left(-\dfrac{1}{3}\right).\left(-\dfrac{15}{19}\right).\dfrac{38}{45}\)
4/\(\left(-\dfrac{5}{11}\right).\dfrac{7}{15}.\dfrac{11}{-5}.\left(-30\right)\) 9/\(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+......+\dfrac{1}{19.20}\)
5/\(\left(-\dfrac{5}{9}\right).\dfrac{3}{11}+\left(-\dfrac{13}{18}\right).\dfrac{3}{11}\) 10/\(\dfrac{1}{9.10}-\dfrac{1}{8.9}-\dfrac{1}{7.8}-......-\dfrac{1}{2.3}-\dfrac{1}{1.2}\)
Bài 1:Thực hiện phép tính (tính hợp lý nếu có thể)
1) \(\dfrac{8}{31}\) +\(\dfrac{-12}{25}\) +\(\dfrac{23}{31}\) +\(\dfrac{-13}{25}\)
2) \(\dfrac{1}{2}\) + \(\dfrac{3}{4}\) - ( \(\dfrac{3}{4}\) - \(\dfrac{4}{5}\) )
3) \(\dfrac{7}{3}\) . \(\dfrac{-5}{2}\) . \(\dfrac{15}{21}\) .\(\dfrac{4}{-5}\)
4)\(\dfrac{1}{4}\) + \(\dfrac{3}{4}\) : ( \(-\dfrac{6}{7}\) )
5) (\(\dfrac{3}{29}\) - \(\dfrac{1}{5}\) ) . \(\dfrac{29}{3}\)
6) \(\dfrac{5}{7}\) . \(\dfrac{5}{11}\) + \(\dfrac{5}{7}\) . \(\dfrac{2}{11}\) - \(\dfrac{5}{7}\) .\(\dfrac{14}{11}\)
7)\(\dfrac{-11}{12}\) . \(\dfrac{1}{8}\) + \(\dfrac{11}{12}\) .\(\dfrac{-3}{16}\) -\(\dfrac{11}{12}\)
8) \(\dfrac{7}{4}\) . \(\dfrac{29}{5}\) -\(\dfrac{7}{9}\) .\(\dfrac{9}{4}\) +\(3\dfrac{2}{13}\)
giúp em
1) = (8/31 + 23/31)+ ( -12/25+-13/25) = 1 + (-1) = 0
2) = 1/2 +3/4 -3/4 + 4/5 = 1/2 +4/5 = 13/10
3)= ( 7/3 x 15/21) x ( -5/2 x 4/-5 ) = ( 7/3 x 5/7 ) x 2 = 5/3 x 2 = 10/3
4) = 1/4 + 3/4 x -7/6 = 1/4 + -7/8 = -5/8
5)= 3/29 x 29/3 - 1/5 x 29/3 = 1 x 29/15 = 29/15
6)= 5/7 x ( 5/11 + 2/11 - 14/11) = 5/7 x -7/11 = -5 /11
7) = 11/12 x -1/8 + 11/12 x -3/16 - 11/12 = 11/12 x ( -1/8 + -3/16 - 1) = 11/12 x -21/16 = -77/64 ( mk ko chắc , bạn ấn máy tính để thử lại )
8) = 203/20 - 7/4 + 41/13 = 198/20 + 41/13 = 99/10 + 41/13 = 1697/130 ( câu này cứ lỏ lỏ kiểu gì ý :v )
1) = (8/31 + 23/31)+ ( -12/25+-13/25) = 1 + (-1) = 0
2) = 1/2 +3/4 -3/4 + 4/5 = 1/2 +4/5 = 13/10
3)= ( 7/3 x 15/21) x ( -5/2 x 4/-5 ) = ( 7/3 x 5/7 ) x 2 = 5/3 x 2 = 10/3
4) = 1/4 + 3/4 x -7/6 = 1/4 + -7/8 = -5/8
5)= 3/29 x 29/3 - 1/5 x 29/3 = 1 x 29/15 = 29/15
6)= 5/7 x ( 5/11 + 2/11 - 14/11) = 5/7 x -7/11 = -5 /11
7) = 11/12 x -1/8 + 11/12 x -3/16 - 11/12 = 11/12 x ( -1/8 + -3/16 - 1) = 11/12 x -21/16 = -77/64 ( mk ko chắc , bạn ấn máy tính để thử lại )
8) = 203/20 - 7/4 + 41/13 = 198/20 + 41/13 = 99/10 + 41/13 = 1697/130 ( câu này cứ lỏ lỏ kiểu gì ý :v )
BT2: Tính nhanh:
3) \(\dfrac{-41}{32}\left(\dfrac{15}{8}-\dfrac{16}{41}\right)+\dfrac{15}{8}\left(\dfrac{41}{32}-\dfrac{8}{3}\right)\)
4) \(\dfrac{13}{29}\left(\dfrac{29}{5}-\dfrac{45}{8}\right)-\dfrac{45}{8}\left(\dfrac{9}{8}-\dfrac{13}{29}\right)\)
3)\(\dfrac{-41}{32}\left(\dfrac{15}{8}-\dfrac{16}{41}\right)+\dfrac{15}{8}\left(\dfrac{41}{32}-\dfrac{8}{3}\right)\)
=\(\dfrac{-41}{32}.\dfrac{15}{8}-\dfrac{-41}{32}.\dfrac{16}{41}+\dfrac{15}{8}.\dfrac{41}{32}-\dfrac{15}{8}.\dfrac{8}{3}\)
=\(\left(\dfrac{-41}{32}.\dfrac{15}{8}+\dfrac{15}{8}.\dfrac{41}{32}\right)+\dfrac{-16}{41}.\dfrac{-41}{32}-\dfrac{15}{8}.\dfrac{8}{3}\)
=\(0+\dfrac{1}{2}-5=\dfrac{-9}{2}\)
4)\(\dfrac{13}{29}\left(\dfrac{29}{5}-\dfrac{45}{8}\right)-\dfrac{45}{8}\left(\dfrac{9}{8}-\dfrac{13}{29}\right)\)
=\(\dfrac{13}{29}.\dfrac{29}{5}-\dfrac{45}{8}.\dfrac{13}{29}-\dfrac{45}{8}.\dfrac{9}{8}-\dfrac{45}{8}.\dfrac{13}{29}\)
=\(\left(\dfrac{45}{8}.\dfrac{13}{29}-\dfrac{45}{8}.\dfrac{13}{29}\right)-\dfrac{13}{29}.\dfrac{29}{5}-\dfrac{45}{8}.\dfrac{9}{8}\)
=\(0-\dfrac{13}{5}-\dfrac{405}{64}=\dfrac{-2857}{320}\)
a)\(\dfrac{2}{7}+\dfrac{-3}{8}+\dfrac{11}{7}+\dfrac{1}{3}+\dfrac{1}{7}+\dfrac{5}{-8}\)
b)\(\dfrac{-3}{8}+\dfrac{13}{25}+\dfrac{5}{-8}+\dfrac{2}{-5}+\dfrac{13}{25}\)
CÂU: 20
Các phân số tối giản là:
A. \(\dfrac{21}{23};\dfrac{32}{14}\) B. \(\dfrac{32}{14};\dfrac{9}{8}\) C. \(\dfrac{21}{23};\dfrac{9}{8}\)
BÀI 5: PHÂN SỐ \(\dfrac{9}{15};\dfrac{14}{13};\dfrac{11}{15};\dfrac{15}{15}\) . sắp xếp theo thứ tự lớn dần:................................... ( viết ra )
Bài 10: Không quy đồng mẫu số, so sánh hai phân số sau \(\dfrac{25}{12}v\text{à}\dfrac{1999}{2000}\)
Bài 15: Một miếng đất HCN có Chiều rộng là 19m và bằng \(\dfrac{1}{3}\) chiều dài. Một miếng đất hình vuông có cạnh bằng trung bình cộng của chiều dài và chiều rộng HCN . Tính diện tích miếng đất hình vuông ?
giải giúp mik với, giải rõ ràng ra với nha.
câu 20: C
bài 5:\(\dfrac{9}{15}\);\(\dfrac{11}{15}\);\(\dfrac{15}{15}\);\(\dfrac{14}{13}\)
bài 10:
\(\dfrac{25}{12}\)> 1
\(\dfrac{1999}{2000}\)<1
=> \(\dfrac{25}{12}>\dfrac{1999}{2000}\)
bài 15:
Chiều dài của miếng đất hcn đó là : 19x3= 57 m
Cạnh miếng đất hình vuông là: (19+57):2=38 m
Diện tích miếng đất hình vuông là : 38 x 38= 1444 \(^{m^2}\)\
Chúc bạn học tốt! Có chỗ nào không hiểu hỏi lại mình nhá
Bài 1 Tìm x;y thuộc N*
\(\dfrac{x}{5}-\dfrac{2}{y}=\dfrac{2}{15}\)
D= \(\dfrac{2}{3\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{11}{8\cdot19}+\dfrac{13}{19\cdot32}+\dfrac{25}{32\cdot57}+\dfrac{30}{57\cdot87}\)
\(D=\dfrac{2}{3\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{11}{8\cdot19}+\dfrac{13}{19\cdot32}+\dfrac{25}{32\cdot57}+\dfrac{30}{57\cdot87}\)
Áp dụng công thức tổng quát \(\dfrac{k}{n\cdot\left(n+k\right)}=\dfrac{1}{n}-\dfrac{1}{n+k}\)
Ta có:
\(D=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{32}+\dfrac{1}{32}-\dfrac{1}{57}+\dfrac{1}{57}-\dfrac{1}{87}\\ D=\dfrac{1}{3}-\dfrac{1}{87}\\ D=\dfrac{28}{87}\)
Câu 1 :Câu hỏi của pham duc le hoan - Toán lớp 6 - Học toán với OnlineMath tham khảo nha bạn
[Mình chỉ nhớ cách làm câu 2 thôi nhé, mong bạn thông cảm]
D = \(\dfrac{2}{3.5}\) + \(\dfrac{3}{5.8}\) + \(\dfrac{11}{8.9}\) + \(\dfrac{13}{19.32}\) + \(\dfrac{25}{32.57}\) + \(\dfrac{30}{57.87}\)
D = \(\dfrac{1}{3}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{8}\) + ... + \(\dfrac{1}{57}\) - \(\dfrac{1}{87}\)
D = \(\dfrac{1}{3}\) - \(\dfrac{1}{87}\)
D = \(\dfrac{29}{87}\) - \(\dfrac{1}{87}\)
D = \(\dfrac{28}{87}\)
Chúc bạn papyxu tuong có một mùa hè tuyệt vời và học thật tốt!
\(\dfrac{75}{100}\)-\(\dfrac{17}{25}\)+\(\dfrac{13}{37}\)+\(\dfrac{1}{4}\)-\(\dfrac{8}{25}\)+\(\dfrac{24}{37}\)
\(=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(-\dfrac{17}{25}-\dfrac{8}{25}\right)+\left(\dfrac{13}{37}+\dfrac{24}{37}\right)=1\)
Thực hiện các phép tính:
\(a,\left(\dfrac{7}{16}+\dfrac{-1}{8}+\dfrac{9}{32}\right):\dfrac{5}{4}\) \(b,10\dfrac{2}{9}+2\dfrac{3}{5}+6\dfrac{2}{9}\)
\(c,30\%-2\dfrac{2}{5}+0,2.\dfrac{1}{2}\) \(d,\dfrac{-25}{30}.\dfrac{37}{44}+\dfrac{-25}{30}.\dfrac{13}{44}+\dfrac{-25}{30}.\dfrac{-6}{44}\)
a: \(=\dfrac{14-2+9}{32}\cdot\dfrac{4}{5}=\dfrac{21}{5}\cdot\dfrac{1}{8}=\dfrac{21}{40}\)
b: \(=10+\dfrac{2}{9}+2+\dfrac{3}{5}+6+\dfrac{2}{9}=18+\dfrac{47}{45}=\dfrac{857}{45}\)
c: \(=\dfrac{3}{10}-\dfrac{12}{5}+\dfrac{1}{10}=\dfrac{4}{10}-\dfrac{12}{5}=\dfrac{2}{5}-\dfrac{12}{5}=-2\)
d: \(=\dfrac{-25}{30}\left(\dfrac{37}{44}+\dfrac{13}{44}-\dfrac{6}{44}\right)=\dfrac{-25}{30}\cdot1=-\dfrac{5}{6}\)