Tim x : X+X/3=24
x+x/3=24.Tim x
\(x+\frac{x}{3}=24\)
\(x\times1+x\times\frac{1}{3}=24\)
\(x\times\left(1+\frac{1}{3}\right)=24\)
\(x\times\frac{4}{3}=24\)
\(x=24:\frac{4}{3}\)
\(x=18\)
3./x/+9=24 tim x
3.|x| + 9 = 24
=> 3.|x| = 24 -9
=> 3.|x| = 15
=>|x| = 15 : 3
=> |x| = 5
=> x\(\in\) { -5 ; 5}
\(3\left|x\right|+9=24\\ \Rightarrow3\left|x\right|=24-9\\ \Rightarrow3\left|x\right|=15\\ \Rightarrow\left|x\right|=\dfrac{15}{3}\\ \Rightarrow\left|x\right|=5\\ \Rightarrow x=\pm5\)
Vậy \(x\in\left\{5;-5\right\}\)
24+X/50+X=3/5 TIM X
\(24+\frac{x}{50}+x=\frac{3}{5}\)
\(24+\frac{x}{50}+\frac{50x}{50}=\frac{3}{5}\)
\(24+\frac{51x}{50}=\frac{3}{5}\)
\(\frac{51x}{50}=-\frac{175}{5}\)
\(\Rightarrow255x=-8750\)
\(\Rightarrow x=-\frac{1750}{51}\)
tim x:
x+x/3=24
x + x/3 = 24
x/1 + x/3 = 24
3x/3 + x/3 = 24
4x/3 = 24
4x = 24 . 3
4x = 72
x = 72 : 4
x = 18
\(x+\frac{x}{3}=24\)
\(\frac{x}{1}+\frac{x}{3}=24\)
\(\frac{3x}{3}+\frac{x}{3}=24\)
\(\frac{4x}{3}=24\)
\(4x=24\times3\)
\(4x=72\)
\(x=72:4\)
\(x=18\)
X + \(\frac{x}{3}\)= 24
\(\frac{x}{1}\)+ \(\frac{x}{3}\) = 24
\(\frac{3x}{3}\)+ \(\frac{x}{3}\) =24
\(\frac{4x}{3}\) =24
4x= 24x3
4x=72
x =72:4
x=18
tk nhé
tim x biet:
3^( x + 2 ) - 3^x = 24!
\(3^{x+2}-3^x=24\)
\(3^x.3^2-3^x.1=24\)
\(3^x.\left(3^2-1\right)=24\)
\(3^x.\left(9-1\right)=24\)
\(3^x.8=24\)
\(3^x=24:8\)
\(3^x=3\)
\(3^x=3^1\)
\(\Rightarrow x=1\)
tim x,biet: 435 + 24 : x = 500 - 65 + 24 : 3
435+24:x = 500 - 65 + 24:3
435+24:x = 435+24:3
=> 24:x= 24:3 (vì chung số hạng 435)
=> x = 3
Theo đề bài ta thấy:
435+24:x=500-65+24:3
Mà 435=500-65 nên chỉ còn 24:x=24:3
\(\Rightarrow\)X=3
tim x biet: x + x/3=24
x+x/3 =24
x/1+x/3=24
3x+x/3=24
4x/3=24
4x=24.3
4x=72
x=72/4
x=18
\(+\frac{x}{3}=24\)
\(=>x+x.\frac{1}{3}\)\(=24\)
\(=>x.1+x.\frac{1}{3}=24\)
\(=>x.\left(1+\frac{1}{3}\right)=24\)
\(=>x.\frac{4}{3}\)\(=24\)
\(=>x=24:\frac{4}{3}\)
\(=>x=24.\frac{4}{3}\)
\(=>x=18\)
Tim so nguyen x biet : x+(x+1)+(x+2)+(x+3)+........+23+24=0
Tao không biết và tao cũng chẳng quan tâm
tim x biet:x+x/3+=24