1.You (continually/make)............................silly mistakes,John. It's careless of you.
Giải thích giùm mình với ạ.Mình cảm ơn.
VIết lai câu sao cho nghĩa không đổi
Why didn't you take part in the Enghlish speaking contest last night?jenifer said -->Jenifer asked....................
Giải thích giùm mình với ạ.Mình cảm ơn nhìu
Why didn't you take part in the Enghlish speaking contest last night?jenifer said -->Jenifer asked..me to take part in the English speaking contest the night before
they make a lot of mistakes beacause they are careless (careful)
--> IF ____________________________
If they weren't careless, they wouldn't make a lot of mistakes.
If they were careful, they wouldn't make a lot of mistakes
How careless of you to leave the knife on the floor.
The rain makes it impossible for us to go out.
It is dangerous to have a shower after 10pm.
Giúp mình với ạ.Mình cảm ơn.
Giúp mình với ạ.Mình cảm ơn
giúp mình với ạ.Mình cảm ơn!
1 is watered by my father everymorning
2 is prepared by her mother in the kitchen
3 should be cleaned twice a day
4 repainting before Tet
5 was invited to his birthday party by John last night
6 of the car has to be repaired
7 won't be hung in the living room
8 the most valuable painting in the national museum been stolen
9 were told this story by their grandmother when they visited her last week
10 taken by a man when we were......
11 given up smoking since last year
12 read War and Peace since 2005
Giúp mình với ạ.
Mình cảm ơn
C nguyên
=>2căn x+2+3 chia hết cho căn x+1
=>căn x+1 thuộc Ư(3)
=>căn x+1=1 hoặc căn x+1=3
=>x=4 hoặc x=0
\(P=\dfrac{2\sqrt{x}+5}{\sqrt{x}+1}=\dfrac{2\sqrt{x}+2+3}{\sqrt{x}+1}=2+\dfrac{3}{\sqrt{x}+1}\)`(đk:x >=0)`
Để `P in ZZ`
`=> sqrt(x) +1 in Ư(3)={+-1;+-3}`
Mà `sqrt{x} +1 >0 AA x>=0`
`=> sqrt(x) +1 in {1;3}`
`@ sqrt{x} +1 =1 => x =0`
`@ sqrt(x) +1 =3 => x=4`
Giúp mình với ạ.
Mình cảm ơn ạ.
b: \(\Leftrightarrow\dfrac{-m^2+3}{m}=\dfrac{13}{4}\)
\(\Leftrightarrow-4m^2+12=13m\)
\(\Leftrightarrow4m^2-13m-12=0\)
\(\Leftrightarrow\left(m-4\right)\left(4m+3\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}m=4\\m=-\dfrac{3}{4}\end{matrix}\right.\)
Giúp mình bài 3 với ạ.mình cảm ơn
a: \(E=x^4z^3y\left(\dfrac{2}{5}-0+1\right)=\dfrac{7}{5}x^4yz^3\)
b: \(E=\dfrac{7}{5}x^4yz^3=\dfrac{7}{5}\cdot2^4\cdot\dfrac{1}{2}\cdot\left(-1\right)^3=\dfrac{7}{5}\cdot8\cdot\left(-1\right)=-\dfrac{56}{5}\)
a, \(=\left(\dfrac{2}{5}+1\right)x^4z^3y=\dfrac{7}{5}x^4z^3y\)
b, Thay x = 2 ; y = 1/2 ; z = -1 vào ta được
\(\dfrac{7}{5}.16.\dfrac{-1}{2}.1=-\dfrac{56}{5}\)