3 × ( 2x - 1 ) ^2 = 48
Những câu hỏi liên quan
Tìm x, biết:
4 * 2^x42 - 2x = 480
(2x^2 + 1)*(x-3)=0
48-(15-x)^5=48
(2x2 + 1)(x-3)=0
\(\Rightarrow\orbr{\begin{cases}2x^2+1=0\\x-3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x^2=-1\Rightarrow x^2=-\frac{1}{2}\left(vl\right)\\x=3\end{cases}}\)
Vậy x=3
48-(15-x)5=48
(15-x)5=48-48
(15-x)5=0
=> 15-x =0
x =15-0
x =15
Vậy x=15
Giải pt
1, 9x^2-1 =(3x+1)(4x+1)
2, 2x^3+3x^2-32x=48
3, (2x+5)^2-(x+2)^2=0
4, 2x^3+6x^2=x^2+3x
a) \(9x^2-1=\left(3x+1\right)\left(4x+1\right)\)
\(\Leftrightarrow\)\(\left(3x-1\right)\left(3x+1\right)-\left(3x+1\right)\left(4x+1\right)=0\)
\(\Leftrightarrow\)\(\left(3x+1\right)\left(3x-1-4x-1\right)=0\)
\(\Leftrightarrow\)\(\left(3x+1\right)\left(-x-2\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}3x+1=0\\-x-2=0\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=-\frac{1}{3}\\x=-2\end{cases}}\)
Vậy...
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(x+1)(2x+2)(3x+3)=48
Ta có: (x+1)(2x+2)(3x+3) = 48
=> (x+1).2(x+1).3(x+1) = 48
=> (x+1)3 . 6 = 48
=> (x+1)3 = 8 = 23
=> x + 1 = 2
=> x = 1
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1) x^2 + x - 6
2) x^2 - x - 6
3) x^2 + 2x - 48
4) x^2 - 2x -48
5) x^2 + x- 42
6) x^2 - x-42
1) \(x^2+x-6=x\left(x-2\right)+3\left(x-2\right)=\left(x+3\right)\left(x-2\right)\)
2) \(x^2-x-6=\left(x-3\right)\left(x+2\right)\)
3) \(x^2+2x-48=\left(x-6\right)\left(x+8\right)\)
4) \(x^2-2x-48=\left(x-8\right)\left(x+6\right)\)
5) \(x^2+x-42=\left(x-6\right)\left(x+7\right)\)
6) \(x^2-x-42=\left(x-7\right)\left(x+6\right).\)
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1) \(x^2+x-6\)
\(=x^2-2x+3x-6\)
\(=\left(x^2-2x\right)+\left(3x-6\right)\)
\(=x\left(x-2\right)+3\left(x-2\right)\)
\(=\left(x-2\right)\left(x+3\right)\)
2) \(x^2-x-6\)
\(=x^2+2x-3x-6\)
\(=\left(x^2+2x\right)-\left(3x+6\right)\)
\(=x\left(x+2\right)-3\left(x+2\right)\)
\(=\left(x+2\right)\left(x-3\right)\)
3) \(x^2+2x-48\)
\(=x^2+8x-6x-48\)
\(=\left(x^2+8x\right)-\left(6x+48\right)\)
\(=x\left(x+8\right)-6\left(x+8\right)\)
\(=\left(x+8\right)\left(x-6\right)\)
4) \(x^2-2x-48\)
\(=x^2-8x+6x-48\)
\(=\left(x^2-8x\right)+\left(6x-48\right)\)
\(=x\left(x-8\right)+6\left(x-8\right)\)
\(=\left(x-8\right)\left(x+6\right)\)
5) \(x^2+x-42\)
\(=x^2+7x-6x-42\)
\(=\left(x^2+7x\right)-\left(6x+42\right)\)
\(=x\left(x+7\right)-6\left(x+7\right)\)
\(=\left(x+7\right)\left(x-6\right)\)
6) \(x^2-x-42\)
\(=x^2-7x+6x-42\)
\(=\left(x^2-7x\right)+\left(6x-42\right)\)
\(=x\left(x-7\right)+6\left(x-7\right)\)
\(=\left(x-7\right)\left(x+6\right)\)
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Tính nhanh :
1/ (-48) × 72 + 36 × (-304)
2/ 0,15 × 3700 - 15 × 3 mũ 3 + 150 × (-2)
3/ 3 mũ 2x+1 - 3 nũ 2x
âu 48. Cho y=|x+1|+|x−2||x+1|+|x−2|và các mệnh đề
Câu 49. Hàm số y=-√|2x+3||2x+3| nghịch biến trên khoảng.
Tìm x:
3|1-2x| + 2|\(\frac{1}{4}-\frac{1}{2}x\)|= \(3^2-2^2\)
TÌM X BIẾT:
a) 2^x+1 = 32
b) 2^2x + 2^2x+1 = 48
c)3^x+5.3^x+1 = 144
d) 3^x+5 = 9^x+1
BIẾT CÂU NÀO LÀM CÂU ĐÓ GIÚP EM VS Ạ!!
\(a,2^{x+1}=32\\ 2^{x+1}=2^5\\ x+1=5\\ x=4\\ b,2^{2x}+2^{2x+1}=48\\ 2^{2x}+2\cdot2^{2x}=48\\ 3\cdot2^{2x}=48\\ 2^{2x}=16\\ 2^{2x}=2^4\\ 2x=4\\ x=2\)
\(c,3^x+5\cdot3^{x+1}=144\\ 3^x+15\cdot3^x=144\\ 16\cdot3^x=144\\ 3^x=9\\ 3^x=3^2\\ x=2\\ d,3^{x+5}=9^{x+1}\\ 3^{x+5}=3^{2x+2}\\ x+5=2x+2\\ x=3\)
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1, tìm x biết
a, (2x-1)^2-2x+1=0
b, (4x-3)^2-12x+9=0
c, 3x^2-48=0
a) \(\left(2x-1\right)^2-2x+1=0\)
\(\Leftrightarrow4x^2-4x+1-2x+1=0\)
\(\Leftrightarrow4x^2-6x+2=0\)
\(\Delta=\left(-6\right)^2-4.4.2=4\)
\(x_1=\dfrac{1}{2};x_2=1\)
b) \(\left(4x-3\right)^2-12x+9=0\)
\(\Leftrightarrow16x^2-24x+9-12x+9=0\)
\(\Leftrightarrow16x^2-36x+18=0\)
\(\Delta=\left(-36\right)^2-4.16.18=144\)
\(x_1=\dfrac{3}{4};x_2=\dfrac{3}{2}\)
c) \(3x^2-48=0\)
\(\Leftrightarrow3x^2=48\)
\(\Leftrightarrow x^2=16\)
\(x_1=4;x_2=-4\)
Tick cho mk nha
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