Rú gọn biểu thức G = \(\frac{1^{2010}+2^{2010}+3^{2010}+....................+10^{2010}}{2^{2010}+4^{2010}+6^{2010}+.....................+20^{2010}}\)
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rút gọn biểu thức :
G = \(\dfrac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{2^{2010}+4^{2010}+6^{2010}+...+20^{2010}}\)
\(C=\dfrac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{2^{2010}+4^{2010}+6^{2010}+...+20^{2010}}\)
\(=\dfrac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{1^{1010}.2^{2010}+2^{2010}.2^{2010}+2^{2010}.3^{2010}+...+2^{2010}.10^{2010}}\)
\(=\dfrac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{\left(1^{2010}+2^{2010}+3^{2010}+...+10^{2010}\right)+2^{2010}.2^{2010}.2^{2010}...2^{2010}}\)
\(=\dfrac{1}{2^{2010}+2^{2010}+2^{2010}+...+2^{2010}}\)
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\(G=\dfrac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{2^{2010}+4^{2010}+....+20^{2010}}\\ =\dfrac{1^{2010}+2^{2010}+...+10^{2010}}{2^{2010}\left(1^{2010}+2^{2010}+...+10^{2010}\right)}\\ =\dfrac{1}{2^{2010}}\)
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Theo bài ra, ta có:
\(G=\dfrac{1^{2010}+2^{2010}+3^{2010}+....+10^{2010}}{2^{2010}+4^{2010}+6^{2010}+....+20^{2010}}\)
\(\Rightarrow G=\dfrac{1^{2010}+2^{2010}+3^{2010}+....+10^{2010}}{2^{2010}\left(1^{1010}+2^{2010}+3^{2010}+....+10^{2010}\right)}\)
\(\Rightarrow G=\dfrac{1}{2^{2010}}\)
Vậy \(G=\dfrac{1}{2^{2010}}\)
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Xem thêm câu trả lời
rút gọn biểu thức: P=\(\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
Rút gọn biểu thức:
\(P=\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
\(P=\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
\(P=\frac{-3^{2010}.\left(-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}\right)}{-1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
\(P=-3^{2010}\)
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tính:
B=\(\frac{1^{2010}+2^{2010}+3^{2010}+...+10^{2010}}{2^{2010}+4^{2010}+6^{2010}+...+20^{2010}}\)
mik cần gấp, trước 10:15
Ko là mà muốn có ăn thì chỉ có ăn cứt thôi!
1^2010+2^2010+3^2010+...+10^2010 / 2^2010+4^2010+6^2010+...+20^2010
Rút gọn
A=\(\frac{3^{2010}-6^{2010}+9^{2010}-12^{2010}+15^{2010}-18^{2010}}{1+2^{2010}-3^{2010}+4^{2010}-5^{2010}+6^{2010}}\)
??????????????????????????????????????????
Rút gọn :
Q = 12010 + 22010 + ....+ 102010 phần 22010 + 42010 + .....+ 202010
Tính giá trị của biểu thức :
\(A=\left(\dfrac{\sqrt[4]{2010^2}-\sqrt[4]{2010}}{1-\sqrt[4]{2010}}+\dfrac{1+\sqrt{2010}}{\sqrt[4]{2010}}\right)^2-\dfrac{\sqrt{1+\dfrac{2}{\sqrt{2010}}+\dfrac{1}{2010}}}{1+\sqrt{2010}}\)
Tính giá trị biểu thức:
2010^2010.(7^10:7^8-3.2^4-2^2010:2^2010)
=2010^2010.(7^2-48-1)
=2010^2010.(49-48-1)
=2010^2010.0
=0
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2010^2010 . ( 7^10 : 7^8 - 3 . 2^4 - 2^2010 : 2^2010 )
= 2010^2010 . ( 7^2 - 3 . 16 - 1 )
= 2010^2010 . ( 49 - 48 - 1 )
= 2010^2010 . ( 1 - 1 )
= 2010^2010 . 0
= 0
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