\(-1+6+\left(-11\right)+16+....+996+\left(-1001\right)\)

\(=5+5+....+5+5\)

\(=5.10\)

\(=50\)

-1+6+(-11)+16+.....+996+(-1001)

=[-1+6]+[-11+16]+....+[-991+996]+(-1001)

=5       +      5      +...+       5         + (-1001)

    có 100 số 5

=5 x100+(-1001)

=500+(-1001)

=-501

k cho minh nha

chúc bạn học giỏi

= (32-12)+(34-14)+(36-16)+(38-18)-10

= 20+20+20+20-10

= 80-10

= 70

32+34+36+38-10-12-14-16-18

=(32-12)+(34-14)+(36-16)+(38-18)-10

=20+20+20+20-10

=20 x 4-10

=80-10

=70

=(32+38)+(34+36)-(12+18)-(16+18)

=70+70-30-30

=80

= (11+19) + (12+18) + (13+17) + (14+16) + (10+15)

= 30 + 30 + 30 + 30 + 25 = 145

A = 10 + (11 + 19) + (12 + 18) + (13 + 17) + (14 + 16) + 15

= 10 + 30 + 30 + 30 + 30 + 15 = 145

a) (273 - 51) - [73 - (-149)]

= 273 - 51 - 73 - 149

= (273 - 73) - (51 + 149)

= 200 - 200

= 0

b) 130 - [13 . 3 - (19-16)²

= 130 - (39 - 3²) 

= 130 - (39 - 9)

= 130 - 30

= 100

a) \(\left(273-51\right)-\left[73-\left(-149\right)\right]\)

\(=273-51-73-149\)

\(=\left(273-73\right)-\left(51+149\right)\)

\(=200-200\)

\(=0\)

b) \(130-\left[13.3-\left(19-16\right)^2\right]\)

\(=130-\left(39-3^2\right)\)

\(=130-\left(39-9\right)\)

\(=130-30\)

\(=100\)

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)

=>  \(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)

=>  \(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\right)\)

=>  \(A=1-\frac{1}{32}=\frac{31}{32}\)

* là gì vậy

A)168

B)110

a)168.168-168.58:100=168(168-58):110=168.110:110=168.(110:110)=168.1=110

A.\(\dfrac{4}{20}\)+\(\dfrac{16}{42}\)+\(\dfrac{6}{15}\)+\(\dfrac{-3}{5}\)+\(\dfrac{2}{21}\)+\(\dfrac{-10}{21}\)+\(\dfrac{3}{20}\)

=\(\dfrac{1}{5}\)+\(\dfrac{8}{21}\)+\(\dfrac{6}{15}\)+\(\dfrac{-3}{5}\)+\(\dfrac{2}{21}\)+\(\dfrac{-10}{21}\)+\(\dfrac{3}{20}\)

=\((\dfrac{1}{5}\)+\(\dfrac{6}{15}\)+\(\dfrac{-3}{5}\)\()\)+\((\dfrac{8}{21}\)+\(\dfrac{2}{21}\)+\(\dfrac{-10}{21}\)\()\)+\(\dfrac{3}{20}\)

=\((\)\(\dfrac{1}{5}\)+\(\dfrac{2}{5}\)+\(\dfrac{-3}{5}\)\()\)+ 0 +\(\dfrac{3}{20}\)

= 0 + 0 +\(\dfrac{3}{20}\)

=\(\dfrac{3}{20}\)

B.\(\dfrac{42}{46}\)+\(\dfrac{250}{286}\)+\(\dfrac{-2121}{2323}\)+\(\dfrac{-125125}{143143}\)

=\(\dfrac{21}{23}\)+\(\dfrac{125}{143}\)+\(\dfrac{-21}{23}\)+\(\dfrac{-125}{134}\)

=\((\dfrac{21}{23}+\dfrac{-21}{23})+(\dfrac{125}{143}+\dfrac{-125}{134})\)

= 0 + 0

= 0

Chúc bạn Tran Mai học tốt nha