tim x: 99<x+32<101
tim x
x*99+x=432+568
X × 99 + x = 432 + 568
X × 99 + x × 1 = 1000
X × (99 + 1 )=1000
X × 100 = 10
X =10
\(x\times99+x=432+568.\)
\(\Leftrightarrow x\times99+x=1000\)
\(\Leftrightarrow x\times\left(99+1\right)=1000\)
\(\Leftrightarrow x\times100=1000\)
\(\Leftrightarrow x=10\)
tim x
99-3.(x+17)=45
\(99-3\cdot\left(x+17\right)=45\)
\(3\cdot\left(x+17\right)=99-45\)
\(3\cdot\left(x+17\right)=54\)
\(x+17=54\div3\)
\(x+17=18\)
\(x=18-17\)
\(x=1\)
\(\text{99-3.(x+17)=45 }\)
\(3.\left(x+17\right)=99-45\)
\(3.\left(x+17\right)=54\)
\(x+17=54:3\)
\(x+17=18\)
\(x=18-17\)
\(x=1\)
hok tốt
x:3.(45)=99 tim x
tim x
(x+1)+(x+3)+(x+5)+...+(x+99)=3000
Ta có :
(x + 1) + (x + 3) + (x + 5) + ... + (x + 99) = 3000
(x + x + x + ... + x) + (1 + 3 + 5 + 99) = 3000
50x + 2500 = 3000
50x = 3000 - 2500
50x = 500
x = 500 : 50
x = 10
Vậy x = 10
Ủng hộ mk nha !!! ^_^
( x + 1 ) + ( x + 3 ) + ( x + 5 ) + ... + ( x + 99 ) =3000
x + ( 1 +3 + 5 + ... + 99 ) = 3000
x + 2500 = 3000
x = 3000 - 2500
x = 500
Chúc bạn học tốt!
Đây là toán 4 chứ ko phải toán 6
( x + 1 ) + ( x + 3 ) + ( x + 5 ) + ... + ( x + 99 ) =3000
x + ( 1 +3 + 5 + ... + 99 ) = 3000
x + 2500 = 3000
x = 3000 - 2500
x = 500
TIM X BIET: 3^99 : (2.X-1)=3^97
399 : (2x - 1) = 397
=> 2x - 1 = 9
2x = 10
x = 5
\(3^{99}:\left(2x-1\right)=3^{97}\)
\(\Rightarrow2x-1=3^{99}:3^{97}\)
\(\Rightarrow2x-1=3^2=9\)
\(\Rightarrow2x=9+1=10\)
\(\Rightarrow x=5\)
tim x biet (1+3+....+99)x=2+4+6+.....+100
(1+3+...+99)x = 2+4+6+100
2500x=2550
x=2550:2500
x= 1,02
Kẻ bí mật này, tớ tưởng 2+4+6+100=112 chứ?! Sao ra 2550 giỏi vậy! Đúng là ấm đầu thiệt rùi!
tim X biet
3^99 : (2.x-1)^3 = 3^97
tim x neu x :11du13;x:13du15.hoi :99 du bao nhieu
Tim x
x+1/99+x+2/98+x+3/97+x+4/96=-4
4x + (1/99+2/98+3/97 + 4/96)=-4
4x=-4 - (1/99+2/98+3/97 + 4/96)
4x=