mình biết nội quy rồi nên đưng đăng nội quy

ai chơi bang bang 2 kết bạn với mình

mình có nick có 54k vàng đang góp mua pika 

ai kết bạn mình cho

(1^2+2^2+3^+....+10^2).(65.111-13.15.17)

=(1^2+2^2+3^2+...+10^2).(65.111-13.555)

=(1^2+2^2+3^2+...+10^2).(65.111+13.5.111)

=(1^2+2^2+3^2+...+10^2).(65.111+65.111)

=(1^2+2^2+3^2+...+10^2).[111.(65-65)

=(1^2+2^2+3^2+...+10^2).(111.0)

=(1^2+2^2+3^2+...+10^2).0

=0

\(A=\left(1+2+3+...+2023\right)\left(1^2+2^2+...+2023^2\right)\left(65\cdot111-13\cdot15\cdot37\right)\)

\(=\left(1+2+3+...+2023\right)\cdot\left(1^2+2^2+...+2023^2\right)\cdot\left(13\cdot5\cdot3\cdot37-13\cdot5\cdot3\cdot37\right)\)

=0

B=C*[13*37*(5*3-15)]=0

\(A=\dfrac{2^{10}\cdot78}{2^8\cdot26\cdot4}=\dfrac{78}{26}=3\)

b)Ghi đầu baì

=(1+2+3+...+100).(1²+2²+3²+....+100²).(65.111-13.555)

=(1+2+3+...+100).(1²+2²+3²+....+100²).(65.111-13.5.111)

=(1+2+3+...+100).(1²+2²+3²+....+100²).(111.(65-65))

=(1+2+3+...+100).(1²+2²+3²+....+100²).111.0

=(1+2+3+...+100).(1²+2²+3²+....+100²).0

=0

a,6³¹=6³¹

b, 27¹⁶:9¹⁰=(3³)¹⁶:(3²)¹⁰=3⁴⁸:3²⁰=3²⁸

c,(1+2+3+.....+100).(1²+2²+3²+...+10²).(65.111-13.15.17)

=(1+2+3+.....+100).(1²+2²+3²+...+10²).(13.15.17-13.15.17)

=(1+2+3+.....+100).(1²+2²+3²+...+10²).0

=0

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