So sanh : 4^90 va 3^120
khong quy dong tu so va mau so hay so sanh
a) 13/17 va 15/19
tim x biet
a) \(\frac{2}{3}\times x+\frac{3}{4}=3\)
b, 720:[41-(2x x-5)]=120
a)13/17 < 15/19
a) 2/3 x X + 3/4 = 3
2/3 x X = 3 - 3/4
2/3 x X = 9/4
X = 9/4 : 2/3
X = 27/8
a. Ta có : \(\frac{13}{17}=\frac{247}{323};\frac{15}{19}=\frac{255}{323}\)
Vì 255 > 247 nên 247/323 < 255/323
Hay \(\frac{13}{17}< \frac{15}{19}\)
b. \(\frac{2}{3}\times x+\frac{3}{4}=3\)
\(\frac{2}{3}\times x=3-\frac{3}{4}\)
\(\frac{2}{3}\times x=\frac{9}{4}\)
\(x=\frac{9}{4}:\frac{2}{3}\)
\(x=\frac{27}{8}\)
c. \(720:\left[41-\left(2\times x-5\right)\right]=120\)
\(\left[41-\left(2\times x-5\right)\right]=720:120\)
\(41-\left(2\times x-5\right)=6\)
\(2\times x-5=35\)
\(2\times x=40\)
\(x=20\)
a)\(\frac{13}{17}>\frac{15}{19}\)
b)\(720\div[41-(2x\times5)]=120\) c)\(\frac{2}{3}\times x+\frac{3}{4}=3\)
\(41-(2x\times5)=270\div120\) \(\frac{2}{3}\times x=3-\frac{3}{4}\)
\(41-(2x-5)=6\) \(\frac{2}{3}\times x=\frac{9}{4}\)
\(2x-5=41-6\) \(x=\frac{9}{4}\div\frac{2}{3}\)
\(2x-5=35\) \(x=\frac{9}{4}\times\frac{3}{2}\)
\(2x=35+5\) \(x=\frac{27}{8}\)
\(2x=40\)
\(x=40\div2\)
\(x=20\)
so sanh
a,2^160 va 4^120; b,2^91 va 5^35; c,A=2^0+2^1+2^2+...+2^12 va B=2^11
so sanh 3120 va 580 thi lam the nao?
xin giup toi : khong qui dong mau va tu so .So sanh phan so 17/52 va 41/120
Ta có:\(\frac{17}{52}< \frac{17}{51}hay\frac{17}{52}< \frac{1}{3}\)(1)
\(\frac{41}{120}>\frac{40}{120}hay\frac{41}{120}>\frac{1}{3}\)(2)
Từ (1)và(2) =>\(\frac{17}{52}< \frac{1}{3}< \frac{41}{120}\)
Hay \(\frac{17}{52}< \frac{41}{120}\)
Vậy không quy đồng mẫu số và tử số ta được:\(\frac{17}{52}< \frac{41}{120}\)
Học giỏi^^
so sanh hai phan so 16/51 va 31/90
Ta có\(\frac{16}{51}< \frac{17}{51}=\frac{1}{3};\frac{31}{90}>\frac{30}{90}=\frac{1}{3}\)
\(\Rightarrow\frac{16}{51}< \frac{1}{3}< \frac{31}{90}\Rightarrow\frac{16}{51}< \frac{31}{90}\)
so sanh 31^90 va 32^80
so sanh 32^81 va 31^90
\(\left\{{}\begin{matrix}a=32^{81}\\b=31^{90}\end{matrix}\right.\)
\(\dfrac{a}{b}=\dfrac{2^{5.3^4}}{31^{2.3^2.5}}=\left(\dfrac{2^{3^2}}{31^2}\right)^{^{5.3^2}}\)
\(\dfrac{2^{10}}{2.31^2}< \dfrac{1024}{2.30^2}=\dfrac{1024}{1800}< 1\Rightarrow\dfrac{a}{b}< 1\Rightarrow a< b\)
3.khong quy dong hay so sanh
A,15/23 va 70/115
B, 19/60 va 31/90