b) 1.2.3...9-1.2.3...8-1.2.3...7.8^ 2
1.2.3......9-1.2.3........8-1.2.3.....7.82
1.2.3....9-1.2.3....8-1.2.3....7.82
1.2.4...9-1.2.3...8-1.2.3...7.82
=8!.9-8!.1-8!.8
=8!(9-1-8)
=8!.0
=0
tick ủng hộ mình nhá!
a/ 1.2.3...9-1.2.3...8-1.2.3...7.82
1.2.3...9-1.2.3...8-1.2.3...7.82
= (1.2.3.4.5.6.7).9 - (1.2.3.4.5.6.7).8 - (1.2.3.4.5.6.7).1
= (1.2.3.4.5.6.7).(9-8-1)
=(1.2.3.4.5.6.7).0
= 0
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82 = ?
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3...8.( 9 - 1 - 8)
= 1.2.3..8.0
= 0
Chúc cậu học tốt nhé!!
1.2.3. ..... .9-1.2.3. ...... .8-1.2.3. .... .7.8^2
mong mọi người sẽ giúp
1.2.3....9 - 1.2.3.....8 - 1.2.3...7.82
= 1.2.3.4.5.6.7.8( 9 - 1 - 8)
= 1.2.3.4.5.6.7.8.0
= 0
1.2.3....9 - 1.2.3.....8 - 1.2.3...7.82
= 1.2.3.4.5.6.7.8( 9 - 1 - 8)
= 1.2.3.4.5.6.7.8.0
= 0
1.2.3...9-1.2.3...8-1.2.3...7.82
cau hoi tuong tu nha bn, tick mik nha
Thực hiện phép tính:
1.2.3.......9-1.2.3............8-1.2.3........7.8 mũ 2
1.2.3...9-1.2.3...8-1.2.3....7.8^2
= 8!(9-1)-7! . 8^2
=8! . 8-7! . 8^2=7!8^2-7!8^2=0
Hỏi bài này nhiều quá rồi đấy , mà rõ ràng mình đã giải , bạn còn chưa tích mà
thực hiện phép tính sau 1 cách hợp lý: 1.2.3...9-1.2.3...8-1.2.3...7.8 mũ 2
Bài làm
1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
= 1.2.3...8.( 9 - 1 - 8 )
= 1.2.3...8 .0
= 0
_Chúc_Bạn_Hok_Tốt_^^
\(1.2.3....9-1.2.3...8-1.2.3...7.8^2=1.2.3....8\left(9-1-8\right)=1.2.3....8.0=0\)
Giải
Ta có: 1.2.3....9 - 1.2.3....8 - 1.2.3....8^2
= 1.2.3....8(9-1-8)
= 1.2.3....8.0
= 0
B = -1.2.3 .....8.9+ 1.2.3.....7.8+1.2.3....7.8^2
1.2.3...8.9-1.2.3....8-1.2.3...8.8
=1.2.3...8(9-1-8)
=1.2.3...8.0
=0