tìm x:
321-5*(x+2)=4*32
Tìm x ∈ N, biết:
a, x ∈ B(5), x < 20
b, x ⋮ 24; x ⋮ 45; 200 < x < 500
c, 452 = px+32; 321 = qx+21 (p,q ∈ N*)
a, Ta có: x ∈ B(5) = {0;5;10;15;20;25;...}
Mà x < 20 => x ∈ {0;5;10;15}
b, Ta có: x ⋮ 24; x ⋮ 45 => x ∈ BC{24;45}
24 = 2 3 . 3 ; 45 = 3 2 . 5 => BCNN(24;45) = 2 3 . 3 2 . 5 = 360
=> BC(24;45) = B(360) = {0;360;720;...}
Mà 200 < x < 500 => x = 360
c, Ta có:
452 = px+32 => 420 ⋮ x
321 = qx+21 => 320 ⋮ x
=> x ∈ ƯC(420;320)
420 = 2 2 . 3 . 5 . 7
320 = 2 6 . 5
=> ƯCLN(420;320) = 20 = 2 2 . 5
=> ƯC(420;320) = Ư(20) = {1;2;4;5;10;20}
Vậy x ∈ {1;2;4;5;10;20}
x=321-21*[(2*3^3+4^4:32)-52]
Cứu
\(=321-21\cdot\left[2\cdot27+256:32-52\right]\)
\(=321-21\cdot10=321-210=111\)
1)tính
a)321+{-15+[30+-321]}
b)(2016+332)+[168+-2016]
2)tìm X
a)x+7=-12
b)x-15=-21
3)tìm X
a)17-(2+x)=3
b)(6+x)-(17-21)=-25
c)-10-(31-x)=40
4)tìm X
a)15-(3+x)=4
b)(7+x)-(21-13)=32
c)-11-(19-x)=50
5)tìm X
a)5-lxl=1
b)10+lx-1l=4
6)tìm X
a)lx+4l<5
b)l3-xl>2
(l và l là giá trị tuyệt đối; những số có dấu"-"là số âm nhé)
GIÚP MÌNH VỚI ^-^
Tính theo mẫu?
Mẫu: 26 x 4 + 26 x 3 + 26 x 2 26 x 4 + 26 x 3 + 26 x 2 = 26 x (4 + 3 + 2) = 26 x 9 = 234. |
321 x 3 + 321 x 5 + 321 x 2
321 x 3 + 321 x 5 + 321 x 2
= 321 x (3 + 5 + 2)
= 321 x 10
= 3 210.
321 x 3 + 321 x 5 + 321 x 2
= 321 x (3 + 5 + 2)
= 321 x 10
= 3210
1. Tìm x:
a) /x/ + 2 = 23 . (-2)2
b) /x/ + 4 = (-3)2 + (-2)
2. Tính:
a) 5 . ( -5 - 6 )
b) 321 + { -15 + [ 30 + ( -321 )]}
c) 19 . 92 - 9 . ( -19 ) - 19
a) \(\left|x\right|+2=2^3.\left(-2\right)^2\)
\(\Leftrightarrow\)\(\left|x\right|+2=32\)
\(\Leftrightarrow\)\(\left|x\right|=30\)
\(\Leftrightarrow\)\(x=\pm30\)
Vậy...
b) \(\left|x\right|+4=\left(-3\right)^2+\left(-2\right)\)
\(\Leftrightarrow\)\(\left|x\right|+4=7\)
\(\Leftrightarrow\)\(\left|x\right|=3\)
\(\Leftrightarrow\)\(x=\pm10\)
Vậy...
b2 :
a) 5 . ( -5 - 6 )
= 5 . ( -11 )
= -55
b) 321 + { - 15 + [ 30 + ( -321 ) ] }
= 321 + { - 15 + [ - 291 ] }
= 321 + ( - 306 )
= 15
19 . 92 - 9 . ( - 19 ) - 19
= 1748 - ( -171 ) - 19
= 1919 - 19
= 1900
321- 21. [(2.3^3+4^4 :32)]- 52
2018^0+5^9:5^7-3.7
321- 21. [(2.3^3+4^4 :32)]- 52
=321- 21. [(2.27+256 :32)]- 52
=321-21.[(54+8)]-52
=321-21.62-52
=321-1203-52
=-754
321- 21. [(2.3^3+4^4 :32)]- 52
=321- 21. [(2.27+256 :32)]- 52
=321-21.[(54+8)]-52
=321-21.62-52
=321-1203-52
=-754
2/ Tìm x :
a/ 5(x – 7) = 2 . 32- 3
b/ 12 : (x – 4) = -3
Tìm số nguyên x biết:
1, -x +(-53) =(-42) - 41
2. -12 - x= -32 +19
3.453+x = -443+(-199)
4. -12-x = -32 +19
5. 32.(-2) +x = -120 -5.(-85)
6. -2x + 15.(-4) = 21.(-8) -12
Tìm x,biết :
a,|x| -2,5 =27,5 b, 3/4+2/5.x=29/60 c,(x-1)^5=-32 d,4/5.x+0,5=4.5
a/|x|-2,5=27,5
=>|x|=27,5+2,5=30
=>x=30 hoặc x=-30
b/\(\dfrac{3}{4}+\dfrac{2}{5}.x=\dfrac{29}{60}\)
=>\(\dfrac{2}{5}.x\)=\(\dfrac{29}{60}-\dfrac{3}{4}\)=\(\dfrac{-4}{15}\)
=>x=\(\dfrac{-4}{15}:\dfrac{2}{5}\)=\(\dfrac{-2}{3}\)
c/(x-1)\(^5\)=-32
=>x-1=-2 vì (-2)\(^5\)=-32
=>x=-2+1=-1
d/\(\dfrac{4}{5}.x+0,5=4.5\)
=>\(\dfrac{4}{5}.x+0,5=20\)
=>\(\dfrac{4}{5}.x=20-0,5=19,5\)
=>\(x=19,5:\dfrac{4}{5}\)=\(\dfrac{195}{8}\)