\(\frac{\left(3-x\right)^{10x}}{\left(3-x\right)^{20}}=1\Leftrightarrow\left(3-x\right)^{10x-20}=\left(3-x\right)^{10\left(x-2\right)}=1\\ \)

\(\orbr{\begin{cases}x-2=0=>x=2\\3-x=+-1\orbr{\begin{cases}x=2\\x=4\end{cases}}\end{cases}}\)\(\orbr{\begin{cases}x-2=0\Rightarrow x=2\\3-x=!1!\end{cases}}\)\(\orbr{\begin{cases}x=2\\x=4\end{cases}}\)

\(\left(3-x\right)^{10x}:\left(3-x\right)^{20}=1\)

=>\(\left(3-x\right)^{10x-20}=1\)

=>10x-20=0 hoặc 3-x=1

=>x=2 hoặc x=2

=>x=2

(3-x)^10x:(3-x)²⁰=1

=> (3-x)^10x=(3-x)²⁰

=> 10x=20

=> x=2

a, 7.7^x+1=343

   7^x+1+1=343

    7^x+2=343=7³

=> x+2=3

      x=3-2=1

b,2³.2^x=64

     2^3+x=64=2⁶

  => 3+x=6

        x=6-3=3

c,(3x-15)⁷=0

  =>  (3x-15)=0

    3x-15=0

    3x=0+15

    3x=15

     x=15:3=5

d,  4^(2x-6)=1

  => 4^(2x-6)=4⁰=1

=>    2x-6=0

        2x=0+6=6

         x=6:2=3

e, (3-x)^10x:(3-x)²⁰=1

Nx:   Một số chia cho chính nó luôn bằng1

Có:   3-x=3-x

=>  10x=20

       x=20:10=2

f, (x-6)³=(x-6)²

Ta có:       Th1:      0³=0²=0

                  =>  (x-6)³=(x-6)²=0

                   =>  x-6 =0

                        x=0+6=6

             Th2:    1³=1²=1

                    =>    (x-6)³=(x-6)²=1

                      =>   x-6=1

                              x=1+6=7

(3x - 15)⁷ = 0

=> 3x - 15 = 0

=> 3x = 15

=> x = 5

4^2x-6 = 4⁰

=> 2x - 6 = 0 

=> 2x = 6

=>x = 3

a) (3x-15)⁷ = 0

3x-15 = 0

3x = 0+15

3x = 15

x = 15:3

x = 5

b) 4^2x-6 = 1

 2x-6 = 0

2x = 0+6

2x = 6

x = 6:2

x = 3

c) Tớ ko bít 

d) (x - 6)³ = (x - 6)²

Th₁:

x - 6 = 1

x = 1 + 6

x = 7

Th₂:

x - 6 = 0

x = 6

Vậy x = 7

      x = 6

--thodagbun--

a, (3x-15)^7=0 <=> 3x-15=0 <=> x=5

b, 4²x+6=1 <=> 16x=-5 <=>x=-5/16

c, \(\dfrac{\left(3-x\right)^{10x}}{\left(3-x\right)^{20}}=1\Leftrightarrow\left(3-x\right)^{10x-20}=1\)

TH1: 10x-20 = 0 <=> x=2

TH2: 3-x=1 <=> x=2

Vậy x=2

d, (x-6)^3 = (x-6)^2

<=> (x-6)^2.[(x-6)-1]=0

<=> (x-6)^2=0 hoặc (x-6)-1=0

<=> x=6 hoặc x=7