25^4×2^8
15^8×9^4
27^2÷25^3
tính bằng cách thuận tiện nhất:
c) 815 - 23 - 77 +185
m) 8 x 427 x 3 + 6 x 573 x 4
g) 52 - 42 + 37 + 28 - 38 + 63
h) 35 x 18 - 9 x 70 + 100
n) 2008 x 867 + 2009 x 133
i) 326 x 78 + 327 x 22
q) ( 20 + 21 + 22 + 23 + 24 + 25 ) x ( 16 - 2 x 8 )
c ) 815 - 23 - 77 + 185
= ( 815 + 185 ) - ( 23 + 77 )
= 1000 - 100 = 900
m ) 8 x 427 x 3 + 6 x 573 x 4
= 24 x 427 + 24 x 573
= 24 x ( 427 + 573 )
= 24 x 1000
= 24000
g ) 52 - 42 + 37 + 28 - 38 + 63
= ( 52 + 28 ) - ( 42 + 38 ) + ( 37 + 63 )
= 80 - 80 + 100
= 0 + 100
= 100
h ) 35 x 18 - 9 x 70 + 100
= 7 x 5 x 9 x 2 - 9 x 7 x 5 x 2 + 100
= 0 + 100
= 100
n ) 2008 x 867 + 2009 x 133
= 2008 x 867 + ( 2008 + 1 ) x 133
= 2008 x 867 + 2008 x 133 + 133
= 2008 x ( 867 + 133 ) + 133
= 2008 x 1000 + 133
= 2008000 + 133
= 2008133
i ) 326 x 78 + 327 x 22
= 326 x 78 + ( 326 + 1 ) x 22
= 326 x 78 + 326 x 22 + 22
= 326 x ( 78 + 22 ) + 22
= 326 x 100 + 22
= 32600 +22
= 32622
q ) ( 20 + 21 + 22 + 23 + 24 + 25 ) x ( 16 - 2 x 8 )
= ( 20 + 21 + 22 + 23 + 24 + 25 ) x ( 16 - 16)
= ( 20 + 21 + 22 + 23 + 24 + 25 ) x 0
= 0
tính nhanh
a, 4*125*25*8
b,2*3*4*5*50*25
c,8*427*3+6*573*4
d,54*47-47*53-20-27
e,100-47*72-47*28
a) 8 x 427 x 3 + 6 x 573 x 4
b) 6 x 1235 x 20 – 5 x 235 x 24
c) (72 x 135 + 9 x 65 + 8) : 25 – 3500 : 25
d) (18 x 957 – 9 x 354 x 2 – 3 x 621 x 6) : 72
a: =24*1000=24000
b: =120*1000=120000
c: =72(135+65):25-140
=72*8-140=436
d: =18(957-354-621):72=-9/2
A = 9/8 - 8/9 + 3/25 + 1/4 - 5/16 + 19/25 - 1/9 + 2/25 - 1/81
B = -1/3- 8/35 - 2/9 - 1/35 + 4//5 + -4/9 + 3/7
\(A=\dfrac{9}{8}-\dfrac{8}{9}+\dfrac{3}{24}+\dfrac{1}{4}-\dfrac{5}{16}+\dfrac{19}{25}-\dfrac{1}{9}+\dfrac{2}{25}-\dfrac{1}{81}\)
\(=\dfrac{9}{8}+\dfrac{1}{4}-\dfrac{5}{16}+\dfrac{1}{8}-\dfrac{8}{9}-\dfrac{1}{9}-\dfrac{1}{81}+\dfrac{19}{25}+\dfrac{2}{25}\)
\(=\dfrac{10}{8}+\dfrac{1}{4}-\dfrac{5}{16}-1-\dfrac{1}{81}+\dfrac{21}{25}\)
\(=\dfrac{20+4-5}{16}-\dfrac{82}{81}+\dfrac{21}{25}\)
\(=\dfrac{19}{16}-\dfrac{82}{81}+\dfrac{21}{25}\)
\(=\dfrac{32891}{16\cdot81\cdot25}\)
b: \(B=-\dfrac{1}{3}-\dfrac{8}{35}-\dfrac{2}{9}-\dfrac{1}{35}+\dfrac{4}{5}-\dfrac{4}{9}+\dfrac{3}{7}\)
\(=\dfrac{-1}{3}-\dfrac{2}{9}-\dfrac{4}{9}-\dfrac{8}{35}-\dfrac{1}{35}+\dfrac{4}{5}+\dfrac{3}{7}\)
\(=\dfrac{-3-2-4}{9}+\dfrac{-9}{35}+\dfrac{28+15}{35}\)
\(=-1+\dfrac{-9+43}{35}=-1+\dfrac{34}{35}=-\dfrac{1}{35}\)
1 . 25 x { 32 : [ 12 - 4 + 4 x ( 16 : 8 ) ] }
2. 2195 x 1952 - 952 x 427 - 1952 x 1768
`Answer:`
1. \(25.\left\{32:[12-4+4.\left(16:8\right)]\right\}\)
\(=25.\left\{32:[12-4+4.2]\right\}\)
\(=25.\left\{32:[12-4+8]\right\}\)
\(=25.\left\{32:[8+8]\right\}\)
\(=25.\left\{32:16\right\}\)
\(=25.2\)
\(=50\)
2. \(2195.1952-952.427-1952.1768\)
\(=2195.1952-1952.1768-952.427\)
\(=\left(2195-1768\right).1925-952.427\)
\(=427.1952-952.427\)
\(=\left(1952-952\right).427\)
\(=1000.427\)
\(=427000\)
bài 2 viết mỗi tích, thương sau dưới dạng luỹ thừa
a) 4^10 x 2^30 b) 9^25 x 27^4 x 81^3 c) 25^50 x 125^5 d) 64^3 x 4^8 x 16^4
e)3^8:3^6 ; 2^10:8^3 ; 12^7 :6^7 ; 31^5 ; 81^3
f) 5^8 : 25^2 ; 4^9:64^2 ; 2^25 : 32^4 ; 125^3 : 25^4
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
1.Khoanh vào các phân số bằng nhau
a.1/2, 2/4, 5/8, 4/8, 9/10, 3/6
b.1/4, 2/9, 2/8, 3/12, 5/16, 5/20
c.2/5, 4/15, 8/20, 8/25, 10/25, 12/20
\(a,\dfrac{1}{2}=\dfrac{2}{4}=\dfrac{4}{8}=\dfrac{3}{6}\\ b,\dfrac{1}{4}=\dfrac{2}{8}=\dfrac{3}{12}=\dfrac{5}{20}\\ c,\dfrac{2}{5}=\dfrac{8}{20}=\dfrac{10}{25}\)
Tính
a) 9/8 - 8/9 = 8/25 + 1/4 - 5/16 + 19/25 - 1/9 + 2/25 - 1/81
b) -1/3 + 4/5 - 8/35 + -2/9 - 1/135 + -4/9 + 3/7
Các bn giải giúp mình nha chiều nay mk phải đi học rùi
Làm chi tiết nha
37 x 5^4 trên 25 ^ 2
2 ^4 x 2^6 x 3^8 x 9^2 trên 4^4 x 3^11
3 x 9^4 x 9^3 trên 3^2 x 9
125 x 5 x 64 - 25^3 x10 x 4 trên 5^7 x 8
\(\dfrac{37\cdot5^4}{25^2}=\dfrac{37\cdot5^4}{5^4}=37\\ \dfrac{2^4\cdot2^6\cdot3^8\cdot9^2}{4^4\cdot3^{11}}=\dfrac{2^{10}\cdot3^8\cdot3^4}{2^8\cdot3^{11}}=2^2\cdot3=12\\ \dfrac{3\cdot9^4\cdot9^3}{3^2\cdot9}=\dfrac{3\cdot3^8\cdot3^6}{3^2\cdot3^2}=3^{11}\\ \dfrac{125\cdot5\cdot64-25^3\cdot10\cdot4}{5^7\cdot8}=\dfrac{5^3\cdot5\cdot2^6-5^6\cdot2\cdot5\cdot2^2}{5^7\cdot2^3}=\dfrac{5^4\cdot2^3\left(2^3-5^3\right)}{5^7\cdot2^3}=\dfrac{8-125}{5^3}=\dfrac{-117}{125}\)