a) \(5.3^x=405\)

\(\Rightarrow3^x=405:5\)

\(\Rightarrow3^x=81=3^4\)

\(\Rightarrow x=4\)

b) \(\left(x-2\right)^5=243\)

\(\Rightarrow\left(x-2\right)^5=3^5\)

\(\Rightarrow x-2=3\)

\(\Rightarrow x=5\)

c) \(2^x+2^{x+4}=272\)

\(\Rightarrow2^x.\left(1+2^4\right)=272\)

\(\Rightarrow2^x.17=272\)

\(\Rightarrow2^x=272:17=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

d) Từ x + 1 đến x + 2 có số số hạng là: (30 - 1) : 1 + 1 = 30 (số)

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=795\)

\(\Rightarrow30x+\frac{\left(30+1\right).30}{2}=795\)

\(\Rightarrow30x+465=795\)

\(\Rightarrow30x=330\)

\(\Rightarrow x=330:30\)

\(\Rightarrow x=11\)

a) \(5.3^x=405\)

         \(3^x=\frac{405}{5}=81\)

          \(3^x=3^4\)

Vậy x = 4

b ) \(\left(x-2\right)^5=243\)

      \(\left(x-2\right)^5=3^5\)

\(\Rightarrow x-2=3\)

\(\Rightarrow x=3+2=5\)

     Vậy x = 5

a, 5.3 ^x =405

3^x=405:5

3^x=81

=> x=4

b, (x-2)⁵=243

(x-2)⁵=3⁵

vì 5=5

nên x -2=3

<=> x=3+2

=>x=5

c, 2x  +   2x+4  =  272 

2^x+2^x+2⁴=272

2^x(1+2⁴)=272

2^x.17=272

2^x=272:17

2^x=16

vì 16=2⁴

=>x=4

d, (x+1)+(x+2)+(x+3)+.....+(x+30)=795

(x+x+x+..+x)+(1+2+3+..+30)=795

30x+456=795

30x=795-456

30x=330

x=330:30

x=11

vậy x=11

hc tốt

Lời giải:

$1+2+2^3+2^4+2^5+...+2^{x+1}=1023$

$2^3+2^4+2^5+...+2^{x+1}=1020(1)$

$2^4+2^5+2^6+...+2^{x+2}=2040(2)$

Lấy (2) trừ (1) theo vế suy ra:

$2^{x+2}-2^3=2040-1020=1020$

$2^{x+2}=1028$

Với giá trị này sẽ không tồn tại số tự nhiên x. Bạn xem lại đề.

a ) 2ⁿ = 16 

2.2.2.2 = 16 nên n = 4

Vậy : 2⁴ = 16

b ) 4ⁿ = 64

4.4.4 = 64 nên n = 3

Vậy : 4³ = 64

c ) 15ⁿ = 225

15.15 = 225 nên n = 2

Vậy : 15² = 225

a) \(2^n=16\)

\(vi 16=2.2.2.2=2^4\)nen \(n=4\)

b) \(4^n=64\)

\(vi\)\(64=4.4.4=4^3\)nen \(n=3\)

c) \(15^n=225\)

\(vi\)\(225=15.15=15^2\)nen \(n=2\)

các cậu giúp tớ bài x mũ 50 nữa nha 

a) \(5\left(x+7\right)-10=2^3\cdot5\)

\(\Rightarrow5\left(x+7\right)-10=40\)

\(\Rightarrow5\left(x+7\right)=40+10\)

\(\Rightarrow x+7=\dfrac{50}{5}\)

\(\Rightarrow x+7=10\)

\(\Rightarrow x=10-7\)

\(\Rightarrow x=3\)

b) \(9x-2\cdot3^2=3^4\)

\(\Rightarrow9x-18=81\)

\(\Rightarrow9x=81+18\)

\(\Rightarrow9x=99\)

\(\Rightarrow x=\dfrac{99}{9}\)

\(\Rightarrow x=11\)

c) \(5^{25}\cdot5^{x-1}=5^{25}\)

\(\Rightarrow5^{x-1}=5^{25}:5^{25}\)

\(\Rightarrow5^{x-1}=1\)

\(\Rightarrow5^{x-1}=5^0\)

\(\Rightarrow x-1=0\)

\(\Rightarrow x=1\)

a) 5(�+7)−10=23⋅55(x+7)−10=23⋅5

$\Rightarrow 5\left(x+7\right)-10=40$

$\Rightarrow 5\left(x+7\right)=40+10$

⇒�+7=505⇒x+7=550​

$\Rightarrow x+7=10$

$\Rightarrow x=10-7$

$\Rightarrow x=3$

b) 9�−2⋅32=349x−2⋅32=34

$\Rightarrow 9x-18=81$

$\Rightarrow 9x=81+18$

$\Rightarrow 9x=99$

⇒�=999⇒x=999​

$\Rightarrow x=11$

c) 525⋅5�−1=525525⋅5x−1=525

⇒5�−1=525:525⇒5x−1=525:525

⇒5�−1=1⇒5x−1=1

⇒5�−1=50⇒5x−1=50

$\Rightarrow x-1=0$

$\Rightarrow x=1$

+)  \(x^3=x^2\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)

+) \((7x-11)^3=2^5.5^2+200\)

\((7x-11)^3=2^3.2^2.5^2+2^3.5^2\)

\((7x-11)^3=2^3.5^2.(2^2+1)\)

\((7x-11)^3=2^3.5^2.5\)

\((7x-11)^3=2^3.5^3\)

\((7x-11)^3=10^3\)

\(\Rightarrow7x-11=10\)

                  \(7x=21\)

                    \(x=3\)

+) \(3+2^{x-1}=24-[4^2-(2^2-1)]\)

    \(3+2^{x-1}=11\)

              \(2^{x-1}=8\)

              \(2^{x-1}=2^3\)

       \(\Rightarrow x-1=3\)

                    \(x=4\)

a)x=1

b)x=2

c)x=3

a, x= 1

b, x=2

c,x= 3

\(x^2=1\)

\(x^2=4=2^2\)

\(x^2=9=3^2\)

\(3^x+4^2=19^6:\left(19^3.19^2\right)-2.1^{2014}\)

\(\Rightarrow\) \(3^x+16=19^6:19^5-2\)

\(\Rightarrow\) \(3^x+16=19-2\)

\(\Rightarrow\) \(3^x+16=17\)

\(\Rightarrow\) \(3^x=1\)

\(\Rightarrow\) \(3^x=3^0\)

\(\Rightarrow\) \(x=0\)

  Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

Bài 9,

6²x73+36x3³=36x73+36x27=36(73+27)=36x100=3600.

197-\([\)6x(5-1)²+2022⁰\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.

Bài 10,

21-4x=13

=>4x=21-13=8

=>x=8:4=2.

30:(x-3)+1=4⁵:4³=4²=16

=>30:(x-3)=16-1=15

=>x-3=30:15=2

=>x=2+3=5.

(x-1)³+5x6=38

=>(x-1)³+30=38

=>(x-1)³=38-30=8=2³

=>x-1=2

=>x=3.