\(3^{x+4}+3^{x+2}=270\)

\(\Leftrightarrow3^x\cdot90=270\)

hay x=1

\(3^{x+2}.3^2+3^{x+2}=270\)

\(3^{x+2}\left(3^2+1\right)=270\)

\(3^{x+2}.10=270\)

\(3^{x+2}=27\)

⇒x+2=3

⇒x=1

3^x+1 + 3^x+2 - 2 x 3^x = 270

3^x ( 3 + 3² - 2) = 270

3^x . 10 = 270

3^x = 270 : 10

3^x = 27

3^x = 3³

x = 3

\(3^{x+1}+3^{x+2}-2.3^x=270\)

\(\Leftrightarrow3.3^x+3^2.3^x-2.3^x=270\)

\(\Leftrightarrow\left(3+3^2-2\right).3^x=270\)

\(\Leftrightarrow10.3^x=270\)

\(\Leftrightarrow3^x=27\)

\(\Leftrightarrow3^x=3^3\)

\(\Leftrightarrow x=3\)

a.\(2^x-2^4.2^7.32=0\)
\(2^x-2^{16}=0\)
\(=>x=16\)
b.\(3^x+3^{x+2}=270\)
\(3^x+3^x.3^2=270\)
\(3^x.10=270\)
\(3^x=27\)
\(=>x=3\)
 

\(\Leftrightarrow3^x=27\)

hay x=3

\(\Leftrightarrow3^x+3^x.3^2=270\Leftrightarrow3^x.10=270\\\Leftrightarrow3^x=3^3\Leftrightarrow x=3\)

x²-3x-270=0 

<=> x^2 - 18x + 15x - 270 = 0

<=> x(x - 18) + 15(x - 18) = 0

<=> (x + 15)(x - 18) = 0

<=> x = - 15 hoặc x = 18

vậy_

kết bạn nhé ^^

\(x^2 -3x-270=0\)

\(\Leftrightarrow\)\(( x^2 -18x) + ( 15x-270)=0\)

\(\Leftrightarrow\)\(x. (x-18)+15. (x-18)=0\)

\(\Leftrightarrow\)\((x-18)(x+15)=0\)

\(\Rightarrow\)\(x =18\)  hoặc \(x=-15\)

       x² -3x-270=0 

<=> x² - 18x + 15x - 270 = 0

<=> x(x - 18) + 15(x - 18) = 0

<=> (x + 15)(x - 18) = 0

<=> x = - 15 hoặc x = 18

Vậy......................................

324-3x=270:15

=>324-3x=18

=>3x=324-18

=>3x=306

=>x=306:3=102

Chọn D

Theo NTBS có : X=G=270 (nu)

=> 

X=G=270 (nu) => A = 1 3 X = 1 3 G = 1 3 .270 = 90 ( n u ) Ta có : H= 2A+ 3G= 2.90+3.270=990 (liên kết 

chắc v 

\(x-\left(270:45\right)=120\)

=> \(x-6=120\)

=> \(x=126\)

Đề cậu viết kiểu gì á

#Hoctot

~ Kill ~

    x-270:45=120

=>x-6=120

=>x=120+6

=>x=126

  Vậy x=126

Trả lời:

x - 270 : 45 = 120

x - 270        = 120 . 45

x - 270        = 5400

x                 = 5400 + 270 

x                = 5670

a: \(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=2\end{matrix}\right.\)