a)  ( 135 − 35 ) . ( − 37 ) + 37 ( − 41 − 59 ) = − 100.37 + 37 − 100 = 37 − 100 − 100 = 37 − 200 = − 7400.

b)  − 65 ( 87 − 17 ) − 87 ( 17 − 65 ) = − 65.87 + 65.17 − 87.17 + 87.65 = 87.65 − 65.87 + 17 65 − 87 = 0 + 17. − 22 = − 374.

c)  3 ( − 2 ) − ( − 8 ) . ( − 7 ) − ( − 2 ) . ( − 5 ) = − 6 + 8 . − 7 + 2 = 2. − 7 + 2 = − 12

a)135-35.(-37)+37.(-42-48)=-4490

b)-65.(87-17)-87.(17-65)=-374

= 65 x ( 121 + 11) - 35 x ( 17 + 115 ) 

= 65 x 132 - 35 x 132 

= ( 65 - 35) x 132 

= 30 x 132 

= 3960

65x121-35x17+11x65-115x35=3.960

\(65\cdot121-35\cdot17+11\cdot65-115\cdot35\)

\(=65\cdot\left(11+121\right)-35\cdot\left(115+17\right)\)

\(=65\cdot132+35\cdot132\)

\(=132\cdot\left(65+35\right)\)

\(=132\cdot100\)

\(=13200\)

a) Ta có: \(\left(-65\right)\cdot\left(87-17\right)-87\cdot\left(17-65\right)\)

\(=-65\cdot87+65\cdot17-87\cdot17+87\cdot65\)

\(=17\left(65-87\right)=17\cdot\left(-22\right)=-374\)

b) Ta có: \(\left(135-35\right)\cdot\left(-37\right)+37\cdot\left(-42-58\right)\)

\(=\left(-100\right)\cdot37+37\cdot\left(-100\right)\)

\(=37\left(-100-100\right)=37\cdot\left(-200\right)=-7400\)

-35+87-65-105-17+05

=-35+87+(-65)+(-105)+(-17)+5

=[-35+(-65)]+[-105+5]+[87+(-17)]

=-100+(-100)+70=-130

Chắc thế 

a, (135-35).(-37)+37.(-42-58)

= 100.(-37)+37.(-100)

= 100.(-37)+(-37).100

= (-37).(100+100)

= (-37).200

= -7400

b, -65.(87-17)-87.(17-65)

= -65.70-87.(-48)

= -4550+4176

=-374

c, [3.(-2)-(-8)].(-7)-(-2).(-5)

= [(-6)+8].(-7)+(-10)

= 2.(-17)

= -34

2 . x - 1300 : ( 65 + 35 ) = 17

2 . x - 1300 : 100 = 17

2. x - 13 = 17

2 . x         = 17 + 13

2 . x         = 30

    x          = 30 : 2

     x         = 15

17/24x15/34=5/16

25/35x14/65=2/13

\(\frac{17}{24}\times\frac{15}{34}=\frac{17\times15}{24\times34}=\frac{5}{16}\)

\(\frac{26}{35}\times\frac{14}{65}=\frac{26\times14}{35\times65}=\frac{4}{25}\)

Học tốt~

\(\frac{17}{24}\)x \(\frac{15}{34}\)= \(\frac{1}{8}\)x \(\frac{5}{2}\)= \(\frac{5}{16}\)

\(\frac{26}{35}\)x \(\frac{14}{65}\)= \(\frac{2}{5}\)x \(\frac{2}{5}\)= \(\frac{4}{25}\)