3⁸:3⁴+2²:2³=81,5

3.4²-2.3²=30

(4⁶.3⁴.9³):6¹²=1/9

3⁸:3⁴+2²:2³=3^8-4+2^2-3=3⁴+2^-1=81+0,5=81,5

3.4²-2.3²=3.4²-2.3.3=3.4²-6.3=3.(4²-6)=3.10=30

(4⁶.3⁴.9³):6¹²=(4⁶.3⁴.3⁶):6¹²=(4⁶.3⁴⁺⁶):6¹²=(2¹².3¹⁰):6¹²=\(\frac{2^{12}.3^{10}}{6^{12}}\)=\(\frac{1}{9}\)

=3^8-6+2^2-3=3^2+2^-1=9+0.5=9.5

=3*16-2*9=48-18=30

=(4^6*3^4*9^3)/(3^2*4^6*9^3*3^4)=1/9=\(\frac{1}{9}\)

Ta có : \(C=\dfrac{4^6.3^4.9^5}{6^{12}}=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=3^{4+10-12}=3^2=9\)

\(C=\dfrac{4^6\cdot3^4\cdot9^5}{6^{12}}=\dfrac{2^{12}\cdot3^4\cdot3^{10}}{3^{12}\cdot2^{12}}=3^2=9\)

\(C=\dfrac{4^6.3^4.9^5}{6^{12}}\) 

\(C=\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}\) 

\(C=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}\) 

\(C=\dfrac{2^{12}.3^{14}}{2^{12}.3^{12}}\) 

\(C=3^2=9\)

B = 4^9.36+64^4
       16^4.100
B = 2^20.(9+16)
       2^18.5^2
B = 2^20.5^2
      2^18.5^2
B = 2^2
B = 4

D = 4^6.3^4.9^5
           6^12
D = 2^12.3^4.9^5
        2^12.3^12
D = 2^12.3^14
       2^12.3^12
D = 3^2
D = 9

\(\frac{4^9.36+64^4}{16^4.100}=\frac{4^{10}\left(9+8\right)}{4^{10}.25}=\frac{17}{25}\)

cảm ưn các bn nhìu

a, \(\dfrac{3^8}{3^4}+2^2.2^3\)
= 3⁴ + 2⁵
= 113
b, 3.4² - 2.3²
= 3.(4² - 2.3)
= 3.(16 - 6)
= 3.10
= 30
c, \(\dfrac{4^6.3^4.9^5}{6^{12}}\)

= \(\dfrac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}\)

= \(\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}\)

= \(\dfrac{3^{14}}{3^{12}}\)

= 3²
@Dương Tuyết Mai

\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{2^{12}.3^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)

\(\frac{4^6\cdot3^4\cdot9^5}{6^{12}}\)

\(=\frac{2^{12}\cdot3^4\cdot3^{10}}{2^{12}\cdot3^{12}}\)

\(=\frac{1\cdot3^{14}}{1\cdot3^{12}}\)

\(=\frac{3^{14}}{3^{12}}\)

\(=3^2\)

\(=9\)

\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}+\frac{16^3.3^{10}+120.6^9}{4^6.3^{12}+6^{12}}\)

\(=\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^{12}.3^6+\left(2^3\right)^4.3^5}-\frac{\left(2^4\right)^3.3^{10}+2^3.3.5.\left(2.3\right)^9}{\left(2^2\right)^6.3^{12}+\left(2.3\right)^{12}}\)

\(=\frac{2^{12}.3^5-2^{12}.3^4}{2^{12}.3^6-2^{12}.3^5}-\frac{2^{12}.3^{10}-2^3.3.5.2^9.3^9}{2^{12}.3^{12}+2^{12}.3^{12}}\)

\(=\frac{2^{12}.\left(3^5-3^4\right)}{2^{12}.\left(3^6-3^5\right)}-\frac{2^{12}.3^{10}-2^{12}.3^{10}.5}{2^{12}.3^{12}+2^{12}.3^{12}}\)

\(=\frac{3^5-3^4}{3^6-3^5}-\frac{2^{12}.3^{10}.\left(1-5\right)}{2^{13}.3^{12}}\)

\(=\frac{162}{486}-\frac{2^{12}.3^{10}.\left(-4\right)}{2^{13}.3^{10}.3^2}=\frac{1}{3}-\frac{2^{14}.3^{10}.\left(-1\right)}{2^{13}.3^{10}.9}\)

\(=\frac{1}{3}-\frac{2.1.\left(-1\right)}{1.1.9}=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)

a.3^8:3^4+2^2.2^3

=3^4+2^5

=81+32

=113

b.2^8+4.135+175:25

=256+540+7

=256+547

=803

mấy bài kia bn cứ làm như thế nha!

mik biết nhưng ko thể trả lời hết