`a,`

`x*3+7=16`

`=>3x = 16 - 7`

`=> 3x = 9`

`=> x = 9 \div 3`

`=> x = 3`

Vậy, `x = 3`

`b,`

` x- 152 \div 2 = 46?`

`=> x - 76 = 46`

`=> x = 46 + 76`

`=> x = 122`

Vậy, `x = 122.`

`c,`

` 74-2*(x+3)=34`

`=> 2(x + 3) = 74 - 34`

`=> 2(x+2) = 40`

`=> x + 2 = 40 \div 2`

`=> x + 2 = 20`

`=> x = 20 - 2`

`=> x = 18`

Vậy, `x = 18.`

\(\dfrac{x}{2}=\dfrac{y}{5};\dfrac{y}{3}=\dfrac{z}{4}\Rightarrow\dfrac{x}{6}=\dfrac{y}{15}=\dfrac{z}{20}\)

Áp dụng tc dstbn:

\(\dfrac{x}{6}=\dfrac{y}{15}=\dfrac{z}{20}=\dfrac{2x+3y-2z}{6\cdot2+3\cdot15-2\cdot20}=\dfrac{34}{17}=2\\ \Rightarrow\left\{{}\begin{matrix}x=12\\y=30\\z=40\end{matrix}\right.\)

Lời giải:

$\frac{x}{2}=\frac{y}{5}; \frac{y}{3}=\frac{z}{4}$

$\Rightarrow \frac{x}{6}=\frac{y}{15}=\frac{z}{20}$

Áp dụng TCDTSBN:

$\frac{x}{6}=\frac{y}{15}=\frac{z}{20}$

$=\frac{2x}{12}=\frac{3y}{45}=\frac{2z}{40}=\frac{2x+3y-2z}{12+45-40}=\frac{34}{17}=2$

$\Rightarrow x=2.6=12; y=2.15=30; z=2.20=40$

câu c là j vậy e chỗ 34,72 32,28 và câu e chỗ 12,34 (5,36)

c)34, 72 32,28 : 5 – 57,25 – 36, 05 : 2

=(34,72+32,28):5-(57,25-36,05):2

=67 : 5 - 21,2 : 2

=13,4 - 10,6

=2,8

e)5, 36.12, 34 ( 5, 36).2, 34

=5,36.12,34−5,36.2,34

=5.36.(12,34−2,34)

=5,36.10

=53,6

b ) -2(3x+2)-3 =28

-6x-4-3=28

-6x = 28 +4+3

-6x = 35

x =\(\dfrac{35}{-6}\)= \(\dfrac{-35}{6}\)= -5,8

vậy x= -5,8

c ) -(x+3)-5(x-7)=10x-20

-(x+3)-5x+35=10x-20

-x+3-5x+35=10x-20

-x-5x-10x=-20-3-35

-16x=-58

x=\(\dfrac{-58}{-16}\)=\(\dfrac{58}{16}\)=3,625

vậy x =3,625

d)2x+37=-6(3x-8)

2x+37=-18x+48

2x+18x=48-37

20x=11

x=\(\dfrac{11}{20}\)=0,55

vậy x=0,55

\(6-\left(3x-\frac{1}{3}\right)=2x+\frac{1}{3}\)

\(\Leftrightarrow6-\left(3x-\frac{1}{3}\right)-2x-\frac{1}{3}=0\)

\(\Leftrightarrow6-3x+\frac{1}{3}-2x-\frac{1}{3}=0\)

\(\Leftrightarrow-5x+6=0\)

\(\Leftrightarrow6=5x\)\(\Leftrightarrow x=\frac{6}{5}\)

Học tút!

Cảm ơn bn nhìu nawmsmmm !!!

\(6-3x+\frac{1}{3}=2x+\frac{1}{3}\)

\(6-3x-2x=\frac{1}{3}+\frac{1}{3}\)

\(6-5x=\frac{2}{3}\)

\(5x=6-\frac{2}{3}\)

\(x=\frac{16}{3}:5\)

\(x=\frac{16}{3}\times\frac{1}{5}\)

\(x=\frac{16}{15}\)

(3x -48) .6 =3^2 . 2^2 + 2^3 . 3^2 - 12

(3x-48) .6 =3^2(2^2+2^3) -12

(3x-48) .6 =3^2.12-12

(3x-48) .6 =9.12-12

(3x-48) .6 =8.12

(3x-48) .6 =96

3x-48 =96:6

3x-48=16

3x=16+48

3x=64

x=64:3

x=64/3

\(a,3x-6=5x+2\)

 \(3x-5x=2+6\)

        \(-2x=8\)

              \(x=-4\)

\(b,2\times\left(x-3\right)-3\times\left(x+7\right)=14\)

                        \(2x-6-3x-21=14\)

                                          \(-x-27=14\)

                                                         \(x=-27-14\)

                                                         \(x=-41\)

a) 3x - 6 = 5x + 2

   3x - 6 - 2 = 5x

   3x - 8 = 5x

   3x - 5x = 8

   -2x = 8

   x = -4

b) 2(x - 3) - 3(x + 7) = 14

2x - 6 - 3x - 21 = 14

(-x) - 27 = 14

(-x) = 41

x = -41

c) 3x² - x - 2 = 0

x.(3x - 1) = 2

x.(3x - 1) = 2 = 1.2 = 2.1 = (-1).(-2) = (-2).(-1)

Xét 4 trường hợp ,ta có :

\(\left(1\right)\hept{\begin{cases}x=1\\3x-1=2\end{cases}\Rightarrow\hept{\begin{cases}x=1\\x=1\end{cases}}}\)(nhận)

\(\left(2\right)\hept{\begin{cases}x=2\\3x-1=1\end{cases}\Rightarrow\hept{\begin{cases}x=2\\x=\frac{2}{3}\end{cases}}}\)(loại)

\(\left(3\right)\hept{\begin{cases}x=-1\\3x-1=-2\end{cases}\Rightarrow\hept{\begin{cases}x=-1\\x=-\frac{1}{3}\end{cases}}}\)(loại)

\(\left(4\right)\hept{\begin{cases}x=-2\\3x-1=-1\end{cases}\Rightarrow\hept{\begin{cases}x=-2\\x=0\end{cases}}}\)(loại)

\(3x-6=5x+2\)

\(\Rightarrow-2x=8\)

\(\Rightarrow x=-4\)

b) 

a) (x-2)³+6(x+1)²-x³+12=0

\(\Rightarrow\)x³-6x²+12x-8+6(x²+2x+1)-x³+12=0

\(\Rightarrow\)x³-6x²+12x-8+6x²+12x+6-x³+12=0

\(\Rightarrow\)24x+10=0

\(\Rightarrow\)24x=-10

\(\Rightarrow\)x=\(\dfrac{-10}{24}=\dfrac{-5}{12}\)

b)(x-5)(x+5)-(x+3)²+3(x-2)²=(x+1)²-(x-4)(x+4)+3x²

\(\Rightarrow\)x²-25-(x²+6x+9)+3(x²-4x+4)=x²+2x+1-(x²-16)+3x²

\(\Rightarrow\)x²​-25-x²-6x-9+3x²-12x+12=x²+2x+1-x²+16+3x²

\(\Rightarrow\)3x²-18x-22=3x²+2x+17

\(\Rightarrow\)3x²-18x-22-3x²-2x-17=0

\(\Rightarrow\)-20x-39=0

\(\Rightarrow\)-20x=39

\(\Rightarrow\)x=\(-\dfrac{39}{20}\)

c) (2x+3)² +(x-1)(x+1)=5(x+2)²-(x-5)(x+1)+(x+4)

⇒4x²+12x+9+x²-1=5(x²+4x+4)-(x²+x-5x-5)+x+4

⇒5x²+12x+8=5x²+20x+20-x²-x+5x+5+x+4

⇒5x²+12x+8-5x²-20x-20+x²+x-5x-5-x-4=0

⇒x²-13x-21=0