\(\frac{22}{3}:2=?\)
Những câu hỏi liên quan
\(\frac{3}{2}+\frac{3}{^22}+\frac{3}{^32}+...+\frac{3}{^{2020}2}\)
gọi bt \(\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{2020}}\) là A ta có:
A=\(\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{2020}}\)
\(\Rightarrow2A=3+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^{2019}}\)
\(\Rightarrow2A-A=\left(3+\frac{3}{2}+\frac{3}{2^2}+...+\frac{3}{2^{2019}}\right)-\left(\frac{3}{2}+\frac{3}{2^2}+\frac{3}{2^3}+...+\frac{3}{2^{2020}}\right)\)
\(\Rightarrow A=3-\frac{3}{2^{2020}}\)
Tính:\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
B=\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
B=522+313−12413−211+32
Đặt \(S=\frac{5}{22}+\frac{3}{13}-\frac{1}{2}\)
=> S= \(\frac{-6}{143}\)
Đặt \(H=\frac{4}{13}-\frac{2}{11}+\frac{3}{2}\)
=> H = \(\frac{465}{286}\)
Khi đó B = \(\frac{\frac{-6}{143}}{\frac{465}{286}}\)=\(\frac{-4}{155}\)
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\(\left(\frac{7}{2}-2.x\right).\frac{10}{3}=\frac{22}{3}\)
\(\left(\frac{7}{2}-2.x\right).\frac{10}{3}=\frac{22}{3}\)
\(\left(\frac{7}{2}-2.x\right)=\frac{22}{3}:\frac{10}{3}\)
\(\left(\frac{7}{2}-2.x\right)=\frac{11}{5}\)
\(2.x=\frac{7}{2}-\frac{11}{5}\)
\(2.x=\frac{13}{10}\)
\(x=\frac{13}{10}:2\)
\(x=\frac{13}{20}\)
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\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}=?\)
\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}=\frac{\left(\frac{5}{22}+\frac{3}{13}-\frac{1}{2}\right)\times286}{\left(\frac{4}{13}-\frac{2}{11}+\frac{3}{2}\right)\times286}=\frac{65+66-143}{88-52+429}=-\frac{12}{465}=-\frac{4}{155}\)
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a,\(\left\{\frac{2}{3}\right\}^3-\left\{\frac{3}{4}\right\}^2.\left\{-1\right\}^5\)
b,\(12:\left\{\frac{3}{4}-\frac{5}{6}\right\}^2\)
c,\(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}\)
d,\(\frac{12}{35}.\left\{\frac{7}{4}+\frac{13}{4}\right\}-\frac{1}{3}\)
a. \(\left(\frac{2}{3}\right)^3-\left(\frac{3}{4}\right)^2.\left(-1\right)^5=\frac{8}{27}-\frac{9}{16}.\left(-1\right)=\frac{8}{27}+\frac{9}{16}=\frac{371}{432}\)
b. \(12:\left(\frac{3}{4}-\frac{5}{6}\right)^2=12:\left(-\frac{1}{12}\right)^2=12:\frac{1}{144}=12.144=1728\)
c. \(\frac{7}{22}:\frac{3}{11}+\frac{7}{22}:\frac{4}{11}=\frac{7}{22}.\frac{11}{3}+\frac{7}{22}.\frac{11}{4}=\frac{7}{22}\left(\frac{11}{3}+\frac{11}{4}\right)\)
\(=\frac{7}{22}.\frac{77}{12}=\frac{49}{24}\)
d. \(\frac{12}{35}\left(\frac{7}{4}+\frac{13}{4}\right)-\frac{1}{3}=\frac{12}{35}.5-\frac{1}{3}=\frac{12}{7}-\frac{1}{3}=\frac{29}{21}\)
\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
tính bằng 2 cách
tính bằng 2 cách
\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
Tính\(\frac{\frac{5}{22}+\frac{3}{13}-\frac{1}{2}}{\frac{4}{13}-\frac{2}{11}+\frac{3}{2}}\)
Tìm x:
\(\frac{-22}{15}x+\frac{1}{3}=|\frac{-2}{3}+\frac{2}{5}|\)
\(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{2}{5}\right|\)
\(\Rightarrow-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{4}{15}\right|\).
\(\Rightarrow-\frac{4}{15}=\pm\left(-\frac{22}{15}x+\frac{1}{3}\right)\)
\(\Rightarrow\orbr{\begin{cases}-\frac{22}{15}x+\frac{1}{3}=-\frac{4}{15}\\-\left(-\frac{22}{15}x+\frac{1}{3}\right)=-\frac{4}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{9}{22}\\x=\frac{1}{22}\end{cases}}\)
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༃•๖ۣۜLãσ ๖ۣۜHạ¢ Em bị nhầm dạng toán này rồi. Khi ẩn x ở trong dấu giá trị tuyệt đối mình mới chia hai trường hợp em nhé!
Bài giải:
\(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{4}{15}\right|\)
\(-\frac{22}{15}x+\frac{1}{3}=\frac{4}{15}\)
\(-\frac{22}{15}x=\frac{4}{15}-\frac{1}{3}\)
\(-\frac{22}{15}x=-\frac{1}{15}\)
\(\frac{22x}{15}=\frac{1}{15}\)
\(x=\frac{1}{22}\)
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