Giúp mình với nha.... Đang gấp ai nhanh mik k cho...
2/1.2.3 + 2/2.3.4 + 2/3.4.5 + ....... + 2/48.49.50
CẤP BÁCH...CẤP BÁCH..GIÚP VỚI
M= 2/1.2.3 + 2/2.3.4 + 2/3.4.5 + ....... + 2/48.49.50
Ai nhanh mik k cho nhea
mắc j k... bn biết mà mik k biết thì mik hỏi chứ... VÔ DUYÊN
M= 2/1.2.3 + 2/2.3.4 + 2/3.4.5 +......... + 2/48.49.50
AI NHANH MÌK K CHO
AI K MÌK MÌK K LẠI CHO NHEA
\(M=\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{48.49.50}\)
\(M=\frac{1}{1.2}-\frac{1}{2.3}+\frac{2}{2.3}-\frac{1}{3.4}+...+\frac{1}{48.49}-\frac{1}{49.50}\)
\(M=\frac{1}{1.2}-\frac{1}{49.50}\)
\(M=\frac{1}{2}-\frac{1}{2450}=\frac{612}{1225}\)
Tinh nhanh
A= \(1.2.3+2.3.4+3.4.5+...+48.49.50\)
B = \(1.2.3+2.3.4+3.4.5+...+n.\left(n+1\right).\left(n+2\right)\)
A = 1.2.3 + 2.3.4 + ....+ 48.49.50
=> 4A = 1.2.3.4 + 2.3.4.(5-1) + ...+ 48.49.50.(51-17)
= 1.2.3.4 + 2.3.4.5 - 1.2.3.4 + .....+ 48.49.50.51 - 47.48.49.50
= 48.49.50.51
=> A = 48.49.50.51:4 = 12.49.50.51
bài b) làm tương tự nha
giúp mk gấp vs nhé
Tính C=1.2.3+2.3.4+3.4.5+...+48.49.50
\(C=1.2.3+2.3.4+...+48.49.50\)
\(\Rightarrow4C=1.2.3.4+2.3.4.4+...+48.49.50.4\)
\(=1.2.3.4+2.3.4.\left(5-1\right)+...+48.49.50.\left(51-47\right)\)
\(=1.2.3.4+2.3.4.5-1.2.3.4+...+48.49.50.51-47.48.49.50\)
\(=48.49.50.51\)
\(\Rightarrow C=\frac{48.49.50.51}{4}=1499400\)
P = 1/1.2.3 + 1/2.3.4 + 1/3.4.5 +...+ 1/n(n+1)(n+2)
S = 1/1.2.3 + 1/2.3.4 + 1/3.4.5 +...+ 1/48.49.50 .
tao có:
2p=2/1.2.3+2/2.3.4+...+2/n.n(+1)n(n+2)
2p=3-1/1.2.3+4-2/1.2.3+...+(n+2)-n/n.(n+1).(n+2)
2p=3/1.2.3-1/1.2.3+4/2.3.4-2/2.3.4+...+(n+2)/n.(n+1).(n+2)-n/n.(n+1).(n+2)
2p=1/1.2-1/2.3+1/2.3-1/3.4+...+1/n.(n+1)-1/(n+1).(n+2)
2p=1/1.2-1/(n+1).(n+2)
2p=(n+!).(n+2)-2/(2n+2).(n+2)
suy ra p=(n+1).(n+2)-2/(2n+2).(2n+4)
2s=3-1/1.2.3+4-2/1.2.3+...+50-48/48.49.50
2s=3/1.2.3-1/1.2.3+4/2.3.4-2/2.3.4+...+50/49.50.48-48/48.50.49
2s=1/1.2-1/2.3+1/2.3-1/3.4+...+1/48.49-1/49.50
2s=1/1.2-1/49.50
'2s=1/2-1/2450
2s=1225/2450-1/2450
2s=1224/2450
s=612/1225
\(P=\frac{1}{1\cdot2\cdot3}+\frac{1}{2\cdot3\cdot4}+\frac{1}{3\cdot4\cdot5}+...+\frac{1}{n\left(n+1\right)\left(n+2\right)}\)1
\(P=\frac{1}{2}\left(\frac{2}{1\cdot2\cdot3}+\frac{2}{2\cdot3\cdot4}+\frac{2}{3\cdot4\cdot5}+...+\frac{2}{n\left(n+1\right)\left(n+2\right)}\right)\)
\(P=\frac{1}{2}\left(\frac{1}{1\cdot2}-\frac{1}{2\cdot3}+\frac{1}{2\cdot3}-\frac{1}{3\cdot4}+\frac{1}{3\cdot4}-\frac{1}{4\cdot5}+...+\frac{1}{n\left(n+1\right)}-\frac{1}{\left(n+1\right)\left(n+2\right)}\right)\)
\(P=\frac{1}{2}\left(\frac{1}{2}-\frac{1}{\left(n+1\right)\left(n+2\right)}\right)\)
\(P=\frac{\left(\frac{1}{2}-\frac{1}{\left(n+1\right)\left(n+2\right)}\right)}{2}\)
S cx tinh giong v
mí bạn giải cho mình bài này với
a) A= 1.5+2.6+3.7+...+30.34
b) B= 2^2+4^2+6^2+...+20^2
c) C= (1.2+2.3+3.4+...+20.21) - (1^2 +2^2+...+20^2)
d) D= 1.2.3+2.3.4+3.4.5+...+20.21.22
e) E= 10.11+11.12+12.13+...+28.29
giúp mình nha
mình đang cần gấp
mình cần lời giải rõ ràng
ai làm đúng mình tick cho
I don't now
mik ko biết
sorry
......................
b,\(B=2^2+4^2+...+20^2\)
\(\Rightarrow B=2^2\left(1^2+2^2+...+10^2\right)\)
\(\Rightarrow B=4.\left[1.\left(2-1\right)+2.\left(3-1\right)+...+10.\left(11-1\right)\right]\)
\(\Rightarrow B=4\left(1.2-1+2.3-2+...+10.11-10\right)\)
\(\Rightarrow B=4\left[\left(1.2+2.3+...+10.11\right)-\left(1+2+...+10\right)\right]\)
\(\Rightarrow B=4\left(\frac{10.11.12}{3}-\frac{11.10}{2}\right)\)
c)C=(1.2+2.3+3.4+...+20.21)-(12+22+32+...+202)
=>C=1.2+2.3+3.4+...+20.21-1.1-2.2-3.3-...-20.20
=>C=1.(2-1)+2.(3-2)+3.(4-3)+...+20.(21-20)
=>C=1+2+3+...+20
=>C=(1+20)+(2+19)+...+(15+16)
=>C=21+21+...+21
=>C=21.10
=>C=210
a) A = 1.3 + 2.4 + 3.5 +...+ 97.99 + 98.100
b) B = 1.2.3 + 2.3.4 + 3.4.5 +...+ 48.49.50
c) C = 1/2 + 1/2^2 + 1/2^3 +...+ 1/2^10
a) A = 1.3 +2.4 + 3.5 +...+ 97.99 + 98.100
A = 1(2 + 1) + 2(3+1) + 3(4 + 1) +...+ 98(99+1)
= (1.2 + 2.3 + 3.4 +...+ 98.99) + (1 + 2 + 3 +...+ 98)
= [ 1.2.3 + 2.3.(4-1) +...+ 98.99.(100-97)] + [ 1.2 + 2.(3-1) + 3.(4-2) +... 98.(99-97)]
= [ 1.2.3 + 2.3.(4-1) - 1.2.3 + 3.4.(5-2) - 2.3.(4-1) +...+ 98.99.(100-97) - 97.98(99-96)] + [ 1.2 + 2.(3-1) - 1.2 + 3.(4-2) - 2.(3-1) +...+ 98.(99-97) - 97(98-96)]
= 98.99.100:3 + 98.99:2 = 323 400 + 4581 = 328251
b) B = 1.2.3 + 2.3.4 + 3.4.5 +...+ 48.49.50
4B = 1.2.3.4 + 2.3.4.(5-1) + 3.4.5.(6-2) +...+ 48.49.50.(51-47)
4B-B = 1.2.3.4 + 2.3.4.(5-1) - 1.2.3.4 + 3.4.5.(6-2) - 2.3.4.(5-1) +...+ 48.49.50.(51-47) - 47.48.49.(50-46)
= 48.49.50.51:4 = 1499400
c) C = 1/2 + 1/2^2 + 1/2^3 +...+ 1/2^10
=> 2C = 1 + 1/2 + 1/2^2 +...+ 1/2^9 (1)
= 1/2 + 1/2^2 +...+ 1/2^10
Lấy (1)-(2) ta được:
A = 1-1/2^10 = 1024/1024 - 1/1024 = 1023/1024
Chúc bạn học tốt
Áp dụng phương pháp để tính các biểu thức sau :
a) A = 1.3 + 2.4 + 3.5 + ...... + 97.99 + 98.100
b) B = 1.2.3 + 2.3.4 + 3.4.5 + ........ + 48.49.50
AI giải nhanh mình sẽ tick
a) A = 1.( 2 + 1 ) + 2.( 3 + 1 ) + 3.( 4 + 1 ) + ...+ 98.( 99 + 1 )
A = 1.2 + 1 + 2.3 + 2 + 3.4 + 3 + ... + 98.99 + 98
A = ( 1.2 + 2.3 + 3.4 + ... + 98.99 ) + ( 1 + 2 + 3 + 4 + ... + 98 )
Dat B = 1.2 + 2.3 + 3.4 + ...+ 98.99
C = 1 + 2 + 3 + 4 + ... + 98
=> 3B = 1.2.3 + 2.3.3 + 3.4.3 + ...+ 98.99.3
= 1.2.3 + 2.3.( 4 - 1 ) + 3.4.( 5 - 2 ) + ....+ 98.99.( 100 - 97 )
= 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 98.99.100 - 97.98.99
=> B = ( 98.99.100 ) : 3 = 323400
=> C = 1 + 2 + 3 + ... 98
C = 98 + 97 + ...+ 3 + 2 + 1
Tu lam tiep nha
a)
A= 1.2 +1.2.3+2+3.4+3+......98.99+98
A=(1.2+2.3+3.4+........98.99)+(1+2+3+4+...98)
A= 1.2.3+2.3.4+3.4.5+..........+48.49.50
\(A=1.2.3+2.3.4+3.4.5+...+48.49.50\)
\(4A=1.2.3.4+2.3.4.4+3.4.5.4+...+48.49.50.4\)
\(4A=1.2.3.\left(4-0\right)+2.3.4.\left(5-1\right)+...+48.49.50.\left(51-47\right)\)
\(4A=1.2.3.4-0.1.2.3+2.3.4.5-1.2.3.4+...+48.49.50.51-48.48.49.50\)
\(4A=48.49.50.51\)
\(A=\dfrac{48.49.50.51}{4}=1499400\)
4A=4.[1.2.3 + 2.3.4 + 3.4.5 + 4.5.6 + . . . . . . + 48.49.50]
4A=1.2.3.4 +2.3.4.4 +3.4.5.4 +4.5.6.4 +.........+48.49.50.4
4A=1.2.3.4 +2.3.4.(5-1) + 3.4.5.(6-2) +4.5.6(7-3)+....+ 48.49.50(51-47)
4A=1.2.3.4 +2.3.4.5 --1.2.3.4 + 3.4.5.6--2.3.4.5 + 4.5.6.7-3.4.5.6+....+ 48.49.50.51--47.48.49.50
4A =48.49.50.51
A=(48.49.50.51)/4