\(\dfrac{5}{22}+\dfrac{4}{11}=\dfrac{5}{22}+\dfrac{8}{22}=\dfrac{13}{22}\)

\(\dfrac{5}{22}+\dfrac{4}{11}=\dfrac{5}{22}+\dfrac{4\times2}{11\times2}=\dfrac{5}{22}+\dfrac{8}{22}=\dfrac{5+8}{22}=\dfrac{13}{22}\)

\(\dfrac{5}{22}+\dfrac{4}{11}=\dfrac{5}{22}+\dfrac{8}{22}=\dfrac{5+8}{22}=\dfrac{13}{22}\)

\(\dfrac{11}{3}-\dfrac{3}{11}=\dfrac{121}{33}-\dfrac{99}{33}=\dfrac{121-99}{33}=\dfrac{22}{33}\)

7/15+ 12/15 = 19/15

4/5 x 3/1 = 12/5

16/24- 9/24 = 7/24

1/2: 4/1 = 1/2 x 1/4= 1 /8

Đổi : \(30km=3000000cm\) 

Độ dài thu nhỏ :

\(3000000:10000=300\left(cm\right)\)

Đổi : \(20m=20000mm\)

Độ dài thu nhỏ :

\(20000:5000=4000\left(mm\right)\)

Đổi \(10m=1000m\)

Độ dài thu nhỏ :

\(1000:200=500\left(cm\right)\)

Đổi : \(2km=20000dm\)

Độ dài thu nhỏ :

\(20000:20000=1\left(dm\right)\)

c)\(=\dfrac{5\times17\times2}{17\times5\times2}=1\)

\(=\dfrac{99}{33}=3\)

d)\(=4\times\dfrac{16}{3}=\dfrac{64}{3}\)

còn lại ko nhìn đc

\(\dfrac{5}{17}\times\dfrac{34}{25}=\dfrac{5\times17\times2}{17\times5\times5}=\dfrac{2}{5}\)

\(\dfrac{5}{17}\times\dfrac{34}{25}=\dfrac{5\times34}{17\times25}=\dfrac{170}{425}=\dfrac{2}{5}\)

2/5

=14*17*28/270

=6664/270=3332/135

Chiều dài thực tế của lớp học là: 500x2=1000(cm)
Đổi 1000cm --> 10m

Chiều dài lớp học :

\(500\times2=1000\left(cm\right)\)

Đổi : \(1000cm=10m\)

a.\(y:\dfrac{4}{5}=\dfrac{11}{8}\)

\(y=\dfrac{11}{8}\times\dfrac{4}{5}\)

\(y=\dfrac{11}{10}\)

b.\(\dfrac{11}{3}-y=\dfrac{1}{9}\)

\(y=\dfrac{11}{3}-\dfrac{1}{9}\)

\(y=\dfrac{32}{9}\)

c.\(\dfrac{1}{7}\times x=\dfrac{8}{5}\)

\(x=\dfrac{8}{5}:\dfrac{1}{7}\)

\(x=\dfrac{56}{5}\)

\(y=\dfrac{11}{8}.\dfrac{4}{5}\)

\(y=\dfrac{44}{40}\)

\(x=\dfrac{11}{3}-\dfrac{1}{9}\)

\(x=\dfrac{99-3}{27}=\dfrac{96}{27}\)

\(x=\dfrac{8}{5}:\dfrac{1}{7}\)

\(x=\dfrac{56}{5}\)

a)\(y=\dfrac{4}{5}\times\dfrac{11}{8}=\dfrac{44}{40}=1\dfrac{4}{40}\)

b)\(y=\dfrac{11}{3}-\dfrac{1}{9}=\dfrac{33}{9}-\dfrac{1}{9}=\dfrac{32}{9}\)

c)\(x=\dfrac{8}{5}\times7=\dfrac{56}{5}\)