= 4,32 x (1,2 + 1,3 + 0,1 + 1) = ...

(đến đó dễ rùi bn tự giải nhé)

cảm ơn bn Ngô Hoàng Thạch nha

`|x-2|=3-x`

`@TH1:x-2 >= 0<=>x >= 2=>|x-2|=x-2`

    `=>x-2=3-x`

`<=>2x=5`

`<=>x=5/2` (t/m)

`@TH2:x-2 < 0<=>x < 2=>|x-2|=2-x`

    `=>2-x=3-x`

`<=>0x=1` (Vô lí)

Vậy `S={5/2}`

\(\left|x-2\right|=3-x\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=3-x\\x-2=x-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-2-3+x=0\\x-2-x+3=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-5=0\\\left(x-x\right)+\left(-2+3\right)=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\1=0\left(vl\right)\end{matrix}\right.\)

\(=>x=\dfrac{5}{2}\)

 (t/m)

 (Vô lí)

vậy S={5/2}

x x 3 + : 0,5=12,8

x x (3 + 2)=12,8

x x 5=12,8

x     = 12,8 :5

x      = 2,56

\(\Leftrightarrow\left(x-2\right)\left(x^2+2x+4\right)-\left(x-2\right)\left(x-12\right)=0\\ \Leftrightarrow\left(x-2\right)\left(x^2+x+16\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\\left(x+\dfrac{1}{2}\right)^2+\dfrac{63}{4}=0\left(vô.lí\right)\end{matrix}\right.\\ \Leftrightarrow x=2\)

mình ko biết

\(6,56+x=5,4\times22\)

\(6,56+x=118,8\)

\(x=118,8-6,56=112,24\)

x=112,24

vậy x=(5,4 x 22)-6,56=112,24

\(x\times3,5-x\times2=30\)
\(x\times\left(3,5-2\right)=30\)
\(x\times1,5=30\)
\(x=30:1,5\)
\(x=20\)

\(3,5\times x-2\times x=30\\ \Leftrightarrow x\left(3,5-2\right)-30\\ \Leftrightarrow1,5x=30\\ \Leftrightarrow x=30:1,5\\ \Leftrightarrow x=20\)

Vậy \(x=20\)

X x 3,5 - X x 2 = 30

X x (3.5 - 2)    = 30

X x 1.5            = 30

X                     = 30 : 1.5

X                     = 20

\(\left(-3\sqrt{x}+2\right)\left(x\sqrt{x}+4\sqrt{x}+1\right)\)

\(=-3\sqrt{x}\left(x\sqrt{x}+4\sqrt{x}+1\right)+2\left(x\sqrt{x}+4\sqrt{x}+1\right)\)

\(=-3x^2-12x-3\sqrt{x}+2x\sqrt{x}+8\sqrt{x}+2\)

\(=-3x^2-12x+5\sqrt{x}+2x\sqrt{x}+2\)