các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha

a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)

              -\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)

              -6 < \(x\) < -4

             vì \(x\) \(\in\) Z nên \(x\) = -5

- \(\dfrac{19}{6}+\dfrac{-15}{2}+\dfrac{11}{3}\) < \(x\) < - \(\dfrac{5}{4}\) + \(\dfrac{19}{12}\) - \(\dfrac{10}{3}\)

- \(\dfrac{32}{3}+\dfrac{11}{3}< x< \) \(\dfrac{1}{3}\) - \(\dfrac{10}{3}\)

-7 < \(x\) < - 3

Vì \(x\in\) Z nên \(x\in\) {-6;-5;-4}

a: 6/7=1-1/7

5/6=1-1/6

mà -1/7>-1/6

nên 6/7>5/6

b: 11/10>1>10/11

c: 18/36=3/6<7/6

6/7 bé hơn 5/6

11/10 lớn hơn 10/11

18/36 bé hơn 7/6

Ta có: \(\dfrac{6}{7}=\dfrac{6\times6}{7\times6}=\dfrac{36}{42};\dfrac{5}{6}=\dfrac{5\times7}{6\times7}=\dfrac{35}{42}\)

\(\Rightarrow\dfrac{36}{42}>\dfrac{35}{42}\)

\(\Rightarrow\dfrac{6}{7}>\dfrac{5}{6}\)

Ta có: \(\dfrac{11}{10}=\dfrac{11\times11}{10\times11}=\dfrac{121}{110};\dfrac{10}{11}=\dfrac{10\times10}{11\times10}=\dfrac{100}{110}\)

\(\Rightarrow\dfrac{121}{110}>\dfrac{100}{110}\)

\(\Rightarrow\dfrac{11}{10}>\dfrac{10}{11}\)

Ta có: \(\dfrac{18}{36}\) giữ nguyên ; \(\dfrac{7}{6}=\dfrac{7\times6}{6\times6}=\dfrac{42}{36}\)

\(\Rightarrow\dfrac{18}{36}< \dfrac{42}{36}\)

\(\Rightarrow\dfrac{18}{36}< \dfrac{7}{6}\)

1=32

2=-3

3=-16

4=-9

5=0

6=6

7=1

8=25

nhớ tick cho mình nha

a, 6/7, 6/15, 6/17, 6/21

1: =72/90+65/90=137/90

2: =24/56-77/56=-53/56

3: =-7/10+4/5=1/10

4: =15/100-4/100=11/100

5: =4/6-5/6=-1/6

6: =10/40-15/40-76/40=-81/40

7: =-9/10+7/18

=-81/90+35/90=-46/90=-23/45

8: =27/90-55/90=-28/90=-14/45

9: =36/60-50/60-35/60=-49/60

10: =-4/9+5/6-3/8

=-32/72+60/72-27/72

=1/72

\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)

\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)

\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)

\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)

\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)

\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)

\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)

\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)

\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)

\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)

\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)

\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)

`@mt`

18 - 10 : ( +2 ) - 7 

= 18 - 5 - 7

= 13 - 7

= 16

( 6 . 8 - 10 : 5 ) + 3 . ( -7 )

= ( 48 - 2 ) + -21

= 46 + ( - 21 )

= 25

( 6 . 8  - 10 : 5 ) + 3 . ( - 7 )

= ( 48 - 2 ) + ( - 21 )

= 46 + ( - 21 )

= 25