`30 000-15 273-4727`

`= 30 000-(15 273+4727)`

`=30 000-20000`

`=10 000`

`49 573-(25 000+9573)`

`=49 573-25 000-9573`

`=(49 573-9573)-25 000`

`=40000-25000`

`=15000`

giúp em đi ạ em cần gấp lắm rồi

a: =30000-20000=10000

b: =40000-25000=15000

Cho mik lm lại nha, muốn tính 39 x 24 thì thực hiện như thế này :

39 x 24

= 39  x (20 + 4)

= 39 x 20 + 39 x 4

= 780 + 156

= 936

Chúc bạn 1 ngày thật vui nha, bn hãy tận dụng để lm bài thật tốt nhé

Địch mẹ mi

TL

936 đáp án đó nha

HT

a) \(\dfrac{-15}{4}:\dfrac{21}{-10}=\dfrac{-15}{4}.\dfrac{-10}{21}=\dfrac{25}{14}\)

b) \(\dfrac{-7}{14}:\left(-0,14\right)=\dfrac{-7}{14}.\dfrac{-50}{7}=\dfrac{25}{7}\)

c) \(\left(\dfrac{-11}{15}\right):1\dfrac{1}{10}=\dfrac{-11}{15}.\dfrac{10}{11}=\dfrac{-2}{3}\)

d) \(2\dfrac{1}{7}:1\dfrac{1}{14}=\dfrac{15}{7}.\dfrac{14}{15}=2\)

\(a.-\dfrac{15}{4}:\left(\dfrac{21}{-10}\right)\)

\(=-\dfrac{15}{4}\cdot\left(-\dfrac{10}{21}\right)\)

\(=\dfrac{25}{14}\)

\(b.-\dfrac{7}{14}:\left(-0,14\right)\)

\(=-\dfrac{1}{2}:\left(-\dfrac{7}{50}\right)\)

\(=\dfrac{25}{7}\)

\(c.\left(-\dfrac{11}{15}\right):\left(1\dfrac{1}{10}\right)\)

\(=\left(-\dfrac{11}{15}\right):\dfrac{11}{10}\)

\(=-\dfrac{2}{3}\)

\(d.\left(2\dfrac{1}{7}\right):\left(1\dfrac{1}{14}\right)\)

\(=\dfrac{15}{7}:\dfrac{15}{14}\)

\(=2\)

a) \(\dfrac{-15}{4}:\dfrac{21}{-10}=\dfrac{-15}{4}.\dfrac{-10}{21}=\dfrac{25}{14}\)

b) \(\dfrac{-7}{14}:\left(-0,14\right)=\dfrac{-7}{14}:\dfrac{-7}{50}=\dfrac{-7}{14}.\dfrac{50}{-7}=\dfrac{25}{7}\)

c) \(\dfrac{-11}{15}:1.\dfrac{1}{10}=\dfrac{-11}{15}.\dfrac{1}{10}=\dfrac{-11}{150}\)

d) \(\dfrac{21}{7}:1.\dfrac{1}{14}=3.\dfrac{1}{14}=\dfrac{3}{14}\)

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TL :

Đề bài hơi lỗi nha

HT

a, -(-5)-(+7)+(+3)+(-8)

= 5 - 7 + 3 + (-8)

= (-2) + 3 + (-8)

= 1 + (-8)

= -7

b, -(-15)-|-10|+|-9|-|5I

= 15 - 10 + 9 - 5

= 5 + 9 - 5

= 14 - 5

= 9

c, 14-(-13)-(17)+(-12)

= 14 + 13 - 17 + (-12)

= 27 - 17 + (-12)

= 10 + (-12)

= 2

d, -|-14| + |-10| - (-12) + (-8)

= -14 + 10 + 12 + (-8)

= (-4) + 12 + (-8)

= 7 + (-8)

= -1

e, -(-11) + (-15) + (13) - 21

toan lop 6 ma chi

x : 0,1 = 12

x x 10 = 12

x = 12 : 10

x = 1,2

--------------------------------------------

4 : 0,25 + 320 x 0,5 + 3: 0,125

= 4 x 4 + 320 : 2 + 3 x 8

= 16 + 160 + 24

= 160 + (16 + 24)

= 160 + 40

= 200

=> 72 - 20x - 36x - 84 = 30x - 240 - 6x + 84

=> (72 - 84 )  - (20x + 36x ) = (30x - 6x ) - 240 + 84

=> -12 - 56x = 24x - 156

=> -12 + 156 = 24x + 56x 

=> 144 = 80x

=> x = 144  : 80

=> x = 9/5

=> 72 - 20x - 36x - 84 = 30x - 240 - 6x + 84

=> (72 - 84 )  - (20x + 36x ) = (30x - 6x ) - 240 + 84

=> -12 - 56x = 24x - 156

=> -12 + 156 = 24x + 56x 

=> 144 = 80x

=> x = 144  : 80

=> x = 9/5

Bài 15:

a) Ta có: \(A=\cos^252^0\cdot\sin45^0+\sin^252^0\cdot\cos45^0\)

\(=\dfrac{\sqrt{2}}{2}\left(\sin^252^0+\cos^252^0\right)\)

\(=\dfrac{\sqrt{2}}{2}\)

b) Ta có: \(B=\tan60^0\cdot\cos^247^0+\sin^247^0\cdot\cot30^0\)

\(=\sqrt{3}\cdot\left(\sin^247^0+\cos^247^0\right)\)

\(=\sqrt{3}\)

Bài 17:

c) Ta có: \(C=\tan1^0\cdot\tan2^0\cdot\tan3^0\cdot\tan4^0\cdot...\cdot\tan89^0\)

\(=\left(\tan1^0\cdot\tan89^0\right)\cdot\left(\tan2^0\cdot\tan88^0\right)\cdot...\cdot\tan45^0\)

\(=1\cdot1\cdot...\cdot1=1\)