23 x ( 42 - X) = 23
a)(x+13):5=12
b)23.(42-x)=23
a) \(\left(x+13\right):5=12\)
\(\Rightarrow x+13=12\cdot5\)
\(\Rightarrow x+13=60\)
\(\Rightarrow x=60-13\)
\(\Rightarrow x=47\)
b) \(23\cdot\left(42-x\right)=23\)
\(\Rightarrow42-x=23:23\)
\(\Rightarrow42-x=1\)
\(\Rightarrow x=42-1\)
\(\Rightarrow x=41\)
X-(57-(42+(-23-x)=13-47+25-23-x
x-(57-(42+(-23-x)=13-47+25-23-x
x-57-42-23-x=13-47+25-23-x
x-122-x=-32-x
x-x-122=-32-x
-32-x=-122
x=-32-(-122)
x=90
Vậy x=90
\(x-(57-(42+(-23-x)=13-47+25-13-x\)
\(\Rightarrow x-57-42+\left(-23\right)-x=13-47+25-23-x\)
\(\Rightarrow x-x+x=13-47+25-23+23+42+57\)
\(\Rightarrow x=90\)
23 . (42 - x) = 23
42 - x = 23 : 23
42 - x = 1
x = 42 - 1
x = 41
Tìm x biết 23*(42-x)=23
23*(42-x)=23
42-x =23:23
42-x =1
x =42-1
x =41
\(23.\left(42-x\right)=23\)
<=> \(42-x=1\)
<=> \(x=41\)
Vậy...
hk tốt
^^
Tìm số tự nhiên x biết: 23.(42 - x) = 23
23.(42 – x) = 23
42 – x = 23: 23
42 – x = 1
x = 42 – 1
x = 41
Vậy x = 41
Tìm số tự nhiên x, biết:
b) 23 . (42 – x) = 23
b) 23 . (42 – x) = 23
Vì 23 . 1 = 23
Nên 42 – x = 1
x = 42 -1
x = 41
Vậy x = 41
23. ( 42- x ) = 23
23.(42-X)=23
=>42-X=23:23
=>42-X=1
=>X=42-1
=>X=41
23.[42-x]=23
23.(42-x)=23
42-x=23:23
42-x=1
x=42-1
x=41
23. [42 - x] = 23 42 - x = 23:23 42 - x = 1 x = 42 - 1 x = 41 Vậy x = 41
23.(42-x)=23
23.(42 - x) = 23
42 - x = 23 : 23
42 - x = 1
x = 42 - 1
x = 41
Vậy x = 41