\(2^x+2^x\cdot2^3=144\)

\(2^x\cdot\left(8+1\right)=144\)

\(2^x\cdot9=144\)

\(2^x=144\div9\)

\(2^x=16\)

Vì 2 * 2 * 2 * 2 = 16 = 2⁴ nên x = 4

2^x*(1+8)=2^x*9=144
            => 2^x=144:9

                  2^x=16

=> 2^x=2^4 => x=4

A, (2x+1)³=343

=> (2x+1)³=7³

=> 2x + 1 = 7

=> 2x = 6

=> x = 3

B, 2^x+2^x+3=144

=> 2^x+2^x . 2³ =144

=> 2^x ( 1 + 2³ ) =144

=> 2^x ( 1 + 8 ) =144

=> 2^x . 9 =144

=> 2 ^x = 16

=> 2 ^x = 2 ⁴

=> x = 4

C, 3^x+3^x+2=2430

=> 3^x+3^x . 3² =2430

=> 3^x . ( 1 + 3² ) =2430

=> 3^x . ( 1 + 9 ) =2430

=> 3^x . 10 =2430

=> 3^x = 243

=> 3^x = 3 ⁵

=> x = 5 

2^x+2^x+3=144

2^x+2^x.2³=144

2^x.(2³+1)=144

2^x.9=144

2^x=144:9

2^x=16

2^x=2⁴

=>x=4

Vậy x=4

Bài làm

2^x + 2^{x + 3} = 144

2^x + 2^x . 2³ = 144

2^x ( 1 + 2³ ) = 144

2^x . 9           = 144

2^x                = 16

2^x                = 2⁴ 

=> x = 4

Vậy x = 4

# Học tốt #

\(2^x+2^{x+3}=144\)

\(\Rightarrow2^x\times1+2^x\times2^3=144\)

\(\Rightarrow2^x\times\left(1+8\right)=144\)

\(\Rightarrow2^x\times9=144\)

\(\Rightarrow2^x=16\)

\(\Rightarrow2^x=2^4\)

\(\Rightarrow x=4\)

~Std well~

#K_Miin

\(4^{x+3}\times4^{x-1}=256\)

\(\Rightarrow4^{x+3+x-1}=256\)

\(\Rightarrow4^{2x+2}=256=4^4\)

\(\Rightarrow2x+2=4\)

\(\Rightarrow x=\left(4-2\right):2=1\)

\(2^{x+3}+2^x=144\)

\(\Rightarrow2^x.\left(2^3+1\right)=144\)

\(\Rightarrow2^x.9=144\)

\(\Rightarrow2^x=144:9=16=2^4\)

\(\Rightarrow x=4\)

\(4^{x+3+x-1}=256\)

\(4^{2x+2}=4^4\)

\(2x+2=4=>2x=2=>x=1\)

(3x + 3)² = 144

=> (3x + 3)² = ( \(\pm\)12)²

=> \(\orbr{\begin{cases}3x+3=12\\3x+3=-12\end{cases}}\Rightarrow\orbr{\begin{cases}3x=9\\3x=-15\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=-5\end{cases}}\)

  Bài làm :   

     (3.x + 3)² = 144

=> (3.x + 3) = \(\sqrt{144}\)

=> 3.x + 3 = 12

=> 3.x       = 12 - 3

=> 3.x       = 9

=> x          = 9 : 3

=> x          = 3

\(\left(3x+3\right)^2=144\)

\(\Leftrightarrow\left(3x+3\right)^2=\left(\pm12\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}3x+3=12\\3x+3=-12\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}3x=9\\3x=-15\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=3\\x=-5\end{cases}}\)

\(a,2^x+2^{x+3}=144\\ 2^x.\left(1+2^3\right)=144\\ 2^x.9=144\\ 2^x=144:9\\ 2^x=16=2^4\\ vậy:x=4\)

\(b,\left(x-5\right)^{2022}=\left(x-5\right)^{2021}\\ Vì:\left[{}\begin{matrix}0^{2022}=0^{2021}\\1^{2022}=1^{2021}\end{matrix}\right.\\ Vậy:\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)

\(c,\\ \left(2x+1\right)^3=9.81\\ \left(2x+1\right)^3=3^2.3^4\\ \left(2x+1\right)^3=3^6\\ \left(2x+1\right)^3=\left(3^2\right)^3=9^3\\ Vậy:2x+1=9\\ 2x=9-1\\ 2x=8\\ x=\dfrac{8}{2}\\ x=4\)

,làm ơn giúp mik với ah

\(\left(1+\dfrac{2}{3}\right).\left(1+\dfrac{2}{4}\right).\left(1+\dfrac{2}{5}\right)....\left(1+\dfrac{2}{2020}\right).\left(1+\dfrac{2}{2021}\right)\)

= \(\dfrac{5}{3}.\dfrac{6}{4}.\dfrac{7}{5}.\dfrac{8}{6}.\dfrac{9}{7}....\dfrac{2022}{2020}.\dfrac{2023}{2021}\)

= \(\dfrac{1}{3}.\dfrac{1}{4}.2022.2023\)

= \(\dfrac{337.2023}{2}\)

= \(\dfrac{\text{681751}}{2}\)

`Answer:`

`(2/3+x)-(-1/2)=3/5`

`<=>2/3+x=3/5-1/2`

`<=>2/3+x=\frac{1}{10}`

`<=>x=\frac{1}{10}-2/3`

`<=>x=\frac{-17}{30}`

`-3/4-(x-7/2)=1/2+(-2/3)`

`<=>-3/4-(x-7/2)=-1/6`

`<=>x-7/2=-3/4-(-1/6)`

`<=>x-7/2=-3/4+1/6`

`<=>x-7/2=-\frac{7}{12}`

`<=>x=\frac{-7}{12}+7/2`

`<=>x=\frac{35}{12}`

\(4^2.x+2^4.x+3=144\\ \Rightarrow16x+16x+3=144\\ \Rightarrow32x=144-3\\ \Rightarrow32x=141\\ \Rightarrow x=\dfrac{141}{32}\)

2x + 2x + 3 = 144

         =>  2x . 1 + 2x . 23 = 144 

          => 2x . (1 + 23) = 144

         =>  2x . 9 = 144

         => 2x = 144 : 9 = 16

        => x = 4

2x + 2x + 3 = 144

         =>  2x . 1 + 2x . 23 = 144 

          => 2x . (1 + 23) = 144

         =>  2x . 9 = 144

         => 2x = 144 : 9 = 16

        => x = 4