A=1/2+1/6+1/12+1/20+...1/n Biet A=38/40 Tim n
a=1/2+1/6+1/12+1/20+1/30+...1/n
tim n biet a=39/40
a=1/2+1/6+1/12+1/20+1/30+1/n
a=1/1-1/2+1/2-...+1/a+1
a=1+1/a-1=39
=>a=40
vay n=39X40=1560
ai h minh h lai
A= 1/2+1/6+1/12+20+1/30+....+1/n
biet A=39/40 tim n
A = 1/1.2 + 1/2.3 +.......+1/a(a + 1)
A = 1/1 - 1/2 + 1/2 - ..... - 1/a+1
A= 1 - 1/a+ 1 = 39/40
1/a + 1 = 1/4 0 => a + 1= 40 => a= 39
Vậy n= 39 x 40 = 1560
cho a = 1/2+1/6+1/12+1/20+1/30+..........+1/82 biet a la 39/40 tim a
cho a =1/2+1/6+1/12+1/20+1/30+.....+1/n biet a +39/40
bài này có phải lớp 5 ko vậy tui thấy ? quá
IIIIIIIIIII LLLLLLLLLL oooooooooooo vvvvvvvvvvvvvvvvvvv EEEEEEEEEEEEEEE
YYYYYYYYYYYYYYYYY OOOOOOOOOOOOOOO UUUUUUUUUUUUUUU
I love you
k nha
hjhjhj
hahaha
hjhjhj
hahaha
CHO A=1/2+1/6+1/12+1/20+1/30+......+1/n
biet A =49/50 TIM n
GIUP MINH NHA CAC BN
ta có dạng tổng quát sau : 1/ 2 = 1/(2*1)
1/6 = 1/(2*3)
1/12 = 1/(3*4)
....................
1/n = 1/(x-1)x
cộng vế theo vế ta có :
\(A=\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+.....+\frac{1}{x\left(x-1\right)}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.......+\frac{1}{\left(x-1\right)}-\frac{1}{x}\)
\(=1-\frac{1}{x}\)
Mà A = 49/50
Nên \(1-\frac{1}{x}=\frac{49}{50}\)
\(\frac{1}{x}=1-\frac{49}{50}=\frac{1}{50}\)
\(x=50\)
\(n=x\left(x-1\right)=50\times49=2450\)
Vậy n = 2450
A=1/2+1/6+1/12+1/20+1/30+...+1/n biet A=49/50
a = 1/2 + 1/6 +1/12 + 1/20 + 1/30 + ....................................................... + 1/n biết a = 39/40 .tim n ?
A = 1/2 + 1/6 + 1/12 + 1/20 + 1/30 + 1/n
A = 49/50
Tim n
Ta phân tích:
\(\frac{1}{2}\)= \(\frac{1}{1x2}\)= 1 -\(\frac{1}{2}\)
\(\frac{1}{6}\)= \(\frac{1}{2x3}\)= \(\frac{1}{2}\)- \(\frac{1}{3}\)
.....
\(\frac{1}{n}\)= \(\frac{1}{ax\left(a+1\right)}\)= \(\frac{1}{a}\)- \(\frac{1}{a+1}\)
Ta có:A = \(\frac{1}{2}\)+ \(\frac{1}{6}\)+ ... + \(\frac{1}{n}\)= 1 -\(\frac{1}{2}\)+ \(\frac{1}{2}\)- \(\frac{1}{3}\)+ ... + \(\frac{1}{a}\)- \(\frac{1}{a+1}\)= \(\frac{49}{50}\)
Hay A = 1 - \(\frac{1}{a+1}\)= \(\frac{49}{50}\)
\(\Rightarrow\) \(\frac{1}{a+1}\)= 1 -\(\frac{49}{50}\)
\(\Rightarrow\)\(\frac{1}{a+1}\)= \(\frac{1}{50}\)
Vậy (a + 1) = 50 mà n = a x (a+1) => n = (50-1) x 50 = 2450
Ta lấy \(\frac{49}{50}\)trừ đi 5 phân số kia
Sau đó sẽ là phân số .........
Vậy là tìm được n
A=1/2+1/6+1/12+1/20+1/30+...+1/n Biết A=39/40 Tìm n
A=\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+.........+\frac{1}{n}=\frac{39}{40}\)
A=\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+..........+\frac{1}{ax\left(a+1\right)}=\frac{39}{40}\)
A=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.......+\frac{1}{a}-\frac{1}{a+1}=\frac{39}{40}\)
A=\(1-\frac{1}{a+1}=\frac{39}{40}\)
\(\frac{1}{a+1}=1-\frac{39}{40}\)
\(\frac{1}{a+1}=\frac{1}{40}\)
a+1=40
a=40-1
a=39
n=39x40
n=1560