tìm x biết:x+x:3/2=217
Tìm xϵZ biết:
x-{[-x+(x+3)]} - [(x+3)-(x-2)]=0
\(\Rightarrow x-\left(-x+x+3\right)-\left(x+3-x+2\right)=0\\ \Rightarrow x-3-5=0\\ \Rightarrow x=8\)
Sai rồi bạn ơi, bằng -2 mới đúng,bn thử lại coi
Tìm x, biết:x-(5/6-x)=x-2/3
`x-(5/6 -x) =x-2/3`
`x-5/6 +x -x+2/3 =0`
`x = 5/6-2/3 = 5/6 -4/6 = 1/6`
bạn có thể giải chi tiết hơn dc ko TV Cuber
tìm x biết:x-1/x+2=x-2/x+3
x³ - x² - x = 1/3
<=> x³ = x² + x + 1/3
<=> 3x³ = 3(x² + x + 1/3)
<=> 3x³ = 3x² + 3x + 1
<=> 3x³ + x³ = x³ + 3x² + 3x + 1
<=> 4x³ = (x + 1)³
<=> ³√(4x³) = ³√(x + 1)³
<=> ³√4.x = x + 1
<=> ³√4.x - x = 1
<=> x(³√4 - 1) = 1
<=> x = 1/(³√4 - 1)
Ta có \(\frac{x-1}{x+2}=\frac{x-2}{x+3}\)
\(\Rightarrow\left(x-1\right)\left(x+3\right)=\left(x+2\right)\left(x-2\right)\)
\(\Rightarrow x^2+2x-3=x^2-4\)
\(\Rightarrow x^2-x^2+2x=-4+3\)
\(\Rightarrow2x=-1\)
\(\Rightarrow x=-\frac{1}{2}\)
Vậy \(x=-\frac{1}{2}\)
Tìm X, biết:
X + (X + 1) + (X + 2) + (X + 3) + ...+ (X + 19) = 950
=>20x+190=950
=>20x=760
hay x=38
`20x+190=950`
`20x=760`
`x= 760: 20`
`x= 38`
20 x X = 950 - (1 + 2 + 3 + 4 + 5 + ... + 19)
20 x X = 950 - 190
20 x X = 760
X = 760 : 20
X = 38
tìm x;y biết:x^3+x^2+x+1=y^3
\(x^2\left(x+1\right)+\left(x+1\right)=y^3\)
\(\left(x+1\right)\left(x^2+1\right)=y^3\)
\(\left(x+1\right)\left(x^2+1\right)-y^3=0\)
\(\orbr{\begin{cases}x+1=0\\x^2+1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x^2=-1\end{cases}\Rightarrow\orbr{\begin{cases}x=-1\\kothoaman\end{cases}}}\)
\(\Rightarrow\hept{\begin{cases}x=-1\\y^3=0\end{cases}}\Rightarrow\hept{\begin{cases}x=-1\\y=0\end{cases}}\)
Vậy x = -1, y =0
tìm x biết:x^3+x^2=36
\(x^3+x^2=36\)
\(\left(x^3\right)^2\)=36
\(x^6\)=\(6^6\)
Vậy x=6
tìm x biết:x(x^2-25)-(x+2)(x^2-2x+4)=3
tìm x biết:
x: 2/3 = 5/2
\(x\div\dfrac{2}{3}=\dfrac{5}{2}\)
\(x=\dfrac{2}{3}\times\dfrac{5}{2}\)
\(x=\dfrac{5}{3}\)
Tìm X biết:
X-3/5=1/2:2/3
\(x=\left(\dfrac{1}{2}:\dfrac{2}{3}\right)+\dfrac{3}{5}=\dfrac{1}{3}+\dfrac{3}{5}=\dfrac{5}{15}+\dfrac{9}{15}=\dfrac{14}{15}\)