Sửa đề: x^4+64

x^4+64

=x^4+16x^2+64-16x^2

=(x^2+8)^2-(4x)^2

=(x^2-4x+8)(x^2+4x+8)

\(x^3-64=x^3-4^3\)

\(\Rightarrow\left(x-4\right)\left(x^2+4x+4^2\right)\)

x³-64=x³-4³=(x-4)(x²+4x+16)

Ta có:\(x^3-64\)

\(=x^3-4^3\)

Áp dụng hằng đẳng thức:\(a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)\)

\(\Rightarrow x^3-4^3=\left(x-4\right)\left(x^2+4x+4^2\right)\)

\(=x^4y^4+4x^2y^2+4-4x^2y^2\)

\(=\left(x^2y^2-2\right)^2-\left(2xy^2\right)\)

bn lm tiếp đi

dfdfdfdfd

( x-2 ) ^3 + 4^3

= hằng đẳng thức thứ 6 nha pạn

lam luon di bam dung cho

\(\left(x-2\right)^3+64\)

\(=\left(x-2\right)^3+4^3\)

\(=\left(x-2+4\right)\left[\left(x-2\right)^2-4\left(x-2\right)+4^2\right]\)

\(=\left(x+2\right)\left(x^2-4x+4-4x+8+16\right)\)

\(=\left(x+2\right)\left(x^2-8x+28\right)\)

Tham khảo nhé~

\(=x\left(x-4\right)+5\left(x-4\right)=\left(x+5\right)\left(x-4\right)\)

x(x-4)+5(x-4)

(x+5)(x-4)

x⁸+64

=(x⁴)²+16x⁴+8²-16x⁴

=(x⁴+8)²-(4x²)²

=(x⁴+8-4x²)(x⁴+8+4x²)