\(\frac{11}{25}\)x(-24,8) -\(\frac{11}{25}\)x 75,2 = \(\frac{11}{25}\)x(-24,8-75.2) = \(\frac{11}{25}\)x  (-100) = -44

\(=\dfrac{13}{25}\cdot\dfrac{11}{6}\cdot\dfrac{25}{12}\cdot\dfrac{11}{6}=\dfrac{121}{36}\cdot\dfrac{13}{12}=\dfrac{1573}{432}\)

\(\frac{5}{11}+\frac{1}{14}+\frac{2}{5}+\frac{6}{11}+\frac{3}{4}+\frac{6}{25}+\frac{9}{25}\)

\(=\frac{5}{11}+\frac{6}{11}+\frac{1}{14}+\frac{3}{4}+\frac{2}{5}+\frac{6}{25}+\frac{9}{25}\)

\(=1+\frac{23}{28}+1\)

\(=\frac{79}{28}\)

Bạn có thể xem ở đây : Tại đây

=1/14 +1/4+(2/5+6/25+9/25)+(6/11+5/11)

=4/64+16/64+1+1

=20/64+1+1

=5/16+1+1

=2 và 5/16

\(\frac{5}{11}+\frac{1}{14}+\frac{2}{5}+\frac{6}{11}+\frac{3}{4}+\frac{6}{25}+\frac{9}{25}\)

\(=\left(\frac{5}{11}+\frac{6}{11}\right)+\left(\frac{1}{14}+\frac{3}{4}\right)+\left(\frac{6}{25}+\frac{9}{25}\right)+\frac{2}{5}\)

\(=1+\frac{23}{28}+\frac{3}{5}+\frac{2}{5}\)

\(=1+\frac{23}{28}+1\)

\(=2+\frac{23}{28}\)

\(=\frac{79}{28}\)

Ai k mik mik k lại

\(\frac{79}{28}\)nha bạn

Cho mình sửa lại đề tí nhé bạn , nếu có gì sai liên hệ với mình !

\(\frac{5}{11}+\frac{1}{4}+\frac{2}{5}+\frac{6}{11}+\frac{3}{4}+\frac{6}{25}+\frac{9}{25}\)

\(=\frac{5}{11}+\frac{6}{11}+\frac{1}{4}+\frac{3}{4}+\frac{2}{5}+\frac{6}{25}+\frac{9}{25}\)

\(=1+1+1\)

\(=3\)

\(\frac{79}{28}\)nha bạn

a) 5

b) 11/6

\(\frac{167}{99}\)

Ta có : 

11 . ( 7 - 25 ) + 7. ( 25 - 11 ) 

= 11 . 7 - 11 . 25 + 7 . 25 - 7 . 11 

= ( 11 . 7 - 7 . 11 )  + ( -11 . 25 + 7 . 25 ) 

=        0  +  [  ( -11 ) + 7 ] . 25 

=        0  +    4 . 25

=        0  + 100 

=       100  

Tham khảo nha !!! 

Sửa lại nha 

-11 + 7 = -4 

-4 .25 = -100 

Đáp án : -100 

=11.7-11.25+7.25-11.7=(11.7-11.7)-(11.25-7.25)=0-25.(11-7)=0-25.4=0-100=-100

\(9\frac{7}{25}+\frac{3}{25}\cdot\frac{7}{11}-\frac{7}{25}\cdot\frac{14}{11}\)

\(=9\frac{7}{25}+\frac{3}{25}\cdot\frac{7}{11}-\frac{14}{25}\cdot\frac{7}{11}\)

\(=9\frac{7}{25}+\frac{7}{11}\cdot\left(\frac{3}{25}-\frac{14}{25}\right)\)

\(=9\frac{7}{25}+\frac{7}{11}\cdot\left(-\frac{11}{25}\right)\)

\(=9\frac{7}{25}+\left(-\frac{7}{25}\right)\)

\(=9\)

Chắc sai =]]

thank

\(\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}:\frac{11}{5}+\frac{58}{11}\)

\(=\frac{22}{25}\times\frac{5}{11}-\frac{33}{25}\times\frac{5}{11}+\frac{58}{11}\)

\(=\frac{5}{11}\times\left(\frac{22}{25}+\frac{33}{25}\right)+\frac{58}{11}\)

\(=\frac{5}{11}\times\frac{11}{5}+\frac{58}{11}\)

\(=1+\frac{58}{11}\)

\(=\frac{11}{11}+\frac{58}{11}\)

\(=\frac{69}{11}\)

\(8\frac{3}{11}-\left(3\frac{5}{7}-7\frac{8}{11}\right)\)

\(=\frac{91}{11}-\left(\frac{26}{7}-\frac{85}{11}\right)\)

\(=\frac{91}{11}-\frac{26}{7}+\frac{85}{11}\)

\(=\frac{91}{11}+\frac{85}{11}-\frac{26}{7}\)

\(=16-\frac{26}{7}\)

\(=\frac{86}{7}\)

\(\frac{5}{6}x+325\%=\frac{3}{2}x-30,75\)

\(=>\frac{5}{6}x+3,25=\frac{3}{2}x-30,75\)

\(=>\frac{5}{6}x-\frac{3}{2}x=-30,75-3,25\)

\(=>\frac{-2}{3}x=-34\)

\(=>x=-34:\left(-\frac{2}{3}\right)\)

\(=>x=-34.\left(\frac{3}{-2}\right)\)

\(=>x=51\)