\(=\left(x-y+5-1\right)^2=\left(x-y+4\right)^2\)

(x-y+5)^2-2.1,(x-y+5)+1

(x-y+5-1)^2

(x-y+4)^2

(x-y+5)^2-2(x-y+5)+1

=(x−y+5−1)2

=(x−y+4)2

Đề yêu cầu làm gì bạn

\(\frac{\left(a-b\right)^2}{4}\)- 1 = (\(\frac{a-b}{2}\)- 1)(\(\frac{a-b}{2}\)+ 1)

\(x^2\left(x-3\right)^2-\left(x-3\right)^2-x^2+1=\left(x-3\right)^2\left(x^2-1\right)-\left(x^2-1\right)=\left(x^2-1\right)\left(x-3\right)^2=\left(x-1\right)\left(x+1\right)\left(x-3\right)^2\)

\(3x^2+4x+x^2-4\\ =4x^2+4x-4\\ =4\left(x^2+x-1\right)\)

1/(x+2)² -(3x-1)²=(x+2+3x-1)(x+2-3x+1)=4x(-2x+3)=-8x²+12x

2/(x⁴+x²)(-2x³-2x)=x²(x²+1)-2x(x²+1)=(x²+1)(x²-2x)

Biểu thức này không phân tích được nhé.

\(64x^4+1\)

\(=64x^4+16x^2+1-16x^2\)

\(=\left(8x^2-4x+1\right)\left(8x^2+4x+1\right)\)

\(a,=\left(m-y\right)\left(m+y\right)+a\left(m+y\right)=\left(m+y\right)\left(m-y+a\right)\\ b,=3x\left(y-1\right)+\left(y-1\right)\left(y+1\right)=\left(y-1\right)\left(3x+y+1\right)\)

a: \(=\left(m-y\right)\left(m+y\right)+a\left(m+y\right)\)

\(=\left(m+y\right)\left(m-y+a\right)\)